Applied Statics and Strength of Materials (6th Edition)
6th Edition
ISBN: 9780133840544
Author: George F. Limbrunner, Craig D'Allaird, Leonard Spiegel
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Videos
Textbook Question
Chapter 19, Problem 19.11P
A fillet weld between two steel plates intersecting at right angles was made with one
leg and one
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
Note: the drawing below shows the end view of a weldment consisting of 7 tubes.
8.625"
4.
What is the c-c distance between each of the seven tubes in the weldment above?
QUESTION 3
2. For the given welded bracket shown, design the required size of weld
needed to resist the given eccentric load P=125 kN. Use E70xx electrode.
Where: X=150mm, Y=125mm, Z=50mm
what is the maximum force on the welds in kN? (2 decimal places)
X
Y
2
Chapter 19 Solutions
Applied Statics and Strength of Materials (6th Edition)
Ch. 19 - Prob. 19.1PCh. 19 - Rework Problem 19.1 assuming a bearing-type...Ch. 19 - Rework Problem 19.1 assuming a bearing-type...Ch. 19 - Compute the allowable tensile load for the...Ch. 19 - Rework Problem 19.4 assuming a bearing-type...Ch. 19 - Rework Problem 19.4 assuming that the bolts are 34...Ch. 19 - Select the number and arrangement of 34 in....Ch. 19 - Calculate the allowable tensile load for the...Ch. 19 - In the connection shown, 14 in. side and end...Ch. 19 - Design the fillet welds parallel to the applied...
Ch. 19 - A fillet weld between two steel plates...Ch. 19 - Design an end connection using longitudinal welds...Ch. 19 - Calculate the allowable tensile load for the butt...Ch. 19 - Calculate the allowable tensile load for the lap...Ch. 19 - Calculate the allowable tensile load for the butt...Ch. 19 - Rework Problem 19.10 assuming that both plates are...Ch. 19 - Rework Problem 19.12 assuming that the angle is an...Ch. 19 - Two ASTM A36 steel plates, each 12 in. by 12 in. ,...Ch. 19 - Rework Problem 19.20 changing the fasteners to 34...Ch. 19 - Calculate the minimum main plate thickness for the...Ch. 19 - A roof truss tension member is made up of 2L6412...Ch. 19 - Rework Problem 19.23 changing the fasteners to six...Ch. 19 - Determine the allowable tensile load that can be...Ch. 19 - The welded connection shown is subjected to an...Ch. 19 - In Problem 19.26, use a 38 in. fillet weld, change...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- Determine the fillet weld size required if #70 electrodes are used.arrow_forwardO wrapping the weld around the corner a minuimum of the specified weld size and ar wrapping the weld around the corner for a distance not less than two times nor mor QUESTION 4 On all CJP groove welds in butt joints transverse to the computed tensile stress, they:. O A. Shall have no visible porosity that exceeds 1/32" O B. shall have no visible porosity that exceeds 3/32" O C. shall have no visible porosity O D. shall not have a sum of visible porosity that exceeds 3/8" O E. shall not have a sum of visible porosity that exceeds 1/2" QUESTION 5arrow_forward8. Design the length of weld (L) in the connection below to develop the full tensile capacity of the plate. Use E70 electrodes and 1/4" side fillet welds. The material is ASTM A36 Steel and the allowable axial tensile stress is 22,000 psi. (show all your work) "L" PL 1/2" PL 3/8" x 6" Parrow_forward
- Determine the length of the weld run for a plate of size 120 mm wide and 15 mm thick to be welded to another plate by means of 1. A single transverse weld; and 2. Double parallel fillet welds when the joint is subjected to variable loads.arrow_forwardDetermine the y_bar coordinate of the composite shape. Treat the bent corners as square and ignore the fillet welds. The answer is 272 mm btw.arrow_forward15 What is the weight of the weldment shown? (MS) Plate= .2835 lbs. per cubic inch. S 58" x 21 x 21" M.S. plate both ends 5/8=-625 W16 x 26 x 14 12' a 26 lbs/ft a. 241.90 lbs b. 533.28 lbs. C. 206.45 lbs d. 455.14 lbs 7arrow_forward
- Show your full work. Don't provide the wrong solution.arrow_forwardFind the information from the following weld symbol. 20 2.arrow_forwardQuestion: a) A plate 100 mm wide and 10 mm thick is to be welded to another plate by means of double parallel fillets. The plates are subjected to a static load of 80 kN. Find the length of weld if the permissible shear stress in the weld does not exceed 55MPa. Determine the increase in load carrying capacity if a combination of single transverse double parallel fillet is used the permissible tensile strength of material is 80MPa. b) Draw a neat sketch of double riveted double cover but joint. If 8mm plates with 20 mm diameter rivets having a pitch of 50 mm are joint using double riveted lap joint. The permissible stresses are permissible tensile stress = 120 MPa;Permissible crushing stress= 100 MPa; Permissble shear stess= 150 MPa. Find the strengths and efficiency of joint, taking the strength of the rivet in double shear acoording to the indian boiler standards.arrow_forward
- Join two pieces of metal that are .045 and .045 thick. The joint is made with a triple row of MS20426 rivets. Use minimum edge distance and spacing. The Joint is 7 inches. Diameter of rivets = Length of rivets = Rivet Part Number = Number of rivets =arrow_forwardsniparrow_forwardDetermine the plate thickness if the rivet diameter was 10 mm?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Welding: Principles and Applications (MindTap Cou...Mechanical EngineeringISBN:9781305494695Author:Larry JeffusPublisher:Cengage Learning
Welding: Principles and Applications (MindTap Cou...
Mechanical Engineering
ISBN:9781305494695
Author:Larry Jeffus
Publisher:Cengage Learning
Differences between Temporary Joining and Permanent Joining.; Author: Academic Gain Tutorials;https://www.youtube.com/watch?v=PTr8QZhgXyg;License: Standard Youtube License