(a) Interpretation: The IUPAC name for the given compound is to be stated. Concept introduction: The chemical structures are described by IUPAC name or common names. IUPAC nameis different from common names because IUPAC nameis applied at international level and it comprises suffix, prefix, numbers and other priority rules.

Question

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Answer 1

Question

Chapter 19, Problem 19.1P

Interpretation Introduction

(a)

Interpretation:The IUPAC name for the given compound is to be stated.

Concept introduction:The chemical structures are described by IUPAC name or common names. IUPAC nameis different from common names because IUPAC nameis applied at international level and it comprises suffix, prefix, numbers and other priority rules.

Expert Solution

Answer to Problem 19.1P

The IUPAC name of the compound is 3,3−dimethylhexanoic acid.

Explanation of Solution

The numbering of carbon atoms in the given compound is shown below.

ORGANIC CHEMISTRY, Chapter 19, Problem 19.1P , additional homework tip 1

Figure 1

The given compound has a chain of six carbon atoms. The carboxylic acid is present as a functional group in the compound. Two methyl groups are present at a third carbon atom. Therefore, the name of the compound is 3,3−dimethylhexanoic acid.

Conclusion

The IUPAC name of the given compound is 3,3−dimethylhexanoic acid.

Interpretation Introduction

(b)

Interpretation:The IUPAC name for the given compound is to be stated.

Concept introduction:The chemical structures are described by IUPAC name or common names. IUPAC name is different from common names because IUPAC name is applied at international level and it comprises suffix, prefix, numbers and other priority rules.

Expert Solution

Answer to Problem 19.1P

The IUPAC name of the compound is 3−bromo−4−chloro−2−fluoropentanoic acid.

Explanation of Solution

The numbering of carbon atoms in the given compound is shown below.

ORGANIC CHEMISTRY, Chapter 19, Problem 19.1P , additional homework tip 2

Figure 2

The given compound has a chain of five carbon atoms. The carboxylic acid is present as a functional group in the compound. Fluorine, chlorine and bromine is present at second, third and fourth carbon atoms respectively. Therefore, the name of the compound is 3−bromo−4−chloro−2−fluoropentanoic acid.

Conclusion

The IUPAC name of the compound is 3−bromo−4−chloro−2−fluoropentanoic acid.

Interpretation Introduction

(c)

Interpretation:The IUPAC name for the given compound is to be stated.

Concept introduction:The chemical structures are described by IUPAC name or common names. IUPAC name is different from common names because IUPAC name is applied at international level and it comprises suffix, prefix, numbers and other priority rules.

Expert Solution

Answer to Problem 19.1P

The IUPAC name of the compound is 2, 4-diethylhexanoic acid.

Explanation of Solution

The numbering of carbon atoms in the given compound is shown below.

ORGANIC CHEMISTRY, Chapter 19, Problem 19.1P , additional homework tip 3

Figure 3

The given compound has a chain of six carbon atoms. The carboxylic acid is present as a functional group in the compound. Two ethyl groups are present at second and fourth carbon atoms. Therefore, the name of the compound is 2, 4-diethylhexanoic acid.

Conclusion

The IUPAC name of the compound is 2, 4-diethylhexanoic acid.

Interpretation Introduction

(d)

Interpretation:The IUPAC name for the given compound is to be stated.

Concept introduction:The chemical structures are described by IUPAC name or common names. IUPAC name is different from common names because IUPAC name is applied at international level and it comprises suffix, prefix, numbers and other priority rules.

Expert Solution

Answer to Problem 19.1P

The IUPAC name of the compound is 4−isopropyl−6,8−dimethylnonanoic acid.

Explanation of Solution

The numbering of carbon atoms in the given compound is shown below.

ORGANIC CHEMISTRY, Chapter 19, Problem 19.1P , additional homework tip 4

Figure 4

The given compound has a chain of nine carbon atoms. The carboxylic acid is present as a functional group in the compound. Two methyl groups are present at eighth and nine carbon atoms, while one isopropyl group is present at fourth carbon. Therefore, the name of the compound is 4−isopropyl−6,8−dimethylnonanoic acid.

Conclusion

The IUPAC name of the compound is 4−isopropyl−6,8−dimethylnonanoic acid.

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Answer 2

Question

Chapter 19, Problem 19.1P

Interpretation Introduction

(a)

Interpretation:The IUPAC name for the given compound is to be stated.

Concept introduction:The chemical structures are described by IUPAC name or common names. IUPAC nameis different from common names because IUPAC nameis applied at international level and it comprises suffix, prefix, numbers and other priority rules.

Expert Solution

Answer to Problem 19.1P

The IUPAC name of the compound is 3,3−dimethylhexanoic acid.

Explanation of Solution

The numbering of carbon atoms in the given compound is shown below.

ORGANIC CHEMISTRY, Chapter 19, Problem 19.1P , additional homework tip 1

Figure 1

The given compound has a chain of six carbon atoms. The carboxylic acid is present as a functional group in the compound. Two methyl groups are present at a third carbon atom. Therefore, the name of the compound is 3,3−dimethylhexanoic acid.

Conclusion

The IUPAC name of the given compound is 3,3−dimethylhexanoic acid.

Interpretation Introduction

(b)

Interpretation:The IUPAC name for the given compound is to be stated.

Concept introduction:The chemical structures are described by IUPAC name or common names. IUPAC name is different from common names because IUPAC name is applied at international level and it comprises suffix, prefix, numbers and other priority rules.

Expert Solution

Answer to Problem 19.1P

The IUPAC name of the compound is 3−bromo−4−chloro−2−fluoropentanoic acid.

Explanation of Solution

The numbering of carbon atoms in the given compound is shown below.

ORGANIC CHEMISTRY, Chapter 19, Problem 19.1P , additional homework tip 2

Figure 2

The given compound has a chain of five carbon atoms. The carboxylic acid is present as a functional group in the compound. Fluorine, chlorine and bromine is present at second, third and fourth carbon atoms respectively. Therefore, the name of the compound is 3−bromo−4−chloro−2−fluoropentanoic acid.

Conclusion

The IUPAC name of the compound is 3−bromo−4−chloro−2−fluoropentanoic acid.

Interpretation Introduction

(c)

Interpretation:The IUPAC name for the given compound is to be stated.

Concept introduction:The chemical structures are described by IUPAC name or common names. IUPAC name is different from common names because IUPAC name is applied at international level and it comprises suffix, prefix, numbers and other priority rules.

Expert Solution

Answer to Problem 19.1P

The IUPAC name of the compound is 2, 4-diethylhexanoic acid.

Explanation of Solution

The numbering of carbon atoms in the given compound is shown below.

ORGANIC CHEMISTRY, Chapter 19, Problem 19.1P , additional homework tip 3

Figure 3

The given compound has a chain of six carbon atoms. The carboxylic acid is present as a functional group in the compound. Two ethyl groups are present at second and fourth carbon atoms. Therefore, the name of the compound is 2, 4-diethylhexanoic acid.

Conclusion

The IUPAC name of the compound is 2, 4-diethylhexanoic acid.

Interpretation Introduction

(d)

Interpretation:The IUPAC name for the given compound is to be stated.

Concept introduction:The chemical structures are described by IUPAC name or common names. IUPAC name is different from common names because IUPAC name is applied at international level and it comprises suffix, prefix, numbers and other priority rules.

Expert Solution

Answer to Problem 19.1P

The IUPAC name of the compound is 4−isopropyl−6,8−dimethylnonanoic acid.

Explanation of Solution

The numbering of carbon atoms in the given compound is shown below.

ORGANIC CHEMISTRY, Chapter 19, Problem 19.1P , additional homework tip 4

Figure 4

The given compound has a chain of nine carbon atoms. The carboxylic acid is present as a functional group in the compound. Two methyl groups are present at eighth and nine carbon atoms, while one isopropyl group is present at fourth carbon. Therefore, the name of the compound is 4−isopropyl−6,8−dimethylnonanoic acid.

