Quantitative Chemical Analysis
9th Edition
ISBN: 9781464135385
Author: Daniel C. Harris
Publisher: W. H. Freeman
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Question
Chapter 19, Problem 19.21P
Interpretation Introduction
Interpretation:
The advantage of time resolved emission measurement with
To explain the advantage of time resolved emission measurement with
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Identify and provide an explanation of the operational principles behind a Atomic Absorption Spectrometer (AAS). List the steps involved.
Instructions: Complete the questions in the space provided. Show all your work
1. You are trying to determine the rate law expression for a reaction that you are completing at 25°C. You measure
the initial reaction rate and the starting concentrations of the reactions for 4 trials.
BrO³¯ (aq) + 5Br¯ (aq) + 6H* (aq) → 3Br₂ (l) + 3H2O (l)
Initial rate
Trial
[BrO3]
[H*]
[Br]
(mol/L)
(mol/L) | (mol/L)
(mol/L.s)
1
0.10
0.10
0.10
8.0
2
0.20
0.10
0.10
16
3
0.10
0.20
0.10
16
4
0.10
0.10
0.20
32
a.
Based on the above data what is the rate law expression?
b. Solve for the value of k (make sure to include proper units)
2. The proposed reaction mechanism is as follows:
i.
ii.
BrО¸¯ (aq) + H+ (aq) → HBrO3 (aq)
HBrO³ (aq) + H* (aq) → H₂BrO3* (aq)
iii.
H₂BrO³* (aq) + Br¯ (aq) → Br₂O₂ (aq) + H2O (l)
[Fast]
[Medium]
[Slow]
iv.
Br₂O₂ (aq) + 4H*(aq) + 4Br(aq) → 3Br₂ (l) + H2O (l)
[Fast]
Evaluate the validity of this proposed reaction. Justify your answer.
е.
Д
CH3
D*, D20
Chapter 19 Solutions
Quantitative Chemical Analysis
Ch. 19.1 - Prob. 1TYCh. 19 - Prob. 19.AECh. 19 - Prob. 19.BECh. 19 - Prob. 19.CECh. 19 - Prob. 19.DECh. 19 - Prob. 19.1PCh. 19 - Prob. 19.2PCh. 19 - Prob. 19.3PCh. 19 - Prob. 19.4PCh. 19 - Prob. 19.5P
Ch. 19 - Prob. 19.6PCh. 19 - Prob. 19.7PCh. 19 - Prob. 19.9PCh. 19 - Prob. 19.10PCh. 19 - Prob. 19.11PCh. 19 - Prob. 19.12PCh. 19 - Prob. 19.13PCh. 19 - Prob. 19.14PCh. 19 - Prob. 19.15PCh. 19 - Prob. 19.16PCh. 19 - Prob. 19.17PCh. 19 - Prob. 19.18PCh. 19 - Prob. 19.19PCh. 19 - Prob. 19.20PCh. 19 - Prob. 19.21PCh. 19 - Prob. 19.22PCh. 19 - Prob. 19.23PCh. 19 - Prob. 19.24PCh. 19 - Prob. 19.25P
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