Bundle: Human Biology, Loose-leaf Version, 11th + MindTap Biology, 1 term (6 months) Printed Access Card
11th Edition
ISBN: 9781305616660
Author: Cecie Starr, Beverly McMillan
Publisher: Cengage Learning
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Chapter 19, Problem 3CT
Go back to Problem 1, and assume you now study a third gene having alleles C and c. For each genotype listed, what type(s) of gametes can be produced?
- a. AABBCC
- b. AaBBcc
- c. AaBBCc
- d. AaBbCc
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What is/are the phenotypes of the recombinant offspring of the F2generation?a. red eyes, long wingsb. white eyes, miniature wingsc. red eyes, long wings and white eyes, miniature wingsd. red eyes, miniature wings and white eyes, long wings
[Answer the multiple-choice questions based on the following experiment:P generation: True-breeding flies with red eyes and long wings werecrossed to flies with white eyes and miniature wings. All F1 offspringhad red eyes and long wings.The F1 female flies were then crossed to males with white eyes and miniaturewings. The following results were obtained for the F2 generation:129 red eyes, long wings133 white eyes, miniature wings71 red eyes, miniature wings67 white eyes, long wings]
a. What is the type of inheritance?
b. What is known of the genotype of the male in the above cross?
c. What is known of the genotype of the female in the above cross?
d. Provide map distances if possible.
How many different types of gametes could be produced by an individual of genotype (remember your simple multiplication regarding potential outcomes for EACH gene): a. aaBbCcDdEeffGG b. AabbCcDdeeFF c. aaBBccDD
Chapter 19 Solutions
Bundle: Human Biology, Loose-leaf Version, 11th + MindTap Biology, 1 term (6 months) Printed Access Card
Ch. 19 - Define the difference between (a) gene and allele,...Ch. 19 - Prob. 2RQCh. 19 - What is probability, and how is it applied in...Ch. 19 - What is independent assortment? Does independent...Ch. 19 - Alleles are ___________. a. alternate forms of a...Ch. 19 - A heterozygote has _____. a. only one of the...Ch. 19 - Prob. 3SQCh. 19 - Offspring of a cross AA aa are ______. a. all AA...Ch. 19 - Prob. 5SQCh. 19 - Prob. 6SQ
Ch. 19 - Which statement best fits the principle of...Ch. 19 - Prob. 8SQCh. 19 - Prob. 9SQCh. 19 - Prob. 10SQCh. 19 - One gene has alleles A and a. Another has alleles...Ch. 19 - Still referring to Problem 1, what will be the...Ch. 19 - Go back to Problem 1, and assume you now study a...Ch. 19 - The young woman shown at right has albinismvery...Ch. 19 - When you decide to breed your Labrador retriever...Ch. 19 - The ABO blood system has been used to settle cases...Ch. 19 - Prob. 7CTCh. 19 - A man is homozygous dominant for ten different...Ch. 19 - Prob. 9CTCh. 19 - Bill and Marie each have flat feet, long...Ch. 19 - You decide to breed a pair of guinea pigs, one...
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- The F1 flies described in question 1 were mated with brown-eyed flies from a true-breeding line. What phenotypes would you expect the offspring to have? (a) all with red eyes (b) all with brown eyes (c) half with red eyes and half with brown eyes (d) red-eyed females and brown-eyed males (e) brown-eyed females and red-eyed malesarrow_forwarda. aabbccDd b. AabbCcDd c. AAbbCCddarrow_forwardFor this problem, use the information given in problem 15. A young woman with blood type O gave birth to a baby with blood type O. In a court case, she claims that a certain young man is the father of her child. The man has type A blood. Could he be the father? Can it be proven on this evidence alone that he is the father? ^Need answers to that one, including genotype, phenotype gametes and punnett square. This is question 15 as a little background dont need this solved . In humans, there are three alleles for blood type: A, B, and O. The allele for blood type A and the allele for blood type B show incomplete dominance. A person with both alleles has blood type AB. Both A and B dominate type O. A person with alleles for blood types A and O marries someone with alleles for blood types B and O. List the types of blood their offspring could have and the probability for each blood type in the offspringarrow_forward
- Hemophilia is a disease caused by a gene found on the X chromosome. Therefore, it is referred to as a sex-linked disease. The recessive allele causes the disease. A man with hemophilia (xhy) marries a woman who is homozygous dominant (XHXH. A. Illustrate using a Punnett square the probability that their children will have the disease. B. Will any of their children have the disease? C. Predict the probabilities of their children having the disease.arrow_forward. A sex-linked recessive allele c produces a red–green color blindness in humans. A normal woman whose father was color blind marries a color-blind mana. What genotypes are possible for the mother of the color-blind man? b. What are the chances that the first child from this marriage will be a color-blind boy? c. Of the girls produced by these parents, what proportion can be expected to be color blind? d. Of all the children (sex unspecified) of these parents, what proportion can be expected to have normal color vision?arrow_forwarda. Which progeny are the parental types? How can you tell?b. Which progeny are the recombinants? How can you tell?c. Do the results of this test cross support linkage of the traits? What is the % recombination?arrow_forward
- or each of the following genotypes how many gametes would be made? a. AaBb - b. AaBbCC - c. AABbCcdd - d. AabbCcDd -arrow_forwardGenes G and H are located on chromosome 18. A woman with the genotype Gg Hh has a child with a man with the genotype GG HH. Unfortunately, the child has the genotype Ggg hhh and only survives for 6 months. When and in which parent did nondisjunction occur? Group of answer choices a. Meiosis II in the mother b. Meiosis I in the mother c. Meiosis I in the father d. Meiosis II in the fatherarrow_forwardPhenotypic ratio Type A : Type O = 2:2 or 1:1 Let's Try This! I1. Solve for the genetic problems below. One point each for: a. genotype of the parents b. Punnett square C. genotypic ratio d. phenotypic ratio e. type of Mendelian or non-Mendelian principlearrow_forward
- Questions a to e are answerable by yes or no. Indicate the possible parental genotypes if your answer is yes.a. Can a man with hairy ears have a hairy-eared daughter?b. Can two normal parents produce a colorblind son?c. Can two normal parents produce a colorblind daughter?d. Can a colorblind woman have a normal son?e. Can a bald man have a nonbald daughter?arrow_forwardWhich process is best represented by the diagram belowarrow_forward#11arrow_forward
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