Conclusion

The IUPAC name of the compound is 4−isopropyl−6,8−dimethylnonanoic acid.

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Answer 3

Question

Chapter 19, Problem 19.1P

Interpretation Introduction

(a)

Interpretation:The IUPAC name for the given compound is to be stated.

Concept introduction:The chemical structures are described by IUPAC name or common names. IUPAC nameis different from common names because IUPAC nameis applied at international level and it comprises suffix, prefix, numbers and other priority rules.

Expert Solution

Answer to Problem 19.1P

The IUPAC name of the compound is 3,3−dimethylhexanoic acid.

Explanation of Solution

The numbering of carbon atoms in the given compound is shown below.

ORGANIC CHEMISTRY, Chapter 19, Problem 19.1P , additional homework tip 1

Figure 1

The given compound has a chain of six carbon atoms. The carboxylic acid is present as a functional group in the compound. Two methyl groups are present at a third carbon atom. Therefore, the name of the compound is 3,3−dimethylhexanoic acid.

Conclusion

The IUPAC name of the given compound is 3,3−dimethylhexanoic acid.

Interpretation Introduction

(b)

Interpretation:The IUPAC name for the given compound is to be stated.

Concept introduction:The chemical structures are described by IUPAC name or common names. IUPAC name is different from common names because IUPAC name is applied at international level and it comprises suffix, prefix, numbers and other priority rules.

Expert Solution

Answer to Problem 19.1P

The IUPAC name of the compound is 3−bromo−4−chloro−2−fluoropentanoic acid.

Explanation of Solution

The numbering of carbon atoms in the given compound is shown below.

ORGANIC CHEMISTRY, Chapter 19, Problem 19.1P , additional homework tip 2

Figure 2

The given compound has a chain of five carbon atoms. The carboxylic acid is present as a functional group in the compound. Fluorine, chlorine and bromine is present at second, third and fourth carbon atoms respectively. Therefore, the name of the compound is 3−bromo−4−chloro−2−fluoropentanoic acid.

Conclusion

The IUPAC name of the compound is 3−bromo−4−chloro−2−fluoropentanoic acid.

Interpretation Introduction

(c)

Interpretation:The IUPAC name for the given compound is to be stated.

Concept introduction:The chemical structures are described by IUPAC name or common names. IUPAC name is different from common names because IUPAC name is applied at international level and it comprises suffix, prefix, numbers and other priority rules.

Expert Solution

Answer to Problem 19.1P

The IUPAC name of the compound is 2, 4-diethylhexanoic acid.

Explanation of Solution

The numbering of carbon atoms in the given compound is shown below.

ORGANIC CHEMISTRY, Chapter 19, Problem 19.1P , additional homework tip 3

Figure 3

The given compound has a chain of six carbon atoms. The carboxylic acid is present as a functional group in the compound. Two ethyl groups are present at second and fourth carbon atoms. Therefore, the name of the compound is 2, 4-diethylhexanoic acid.

Conclusion

The IUPAC name of the compound is 2, 4-diethylhexanoic acid.

Interpretation Introduction

(d)

Interpretation:The IUPAC name for the given compound is to be stated.

Concept introduction:The chemical structures are described by IUPAC name or common names. IUPAC name is different from common names because IUPAC name is applied at international level and it comprises suffix, prefix, numbers and other priority rules.

Expert Solution

Answer to Problem 19.1P

The IUPAC name of the compound is 4−isopropyl−6,8−dimethylnonanoic acid.

Explanation of Solution

The numbering of carbon atoms in the given compound is shown below.

ORGANIC CHEMISTRY, Chapter 19, Problem 19.1P , additional homework tip 4

Figure 4

The given compound has a chain of nine carbon atoms. The carboxylic acid is present as a functional group in the compound. Two methyl groups are present at eighth and nine carbon atoms, while one isopropyl group is present at fourth carbon. Therefore, the name of the compound is 4−isopropyl−6,8−dimethylnonanoic acid.

Conclusion

The IUPAC name of the compound is 4−isopropyl−6,8−dimethylnonanoic acid.

