Bundle: Human Biology, Loose-leaf Version, 11th + MindTap Biology, 1 term (6 months) Printed Access Card
11th Edition
ISBN: 9781305616660
Author: Cecie Starr, Beverly McMillan
Publisher: Cengage Learning
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Chapter 19, Problem 10SQ
Summary Introduction
To match: The genetic term appropriately.
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are crossed
A test was done to determine the biological father of a child. The child's blood Type is A and the mother's is AB. Man
#1 has a blood type of B, & man #2 has blood type O.
a.
Which man is the biological father?
b. Draw a Punnett square to show the cross between the father and mother that resulted in this child, noting
the genotypes of the mother, father, and the child.
Joe has classic hemophilia, an X-linked recessive disease. Could Joe
have inherited the gene for this disease from the following people?
Yes
No
a. His
mother's
mother
b. His
mother's
father
c. His
father's
mother
d. His
father's
father
The genetic disease hemophilia A is a sex-linked trait. Jane has an uncle on her father's side of the family who has hemophilia A, her father does not have hemophilia A. On Jane's mother's side of the family there has never been a case of hemophilia A. Should Jane be concerned about passing the gene for hemophilia A to her own children? Explain your answer.
Chapter 19 Solutions
Bundle: Human Biology, Loose-leaf Version, 11th + MindTap Biology, 1 term (6 months) Printed Access Card
Ch. 19 - Define the difference between (a) gene and allele,...Ch. 19 - Prob. 2RQCh. 19 - What is probability, and how is it applied in...Ch. 19 - What is independent assortment? Does independent...Ch. 19 - Alleles are ___________. a. alternate forms of a...Ch. 19 - A heterozygote has _____. a. only one of the...Ch. 19 - Prob. 3SQCh. 19 - Offspring of a cross AA aa are ______. a. all AA...Ch. 19 - Prob. 5SQCh. 19 - Prob. 6SQ
Ch. 19 - Which statement best fits the principle of...Ch. 19 - Prob. 8SQCh. 19 - Prob. 9SQCh. 19 - Prob. 10SQCh. 19 - One gene has alleles A and a. Another has alleles...Ch. 19 - Still referring to Problem 1, what will be the...Ch. 19 - Go back to Problem 1, and assume you now study a...Ch. 19 - The young woman shown at right has albinismvery...Ch. 19 - When you decide to breed your Labrador retriever...Ch. 19 - The ABO blood system has been used to settle cases...Ch. 19 - Prob. 7CTCh. 19 - A man is homozygous dominant for ten different...Ch. 19 - Prob. 9CTCh. 19 - Bill and Marie each have flat feet, long...Ch. 19 - You decide to breed a pair of guinea pigs, one...
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- Match the terms with the best description. ___ dihybrid cross a. bb ___ monohybrid cross b. AaBbAaBb ___ homozygous condition c. Aa ___ heterozygous condition d. AaAaarrow_forwardAnswer the following questions. Letter's ONLY 1. A homozygous dominant parent (FF) and a heterozygous parent (Ff) are crossed. What is the genotypic probability of the offspring? * a. 100% Ff b. 50% Ff c. 50% FF and 50% Ff d. 50% Ff and 50% ff e. 50% dominant and 50% recessive f. 100% dominant 2. After performing an experiment on monohybrid cross about the shape of the pea seeds, data were obtained from the result. There are 87 wrinkled pea seeds and 313 round seeds. Of course, round seed is dominant over wrinkled seed. What is the expected value or ratio for the wrinkled seed? * a. 21.75 b. 65.25 c. 100 d. 300 e. 400 f. None of the choicesarrow_forwardChoose the correct answer. 1.What are the phenotypes of the offspring that results from a cross between snapdragon plants that produce red (RR) and pink (Rr) flowers? (Incomplete dominance) * a. 75% red, 25% pink b. 50% red, 50% pink c. 50% red, 25% pink, 25% white d. 75% pink, 25% red 2. In Dalmatian dogs, the spotted condition (S) is dominant over non-spotted (s). A litter of 8 pups were found—four spotted and four non-spotted. Based on the appearance of the pups, what are the genotypes of the parents? * a. Ss and Ss b. SS and ss c. Ss and ss d. ss and ss 3.The allele for brown eye (B) is dominant to that of blue eye (b). A brown-eyed man with a blue-eyed mother marries a blue-eyed woman. What is the probability that the first child is blue-eyed? * a. 25% b. 75% c. 50% d. 100% 4.The gene for green seed coat (G) is dominant to the gene for yellow seed coat (g). A plant with a yellow seed coat is crossed with a plant with a green seed coat. Eight of the offspring had yellow…arrow_forward
- . Set up the Punnett square for each of the following crosses. These crosses are all for the trait of round (dominant) vs. wrinkled (recessive) in sweet peas. 1. Rr x Rr What percentage off the offspring will be round? _____________________ 2. RR x Rr What percentage off the offspring will be round? _____________________ 3. Rr x rr What percentage off the offspring will be wrinkled? _____________________arrow_forwardThe image shows the genotypes of two parents. The B represents blue flowers, and the b represents white flowers. Bb X bb parent 1 parent 2 A student lists possible offspring of a cross between the two plants. 1. a plant with a blue flower 2. a homozygous plant showing the dominant phenotype 3. a homozygous plant showing the recessive phenotype 4. a plant with a white flower Which three offspring are possible given the two parents? O 1 O 2 O 3 O 4 hp esc -> @ 2 $ 6. tab W e r -arrow_forwardThe image shows the genotypes of two parents. The B represents blue flowers, and the b represents white flowers. Bb X bb parent 1 parent 2 A student lists possible offspring of a cross between the two plants. 1. a plant with a blue flower 2. a homozygous plant showing the dominant phenotype 3. a homozygous plant showing the recessive phenotype 4. a plant with a white flower Which three offspring are possible given the two parents? 0 1 O 2 O 3 esc a %24 %#arrow_forward
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