Bundle: Human Biology, Loose-leaf Version, 11th + MindTap Biology, 1 term (6 months) Printed Access Card
11th Edition
ISBN: 9781305616660
Author: Cecie Starr, Beverly McMillan
Publisher: Cengage Learning
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Chapter 19, Problem 4SQ
Offspring of a cross AA × aa are ______.
- a. all AA
- b. all aa
- c. all Aa
- d. 1/2 AA and 1/2 aa
- e. none of the above
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Chapter 19 Solutions
Bundle: Human Biology, Loose-leaf Version, 11th + MindTap Biology, 1 term (6 months) Printed Access Card
Ch. 19 - Define the difference between (a) gene and allele,...Ch. 19 - Prob. 2RQCh. 19 - What is probability, and how is it applied in...Ch. 19 - What is independent assortment? Does independent...Ch. 19 - Alleles are ___________. a. alternate forms of a...Ch. 19 - A heterozygote has _____. a. only one of the...Ch. 19 - Prob. 3SQCh. 19 - Offspring of a cross AA aa are ______. a. all AA...Ch. 19 - Prob. 5SQCh. 19 - Prob. 6SQ
Ch. 19 - Which statement best fits the principle of...Ch. 19 - Prob. 8SQCh. 19 - Prob. 9SQCh. 19 - Prob. 10SQCh. 19 - One gene has alleles A and a. Another has alleles...Ch. 19 - Still referring to Problem 1, what will be the...Ch. 19 - Go back to Problem 1, and assume you now study a...Ch. 19 - The young woman shown at right has albinismvery...Ch. 19 - When you decide to breed your Labrador retriever...Ch. 19 - The ABO blood system has been used to settle cases...Ch. 19 - Prob. 7CTCh. 19 - A man is homozygous dominant for ten different...Ch. 19 - Prob. 9CTCh. 19 - Bill and Marie each have flat feet, long...Ch. 19 - You decide to breed a pair of guinea pigs, one...
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- 1 p The pedigree below shows the blood types of the Jones family. Review the pedigree and determine the possible genotype(s) of individual 12. AB AB #11 #12 #13 O a. AA O b. 1A Oc. i O d. Only a and b are possible genotypes O e. All of these are possible genotypesarrow_forward1. Based on the cross to the right, what percent of the offspring A a would be considered heterozygous? A. 0% В. 25% С. 50% A AA Aa D. 75% a Aa aaarrow_forwardPlease Aspaarrow_forward
- Two parents without cystic fibrosis have a child with cystic fibrosis. The allele for cystic fibrosis is therefore _________ to the non-disease allele Group of answer choices A. codominant B. recessive C. dominant D. epistatic E. incompletely dominantarrow_forwardа. a chart that shows the combinations (results) for a cross 8. Genetics b. a picture (diagram) that shows genetics pass from generation (pass from 9. Alleles parents to kids to 10. Punnett grandkids) Square genotype of 2 DIFFERENT alleles (Bb, Dd, Aa...) с. 11. Phenotype d. the information on the alleles / Genes (ex. TT, Tt, tt) 12. Genotype e. a person's Physical appearance; their characteristics (ex. Brown eyes) 13. Homozygous f. a type of gene - we get one from our mom and one from our dad. 14. Heterozygous g. genotype of two of the SAME alleles (AA, aa, BB, bb...) 15. Pedigree h. the study of heredity and the variations of characteristics (how people look differently)arrow_forwardThe probability of a crossover occurring between two genes on the same chromosome_____ . a. is unrelated to the distance between them b. decreases with increasing distance between them c. increases with the distance between themarrow_forward
- 1. +Tº a. A female carrier 3 3 4 e. A male carrier 4 979 5 b. A male who is affected with the given trait represented in the pedigree PTO Consider the pedigree illustrated above (i.e., Figure D in the supplemental file). Individual 1-1 can best be described as... c. A male who is not affected with the given trait represented in the pedigree d. A female who is affected with the given trait represented in the pedigree 9 10-13 10arrow_forwardChromosomes undergo division during meiosis. Such chromosomal behaviors are consistent with Mendel's laws of a. Unit Characters b. None of these c. Dominance and Recessiveness d. Independent Assortment e. Secondary Nondisjunction Chromosomes undergo division during meiosis. Such chromosomal behaviors are consistent with Mendel's laws of a. Unit Characters b. None of these c. Dominance and Recessiveness d. Independent Assortment e. Secondary Nondisjunctionarrow_forwardDuring a ____ cross, an individual with the dominant phenotype andunknown genotype is crossed with a ___ individual to determine theunknown genotype.a. single-factor, homozygous recessiveb. two-factor, heterozygousc. test, homozygous dominantd. single-factor, homozygous dominante. test, homozygous recessivearrow_forward
- Klinefelter syndrome (XXY) can most be easily diagnosed by_______ . a. pedigree analysis c. karyotyping b. aneuploidy d. phenotypic treatmentarrow_forwardA BOOKMARK E- Question 4/28 NEXT Which Punnett square shows a cross between a heterozygous tall (Tt) plant and a homozygous short (tt) pea plant? C. A. Tt tt TT TT Tt tt TT TT D. В. Tt Tt tt tt Tt Tt tt tt C DDarrow_forwardare crossed A test was done to determine the biological father of a child. The child's blood Type is A and the mother's is AB. Man #1 has a blood type of B, & man #2 has blood type O. a. Which man is the biological father? b. Draw a Punnett square to show the cross between the father and mother that resulted in this child, noting the genotypes of the mother, father, and the child.arrow_forward
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