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Answer 4

Question

Chapter 19, Problem 19.1P

Interpretation Introduction

(a)

Interpretation:The IUPAC name for the given compound is to be stated.

Concept introduction:The chemical structures are described by IUPAC name or common names. IUPAC nameis different from common names because IUPAC nameis applied at international level and it comprises suffix, prefix, numbers and other priority rules.

Expert Solution

Answer to Problem 19.1P

The IUPAC name of the compound is 3,3−dimethylhexanoic acid.

Explanation of Solution

The numbering of carbon atoms in the given compound is shown below.

ORGANIC CHEMISTRY, Chapter 19, Problem 19.1P , additional homework tip 1

Figure 1

The given compound has a chain of six carbon atoms. The carboxylic acid is present as a functional group in the compound. Two methyl groups are present at a third carbon atom. Therefore, the name of the compound is 3,3−dimethylhexanoic acid.

Conclusion

The IUPAC name of the given compound is 3,3−dimethylhexanoic acid.

Interpretation Introduction

(b)

Interpretation:The IUPAC name for the given compound is to be stated.

Concept introduction:The chemical structures are described by IUPAC name or common names. IUPAC name is different from common names because IUPAC name is applied at international level and it comprises suffix, prefix, numbers and other priority rules.

Expert Solution

Answer to Problem 19.1P

The IUPAC name of the compound is 3−bromo−4−chloro−2−fluoropentanoic acid.

Explanation of Solution

The numbering of carbon atoms in the given compound is shown below.

ORGANIC CHEMISTRY, Chapter 19, Problem 19.1P , additional homework tip 2

Figure 2

The given compound has a chain of five carbon atoms. The carboxylic acid is present as a functional group in the compound. Fluorine, chlorine and bromine is present at second, third and fourth carbon atoms respectively. Therefore, the name of the compound is 3−bromo−4−chloro−2−fluoropentanoic acid.

Conclusion

The IUPAC name of the compound is 3−bromo−4−chloro−2−fluoropentanoic acid.

Interpretation Introduction

(c)

Interpretation:The IUPAC name for the given compound is to be stated.

Concept introduction:The chemical structures are described by IUPAC name or common names. IUPAC name is different from common names because IUPAC name is applied at international level and it comprises suffix, prefix, numbers and other priority rules.

Expert Solution

Answer to Problem 19.1P

The IUPAC name of the compound is 2, 4-diethylhexanoic acid.

Explanation of Solution

The numbering of carbon atoms in the given compound is shown below.

ORGANIC CHEMISTRY, Chapter 19, Problem 19.1P , additional homework tip 3

Figure 3

The given compound has a chain of six carbon atoms. The carboxylic acid is present as a functional group in the compound. Two ethyl groups are present at second and fourth carbon atoms. Therefore, the name of the compound is 2, 4-diethylhexanoic acid.

Conclusion

The IUPAC name of the compound is 2, 4-diethylhexanoic acid.

Interpretation Introduction

(d)

Interpretation:The IUPAC name for the given compound is to be stated.

Concept introduction:The chemical structures are described by IUPAC name or common names. IUPAC name is different from common names because IUPAC name is applied at international level and it comprises suffix, prefix, numbers and other priority rules.

Expert Solution

Answer to Problem 19.1P

The IUPAC name of the compound is 4−isopropyl−6,8−dimethylnonanoic acid.

Explanation of Solution

The numbering of carbon atoms in the given compound is shown below.

ORGANIC CHEMISTRY, Chapter 19, Problem 19.1P , additional homework tip 4

Figure 4

The given compound has a chain of nine carbon atoms. The carboxylic acid is present as a functional group in the compound. Two methyl groups are present at eighth and nine carbon atoms, while one isopropyl group is present at fourth carbon. Therefore, the name of the compound is 4−isopropyl−6,8−dimethylnonanoic acid.

Conclusion

The IUPAC name of the compound is 4−isopropyl−6,8−dimethylnonanoic acid.

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Answer 5

Chapter 19, Problem 19.1P

Interpretation Introduction

(a)

Interpretation:The IUPAC name for the given compound is to be stated.

