Quantitative Chemical Analysis
9th Edition
ISBN: 9781464135385
Author: Daniel C. Harris
Publisher: W. H. Freeman
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Chapter 19, Problem 19.23P
Interpretation Introduction
Interpretation:
The pictorial representation and explanations has to be done showing the state of beads in steps (1-3).
Concept Introduction:
Immunoassays:
Immunoassays are applications of light absorption and emission. Immunoassays are useful in detecting the analyte with the help of antibodies. Antibodies are proteins that are formed by the immune system of an animal to response to a foreign substance called as antigen. A specific antigen is recognized by antibody. The formation constant for complex of antibody-antigen is large but the binding of the antibodies to other molecules is weak.
To give pictorial representation and explanations showing the state of beads in steps (1-3)
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The reaction for obtaining NO2 from NO and O2 has the rate equation: v = k[NO]2[O2]. Indicate which of the following options is correct.(A). This rate equation is inconsistent with the reaction consisting of a single trimolecular step.(B). Since the overall order is 3, the reaction must necessarily have some trimolecular step in its mechanism.(C). A two-step mechanism: 1) NO + NO ⇄ N2O2 (fast); 2) N2O2 + O2 → NO2 + NO2 (slow).(D). The mechanism must necessarily consist of three unimolecular elementary steps with very similar rate constants.
a. What is the eluent used in the column chromatography here (a “silica plug filtration” is essentially a very short column)?
b. The spectroscopy of compound 5b is described in the second half of this excerpt, including 1H-NMR and 13C-NMR (which you will learn about in CHEM 2412L), MS (which you will learn about later in CHEM 2411L) and IR. One of the IR signals is at 3530 cm-1. What functional group does this indicate might be present in compound 5b?
Steps and explanations. Also provide, if possible, ways to adress this kind of problems in general.
Chapter 19 Solutions
Quantitative Chemical Analysis
Ch. 19.1 - Prob. 1TYCh. 19 - Prob. 19.AECh. 19 - Prob. 19.BECh. 19 - Prob. 19.CECh. 19 - Prob. 19.DECh. 19 - Prob. 19.1PCh. 19 - Prob. 19.2PCh. 19 - Prob. 19.3PCh. 19 - Prob. 19.4PCh. 19 - Prob. 19.5P
Ch. 19 - Prob. 19.6PCh. 19 - Prob. 19.7PCh. 19 - Prob. 19.9PCh. 19 - Prob. 19.10PCh. 19 - Prob. 19.11PCh. 19 - Prob. 19.12PCh. 19 - Prob. 19.13PCh. 19 - Prob. 19.14PCh. 19 - Prob. 19.15PCh. 19 - Prob. 19.16PCh. 19 - Prob. 19.17PCh. 19 - Prob. 19.18PCh. 19 - Prob. 19.19PCh. 19 - Prob. 19.20PCh. 19 - Prob. 19.21PCh. 19 - Prob. 19.22PCh. 19 - Prob. 19.23PCh. 19 - Prob. 19.24PCh. 19 - Prob. 19.25P
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