Horizons: Exploring the Universe (MindTap Course List)
14th Edition
ISBN: 9781305960961
Author: Michael A. Seeds, Dana Backman
Publisher: Cengage Learning
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Chapter 19, Problem 10P
The mass of an average comet’s nucleus is about 1014 kg. If the Oort cloud contains
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There are two parts to this question. The answers are not 4.690117253 abd 0.2742758627. Please help!
It is believed there are 2.7 x 1012 comets in the Oort Cloud, which has a radius of 71000.0 AU. Calculate the average volume that each comet has to itself. Then take the cube root of the average volume per comet to find their typical spacing in AU.
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Chapter 19 Solutions
Horizons: Exploring the Universe (MindTap Course List)
Ch. 19 - What do Widmanst?tten patterns indicate about the...Ch. 19 - What do chondrules tell you about the history of...Ch. 19 - Why are there no chondrules in achondritic...Ch. 19 - Why do astronomers refer to carbonaceous...Ch. 19 - Prob. 5RQCh. 19 - Prob. 6RQCh. 19 - Why do astronomers think the asteroids were never...Ch. 19 - Prob. 8RQCh. 19 - What evidence indicates that some asteroids have...Ch. 19 - What evidence indicates that some asteroids have...
Ch. 19 - Prob. 11RQCh. 19 - What is the difference between a gas tail and a...Ch. 19 - Prob. 13RQCh. 19 - What are the hypotheses for how the bodies in the...Ch. 19 - Prob. 15RQCh. 19 - Prob. 1DQCh. 19 - Do you think the government should spend money to...Ch. 19 - Prob. 1PCh. 19 - If a single asteroid 1 km in diameter were to be...Ch. 19 - If a trillion (1012) asteroids, each 1 km in...Ch. 19 - Prob. 4PCh. 19 - What is the maximum angular diameter of the...Ch. 19 - Prob. 6PCh. 19 - Prob. 7PCh. 19 - Prob. 8PCh. 19 - What is the orbital period of a comet nucleus in...Ch. 19 - The mass of an average comet’s nucleus is about...Ch. 19 - Prob. 1LTLCh. 19 - Prob. 2LTLCh. 19 - Prob. 3LTL
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- It is believed that there are 1.6*10^12 comets in the spherical Oort Cloud,which has radius of 46000 AU.Calculate the average volume that each comet has to itself.Then take cube root of average volume per comet to find their typical spacing in AU.arrow_forwardThis is a challenging problem. Solve it on paper, writing out each step carefully. When doing calculations, do not round intermediate values. Note: If you have approached the problem in a principled way, do not abandon your approach if your numerical answer is not accepted; check your calculations! This problem is closely related to the spectacular impact of the comet Shoemaker-Levy with Jupiter in July 1994. (More information about the event can be found here.) A rock far outside a solar system similar to ours is initially moving very slowly relative to its sun, in the plane of the orbit of a large planet (about the size of Jupiter) around its sun. The rock falls toward the sun, but on its way to the sun it collides with the planet. The mass of the planet is 4 x 1027 kg, the mass of its sun is 3.2 x 1030 kg, the radius of the planet is 1.4 x 10® m, and the center-to-center distance from the planet to the sun is 9.2 x 1011 m. Part 1 (a) Calculate the rock's speed just before it…arrow_forwardYou observe a comet 0.46 AU from Earth with a tail that is 1.7 degrees long. How long is the tail in AU? How long is the tail in kilometers? How many times could the U.S. fit along the length of the tail? (The width of the U.S. is 4,313 km.)arrow_forward
- Consider an asteroid that orbits in a relatively circular orbit with a semimajor axis a = 2 au from the Sun. A typical asteroid has an albedo, or reflectivity, A ~ 0.3. At our closest approach to the asteroid, we make a measurement of the flux coming from the asteroid to be F = 3 × 10-15 w m-2. What is the radius of the asteroid in km? Include a labelled diagram along with your calculations.arrow_forwardIf the velocity of the solar wind is about 4.0 ✕ 102 km/s and the visible tail of a comet is 8.0 ✕ 108 km long, how many days does an atom in the solar wind take to travel from the nucleus to the end of the visible tail? (Note: 1 day = 86,400 seconds.)arrow_forwardThere are two parts to this question. Thank you!arrow_forward
- If the velocity of the solar wind is about 4.0 ✕ 102 km/s and the visible tail of a comet is 5.0 ✕ 108 km long, how many days does an atom in the solar wind take to travel from the nucleus to the end of the visible tail? (Note:1 day = 86,400 seconds.)arrow_forwardAssuming a night lasts 12 hours, how many total meteors from Swift Tuttles comet could you see at the rate listed for its shower in Appendix Table A-12?arrow_forwardRefer to Example 13.1. How would the calculation change if a typical comet in the Oort cloud is only 1 km in diameter?arrow_forward
- What is the orbital velocity of Miranda around Uranus? (Hint: Use the formula for circular velocity, Eq. 5-1a. The formula requires input quantities in kg and m.) (Note: Necessary data are given in Celestial Profile: Uranus and Appendix Table A-11.)arrow_forwardTutorial You observe a comet 0.32 AU from Earth with a tail that is 1.7 degrees long. How long is the tail in AU? How long is the tail in kilometers? How many times could the U.S. fit along the length of the tail? (The width of the U.S. is 4,313 km.) Part 1 of 3 You observe a comet 0.32 AU from Earth with a tail that is 1.7 degrees long. How long is the tail in AU? We use the small angle formula to calculate the length of the tail in AU. arc seconds d Ꮎ 2.06 x 105 D Solving for the linear distance gives: dAU = DAU dAU = = AU arc seconds 2.06 x 105arrow_forward____ daysarrow_forward
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