Concept introduction:The chemical structures are described by IUPAC name or common names. IUPAC nameis different from common names because IUPAC nameis applied at international level and it comprises suffix, prefix, numbers and other priority rules.

Expert Solution

Answer to Problem 19.1P

The IUPAC name of the compound is 3,3−dimethylhexanoic acid.

Explanation of Solution

The numbering of carbon atoms in the given compound is shown below.

ORGANIC CHEMISTRY, Chapter 19, Problem 19.1P , additional homework tip 1

Figure 1

The given compound has a chain of six carbon atoms. The carboxylic acid is present as a functional group in the compound. Two methyl groups are present at a third carbon atom. Therefore, the name of the compound is 3,3−dimethylhexanoic acid.

Conclusion

The IUPAC name of the given compound is 3,3−dimethylhexanoic acid.

Interpretation Introduction

(b)

Interpretation:The IUPAC name for the given compound is to be stated.

Concept introduction:The chemical structures are described by IUPAC name or common names. IUPAC name is different from common names because IUPAC name is applied at international level and it comprises suffix, prefix, numbers and other priority rules.

Expert Solution

Answer to Problem 19.1P

The IUPAC name of the compound is 3−bromo−4−chloro−2−fluoropentanoic acid.

Explanation of Solution

The numbering of carbon atoms in the given compound is shown below.

ORGANIC CHEMISTRY, Chapter 19, Problem 19.1P , additional homework tip 2

Figure 2

The given compound has a chain of five carbon atoms. The carboxylic acid is present as a functional group in the compound. Fluorine, chlorine and bromine is present at second, third and fourth carbon atoms respectively. Therefore, the name of the compound is 3−bromo−4−chloro−2−fluoropentanoic acid.

Conclusion

The IUPAC name of the compound is 3−bromo−4−chloro−2−fluoropentanoic acid.

Interpretation Introduction

(c)

Interpretation:The IUPAC name for the given compound is to be stated.

Concept introduction:The chemical structures are described by IUPAC name or common names. IUPAC name is different from common names because IUPAC name is applied at international level and it comprises suffix, prefix, numbers and other priority rules.

Expert Solution

Answer to Problem 19.1P

The IUPAC name of the compound is 2, 4-diethylhexanoic acid.

Explanation of Solution

The numbering of carbon atoms in the given compound is shown below.

ORGANIC CHEMISTRY, Chapter 19, Problem 19.1P , additional homework tip 3

Figure 3

The given compound has a chain of six carbon atoms. The carboxylic acid is present as a functional group in the compound. Two ethyl groups are present at second and fourth carbon atoms. Therefore, the name of the compound is 2, 4-diethylhexanoic acid.

Conclusion

The IUPAC name of the compound is 2, 4-diethylhexanoic acid.

Interpretation Introduction

(d)

Interpretation:The IUPAC name for the given compound is to be stated.

Concept introduction:The chemical structures are described by IUPAC name or common names. IUPAC name is different from common names because IUPAC name is applied at international level and it comprises suffix, prefix, numbers and other priority rules.

Expert Solution

Answer to Problem 19.1P

The IUPAC name of the compound is 4−isopropyl−6,8−dimethylnonanoic acid.

Explanation of Solution

The numbering of carbon atoms in the given compound is shown below.

ORGANIC CHEMISTRY, Chapter 19, Problem 19.1P , additional homework tip 4

Figure 4

The given compound has a chain of nine carbon atoms. The carboxylic acid is present as a functional group in the compound. Two methyl groups are present at eighth and nine carbon atoms, while one isopropyl group is present at fourth carbon. Therefore, the name of the compound is 4−isopropyl−6,8−dimethylnonanoic acid.

Conclusion

The IUPAC name of the compound is 4−isopropyl−6,8−dimethylnonanoic acid.

Answer 6

Chapter 19, Problem 19.1P

Interpretation Introduction

(a)

Interpretation:The IUPAC name for the given compound is to be stated.

