Nernst equation for the given electrode reaction should be written and reason for electrolysis of concentrated Sodium chloride release Chlorine gas rather than Oxygen gas at anode should be explained. Concept Introduction: Nernst equation: The relationship between standard cell potential and cell potential at non standard conditions and the reaction quotient are given by Nernst equation it is, E cell = E° cell - 2 .303 RT nF logQ Where, E cell is cell potential E° cell is standard cell potential R is gas constant T is temperature Q is reaction quotient Electrolysis: Decomposition of Chemical, when the electric current is passing through into its ionic solution is known as electrolysis.
Nernst equation for the given electrode reaction should be written and reason for electrolysis of concentrated Sodium chloride release Chlorine gas rather than Oxygen gas at anode should be explained. Concept Introduction: Nernst equation: The relationship between standard cell potential and cell potential at non standard conditions and the reaction quotient are given by Nernst equation it is, E cell = E° cell - 2 .303 RT nF logQ Where, E cell is cell potential E° cell is standard cell potential R is gas constant T is temperature Q is reaction quotient Electrolysis: Decomposition of Chemical, when the electric current is passing through into its ionic solution is known as electrolysis.
Solution Summary: The author explains Nernst equation for the electrolysis of concentrated Sodium chloride release Chlorine gas rather than Oxygen gas at anode.
Author: Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Nernst equation for the given electrode reaction should be written and reason for electrolysis of concentrated Sodium chloride release Chlorine gas rather than Oxygen gas at anode should be explained.
Concept Introduction:
Nernst equation:
The relationship between standard cell potential and cell potential at non standard conditions and the reaction quotient are given by Nernst equation it is,
Relative Intensity
Part VI. consider the multi-step reaction below for compounds
A, B, and C.
These compounds were subjected to mass spectrometric analysis and
the following spectra for A, B, and C was obtained.
Draw the structure of B and C and match all three compounds
to the correct spectra.
Relative Intensity
Relative Intensity
100
HS-NJ-0547
80
60
31
20
S1
84
M+
absent
10
30
40
50
60
70
80
90
100
100-
MS2016-05353CM
80-
60
40
20
135 137
S2
164 166
0-m
25
50
75
100
125
150
m/z
60
100
MS-NJ-09-43
40
20
20
80
45
S3
25
50
75
100
125
150
175
m/z
Part II. Given two isomers: 2-methylpentane (A) and 2,2-dimethyl butane (B) answer the following:
(a) match structures of isomers given their mass spectra below (spectra A and spectra B)
(b) Draw the fragments given the following prominent peaks from
each spectrum:
Spectra A m/2 =43 and 1/2-57
spectra B m/2 = 43
(c) why is 1/2=57 peak in spectrum A more intense compared
to the same peak in spectrum B.
Relative abundance
Relative abundance
100
A
50
29
29
0
10
-0
-0
100
B
50
720
30
41
43
57
71
4-0
40
50
60 70
m/z
43
57
8-0
m/z = 86
M
90 100
71
m/z = 86
M
-O
0
10 20 30
40 50
60
70
80
-88
m/z
90
100
Chapter 19 Solutions
General Chemistry - Standalone book (MindTap Course List)
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Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell