Degarmo's Materials And Processes In Manufacturing
13th Edition
ISBN: 9781119492825
Author: Black, J. Temple, Kohser, Ronald A., Author.
Publisher: Wiley,
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Chapter 18, Problem 64RQ
How might tubular products be made by extrusion?
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CORRECT ANSWER WITH COMPLETE FBD ONLY. I WILL UPVOTE.
A torque wrench is used to tighten the pipe shown.Dimensions: S1 = 400 mm; S2 = 250 mm; S3 = 100 mmModulus of Rigidity G = 78 GPa1. The diameter of the solid pipe is 20 mm. How much is themaximum force P (N) that can be applied based on theallowable shear stress of 60 MPa?2. For a hollow pipe with 50 mm outside diameter and is 6 mmthick, compute for the maximum force P (kN) that can beapplied such that the angle of twist at A does not exceed 5degrees.3. The torque applied to tighten the hollow pipe is 200 N-m.Given: Pipe outside diameter = 50 mm Pipe thickness = 6 mmSolve for the resulting maximum shear stress (MPa) in the pipe.
Correct answer and complete fbd only. I will upvote.
6: The shaft carries a total torque T0 that is uniformly distributedover its length L. Determine the angle of twist (degrees) of the shaft in termsif T0 = 1.2 kN-m, L = 2 m, G = 80 GPa, and diameter = 120 mm.
2. Calculate the force in all members of the trusses shown using the method of joints.
A
5525 lb
C
3500 lb
BY
14'-0"
D
10'- 0"
6250 lb
10'- 0"
E
Chapter 18 Solutions
Degarmo's Materials And Processes In Manufacturing
Ch. 18 - Briefly describe the evolution of forming...Ch. 18 - What are some of the possible means of classifying...Ch. 18 - How are bulk deformation processes different from...Ch. 18 - Prob. 4RQCh. 18 - Prob. 5RQCh. 18 - Prob. 6RQCh. 18 - Prob. 7RQCh. 18 - Why is it undesirable to minimize friction between...Ch. 18 - Prob. 9RQCh. 18 - Prob. 10RQ
Ch. 18 - Prob. 11RQCh. 18 - Prob. 12RQCh. 18 - Prob. 13RQCh. 18 - Prob. 14RQCh. 18 - Why is foil almost always rolled on a cluster...Ch. 18 - Prob. 16RQCh. 18 - Prob. 17RQCh. 18 - Prob. 18RQCh. 18 - Prob. 19RQCh. 18 - Explain how hot�rolled products can have...Ch. 18 - What is mill scale, and how can it be removed?Ch. 18 - Discuss the problems in producing uniform...Ch. 18 - Prob. 23RQCh. 18 - How might the addition of horizontal tensions act...Ch. 18 - What are some other techniques to reduce roll...Ch. 18 - What is thermomechanical processing, and what are...Ch. 18 - Provide a concise description of the forging...Ch. 18 - What are some of the types of flow that can occur...Ch. 18 - Prob. 29RQCh. 18 - Prob. 30RQCh. 18 - Prob. 31RQCh. 18 - Prob. 32RQCh. 18 - Prob. 33RQCh. 18 - Prob. 34RQCh. 18 - Prob. 35RQCh. 18 - Prob. 36RQCh. 18 - Prob. 37RQCh. 18 - Prob. 38RQCh. 18 - Prob. 39RQCh. 18 - Describe some of the primary differences among...Ch. 18 - What are some common examples of impression�die...Ch. 18 - What are some of the significant requirements of...Ch. 18 - Why are different tolerances usually applied to...Ch. 18 - What are some of the roles played by lubricants in...Ch. 18 - What are some of the attractive features of...Ch. 18 - What types of product geometry can be produced by...Ch. 18 - What is upset forging?Ch. 18 - What are some of the typical products produced by...Ch. 18 - What types of products can be produced by...Ch. 18 - What are some of the attractive features of...Ch. 18 - How does roll forging differ from a conventional...Ch. 18 - Describe the swaging process.Ch. 18 - What kind of products are produced by swaging?Ch. 18 - How can the swaging process impart different sizes...Ch. 18 - What are some possible objectives of...Ch. 18 - Provide a concise definition of extrusion.Ch. 18 - What metals can be shaped by extrusion?Ch. 18 - What are some of the attractive features of the...Ch. 18 - What is the