Concept introduction:The chemical structures are described by IUPAC name or common names. IUPAC nameis different from common names because IUPAC nameis applied at international level and it comprises suffix, prefix, numbers and other priority rules.

Expert Solution

Answer to Problem 19.1P

The IUPAC name of the compound is 3,3−dimethylhexanoic acid.

Explanation of Solution

The numbering of carbon atoms in the given compound is shown below.

ORGANIC CHEMISTRY, Chapter 19, Problem 19.1P , additional homework tip 1

Figure 1

The given compound has a chain of six carbon atoms. The carboxylic acid is present as a functional group in the compound. Two methyl groups are present at a third carbon atom. Therefore, the name of the compound is 3,3−dimethylhexanoic acid.

Conclusion

The IUPAC name of the given compound is 3,3−dimethylhexanoic acid.

Answer 7

Chapter 19, Problem 19.1P

Interpretation Introduction

(a)

Interpretation:The IUPAC name for the given compound is to be stated.

Concept introduction:The chemical structures are described by IUPAC name or common names. IUPAC nameis different from common names because IUPAC nameis applied at international level and it comprises suffix, prefix, numbers and other priority rules.

Answer 8

Expert Solution

Answer to Problem 19.1P

The IUPAC name of the compound is 3,3−dimethylhexanoic acid.

Answer 9

Expert Solution

Answer 10

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

The numbering of carbon atoms in the given compound is shown below.

ORGANIC CHEMISTRY, Chapter 19, Problem 19.1P , additional homework tip 1

Figure 1

The given compound has a chain of six carbon atoms. The carboxylic acid is present as a functional group in the compound. Two methyl groups are present at a third carbon atom. Therefore, the name of the compound is 3,3−dimethylhexanoic acid.

Answer 13

Conclusion

The IUPAC name of the given compound is 3,3−dimethylhexanoic acid.

Answer 14

Interpretation Introduction

(b)

Interpretation:The IUPAC name for the given compound is to be stated.

Concept introduction:The chemical structures are described by IUPAC name or common names. IUPAC name is different from common names because IUPAC name is applied at international level and it comprises suffix, prefix, numbers and other priority rules.

Expert Solution

Answer to Problem 19.1P

The IUPAC name of the compound is 3−bromo−4−chloro−2−fluoropentanoic acid.

Explanation of Solution

The numbering of carbon atoms in the given compound is shown below.

ORGANIC CHEMISTRY, Chapter 19, Problem 19.1P , additional homework tip 2

Figure 2

The given compound has a chain of five carbon atoms. The carboxylic acid is present as a functional group in the compound. Fluorine, chlorine and bromine is present at second, third and fourth carbon atoms respectively. Therefore, the name of the compound is 3−bromo−4−chloro−2−fluoropentanoic acid.

Conclusion

The IUPAC name of the compound is 3−bromo−4−chloro−2−fluoropentanoic acid.

Answer 15

Interpretation Introduction

(b)

Interpretation:The IUPAC name for the given compound is to be stated.

Concept introduction:The chemical structures are described by IUPAC name or common names. IUPAC name is different from common names because IUPAC name is applied at international level and it comprises suffix, prefix, numbers and other priority rules.

Answer 16

Expert Solution

Answer to Problem 19.1P

The IUPAC name of the compound is 3−bromo−4−chloro−2−fluoropentanoic acid.

Answer 17

Expert Solution

Answer 18

Expert Solution

Answer 19

Expert Solution

Answer 20

Explanation of Solution

The numbering of carbon atoms in the given compound is shown below.

ORGANIC CHEMISTRY, Chapter 19, Problem 19.1P , additional homework tip 2

Figure 2

The given compound has a chain of five carbon atoms. The carboxylic acid is present as a functional group in the compound. Fluorine, chlorine and bromine is present at second, third and fourth carbon atoms respectively. Therefore, the name of the compound is 3−bromo−4−chloro−2−fluoropentanoic acid.

Answer 21

Conclusion

The IUPAC name of the compound is 3−bromo−4−chloro−2−fluoropentanoic acid.

Answer 22

Interpretation Introduction

(c)

Interpretation:The IUPAC name for the given compound is to be stated.

Concept introduction:The chemical structures are described by IUPAC name or common names. IUPAC name is different from common names because IUPAC name is applied at international level and it comprises suffix, prefix, numbers and other priority rules.

Expert Solution

Answer to Problem 19.1P

The IUPAC name of the compound is 2, 4-diethylhexanoic acid.

Explanation of Solution

The numbering of carbon atoms in the given compound is shown below.

ORGANIC CHEMISTRY, Chapter 19, Problem 19.1P , additional homework tip 3

Figure 3

The given compound has a chain of six carbon atoms. The carboxylic acid is present as a functional group in the compound. Two ethyl groups are present at second and fourth carbon atoms. Therefore, the name of the compound is 2, 4-diethylhexanoic acid.

Conclusion

The IUPAC name of the compound is 2, 4-diethylhexanoic acid.

Answer 23

Interpretation Introduction

(c)

Interpretation:The IUPAC name for the given compound is to be stated.

Concept introduction:The chemical structures are described by IUPAC name or common names. IUPAC name is different from common names because IUPAC name is applied at international level and it comprises suffix, prefix, numbers and other priority rules.

Answer 24

Expert Solution

Answer to Problem 19.1P

The IUPAC name of the compound is 2, 4-diethylhexanoic acid.

Answer 25

Expert Solution

Answer 26

Expert Solution

Answer 27

Expert Solution

Answer 28

Explanation of Solution

The numbering of carbon atoms in the given compound is shown below.

ORGANIC CHEMISTRY, Chapter 19, Problem 19.1P , additional homework tip 3

Figure 3

The given compound has a chain of six carbon atoms. The carboxylic acid is present as a functional group in the compound. Two ethyl groups are present at second and fourth carbon atoms. Therefore, the name of the compound is 2, 4-diethylhexanoic acid.

Answer 29

Conclusion

The IUPAC name of the compound is 2, 4-diethylhexanoic acid.

Answer 30

Interpretation Introduction

(d)

Interpretation:The IUPAC name for the given compound is to be stated.

Concept introduction:The chemical structures are described by IUPAC name or common names. IUPAC name is different from common names because IUPAC name is applied at international level and it comprises suffix, prefix, numbers and other priority rules.

Expert Solution

Answer to Problem 19.1P

The IUPAC name of the compound is 4−isopropyl−6,8−dimethylnonanoic acid.

Explanation of Solution

The numbering of carbon atoms in the given compound is shown below.

ORGANIC CHEMISTRY, Chapter 19, Problem 19.1P , additional homework tip 4

Figure 4

The given compound has a chain of nine carbon atoms. The carboxylic acid is present as a functional group in the compound. Two methyl groups are present at eighth and nine carbon atoms, while one isopropyl group is present at fourth carbon. Therefore, the name of the compound is 4−isopropyl−6,8−dimethylnonanoic acid.

Conclusion

The IUPAC name of the compound is 4−isopropyl−6,8−dimethylnonanoic acid.

Answer 31

Interpretation Introduction

(d)

Interpretation:The IUPAC name for the given compound is to be stated.

Concept introduction:The chemical structures are described by IUPAC name or common names. IUPAC name is different from common names because IUPAC name is applied at international level and it comprises suffix, prefix, numbers and other priority rules.

Answer 32

Expert Solution

Answer to Problem 19.1P

The IUPAC name of the compound is 4−isopropyl−6,8−dimethylnonanoic acid.

Answer 33

Expert Solution

Answer 34

Expert Solution

Answer 35

Expert Solution

Answer 36

Explanation of Solution

The numbering of carbon atoms in the given compound is shown below.

ORGANIC CHEMISTRY, Chapter 19, Problem 19.1P , additional homework tip 4

Figure 4

The given compound has a chain of nine carbon atoms. The carboxylic acid is present as a functional group in the compound. Two methyl groups are present at eighth and nine carbon atoms, while one isopropyl group is present at fourth carbon. Therefore, the name of the compound is 4−isopropyl−6,8−dimethylnonanoic acid.