primary shape limitation of the...Ch. 18 - What is the primary benefit of indirect extrusion?Ch. 18 - What are some temperature considerations in hot...Ch. 18 - Why might lubricant selection be more critical in...Ch. 18 - What are some possible causes of surface cracks in...Ch. 18 - How might tubular products be made by extrusion?Ch. 18 - What types of products are made using a...Ch. 18 - Why can lubricants not be used in spider�mandrel...Ch. 18 - What are some of the attractive features of...Ch. 18 - What are some unique concerns and limitations of...Ch. 18 - What is the unique capability provided by...Ch. 18 - How is the feedstock pushed through the die in...Ch. 18 - Describe the Conform process of continuous...Ch. 18 - What types of feedstock can be used in continuous...Ch. 18 - How is wire, rod, and tube drawing different from...Ch. 18 - Why are rods generally drawn on draw benches,...Ch. 18 - Why is the reduction in area significantly...Ch. 18 - What is the difference between tube drawing and...Ch. 18 - For what types of products might a floating plug...Ch. 18 - What are some of the benefits of cold drawing of...Ch. 18 - What types of materials are used for...Ch. 18 - What is the benefit of a tandem wire drawing...Ch. 18 - What is cold forming?Ch. 18 - What types of products are produced by cold...Ch. 18 - What is impact extrusion and what variations...Ch. 18 - If a product contains a large�diameter head and...Ch. 18 - What are some of the attractive properties or...Ch. 18 - What process can be used to produce seamless pipe...Ch. 18 - What type of products can be made by the...Ch. 18 - What types of rivets can be used when there is...Ch. 18 - How is coining different from a process known as...Ch. 18 - Why might hubbing be an attractive way to produce...Ch. 18 - How might a peening operation increase the...Ch. 18 - What is burnishing?Ch. 18 - Prob. 1PCh. 18 - Consider the extrusion of a cylindrical billet,...Ch. 18 - The force required to compress a cylindrical solid...Ch. 18 - Prob. 4PCh. 18 - Prob. 5PCh. 18 - Prob. 6PCh. 18 - Prob. 7PCh. 18 - Prob. 8PCh. 18 - Based on the size, shape, and desired precision,...Ch. 18 - What types of engineering materials might be able...Ch. 18 - For each of the shape generation methods in part...Ch. 18 - Which of the combinations of part 4 do you feel...Ch. 18 - For this system, outline the specific steps that...Ch. 18 - For your proposed solution, would any additional...
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- Correct answer and complete fbd only. I will upvote. 8: The steel rod fits loosely inside the aluminum sleeve. Both components are attached to a rigid wall at A andjoined together by a pin at B. Because of a slight misalignmentof the pre-drilled holes, the torque T0 = 750 N-m was appliedto the steel rod before the pin could be inserted into theholes. Determine the torque (N-m) in each component afterT0 was removed. Use G = 80 GPa for steel and G = 28 GPa foraluminumarrow_forwardCorrect answer and complete fbd only. I will upvote. 9: The two steel shafts, each with one end builtinto a rigid support, have flanges attached to their freeends. The flanges are to be bolted together. However,initially there is a 6⁰ mismatch in the location of the boltholes as shown in the figure. Determine the maximumshear stress(ksi) in each shaft after the flanges have beenbolted together. The shear modulus of elasticity for steelis 12 x 106 psi. Neglect deformations of the bolts and theflanges.arrow_forwardCorrect answer and complete fbd only. I will upvote. The tapered, wrought iron shaft carriesthe torque T = 2000 lb-in at its free end. Determine theangle of twist (degrees) of the shaft. Use G = 10 x 106psi for wrought ironarrow_forward
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