EBK ORGANIC CHEMISTRY
8th Edition
ISBN: 8220102744127
Author: Bruice
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Textbook Question
Chapter 18, Problem 64P
An aromatic hydrocarbon with a molecular formula of C13H20 has an 1H NMR spectrum with a signal at -7 ppm that integrates to 5H. It also has two singlets: one of the singlets has 1.5 times the area of the second. What is the structure of the aromatic hydrocarbon?
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
An aromatic hydrocarbon with a molecular formula of C13H20 has an 1
H NMR spectrum with a signal at ~7 ppm that integrates to 5H. It also has two
singlets; one of the singlets has 1.5 times the area of the second. What is the structure of the aromatic hydrocarbon?
An aromatic hydrocarbon with a molecular formula of C13H20 has an 1H NMR spectrum with a signal at ~7 ppm that integrates to 5H. It also has twosinglets; one of the singlets has 1.5 times the area of the second. What is the structure of the aromatic hydrocarbon?
An aromatic hydrocarbon with a molecular formula of C13H20 has an 1H NMR spectrum with a signal at ~7 ppm that integrates to 5H. It also has two singlets; one of the singlets has 1.5 times the area of the second. What is the structure of the aromatic hydrocarbon?
Chapter 18 Solutions
EBK ORGANIC CHEMISTRY
Ch. 18.1 - Draw the structure for each of the following: a....Ch. 18.3 - Why does hydration inactivate FeBr3?Ch. 18.6 - Prob. 4PCh. 18.7 - What is the major product of a Friedel-Crafts...Ch. 18.9 - Describe two ways to prepare each of the following...Ch. 18.10 - Prob. 7PCh. 18.11 - Name the following:Ch. 18.11 - Draw a structure for each of the following: a....Ch. 18.11 - Draw the structure for each of the following: a....Ch. 18.11 - Correct the following incorrect names: a....
Ch. 18.12 - Prob. 14PCh. 18.12 - List the compounds in each set from most reactive...Ch. 18.13 - Prob. 16PCh. 18.13 - What product(s) result from nitration of each of...Ch. 18.13 - Prob. 18PCh. 18.13 - What products are obtained from the reaction of...Ch. 18.15 - Give the products, if any, of each of the...Ch. 18.16 - a. Does a coupling reaction have to be used to...Ch. 18.16 - Show how the following compounds can be...Ch. 18.16 - Prob. 24PCh. 18.17 - What is the major product(s) of each of the...Ch. 18.17 - Prob. 26PCh. 18.18 - Why isn't FeBr3 used as a catalyst in the first...Ch. 18.18 - Prob. 29PCh. 18.18 - Write the sequence of steps required for the...Ch. 18.18 - Show how the following compounds can be...Ch. 18.19 - What product is formed from reaction of...Ch. 18.19 - Prob. 33PCh. 18.19 - Draw the structure of the activated ring and the...Ch. 18.20 - Prob. 35PCh. 18.20 - Prob. 36PCh. 18.20 - Diazomethane can be used to convert a carboxylic...Ch. 18.21 - Prob. 38PCh. 18.21 - Prob. 39PCh. 18.21 - Prob. 40PCh. 18.22 - Prob. 41PCh. 18 - Draw the structure for each of the following: a....Ch. 18 - Name the following:Ch. 18 - Prob. 44PCh. 18 - Prob. 45PCh. 18 - For each of the statements in Column I, choose a...Ch. 18 - What product is obtained from the reaction of...Ch. 18 - Draw the product(s) of each of the following...Ch. 18 - Rank the following substituted anilines from most...Ch. 18 - Prob. 50PCh. 18 - Prob. 51PCh. 18 - Show how the following compounds can be...Ch. 18 - Prob. 53PCh. 18 - The compound with the 1H NMR spectrum shown below...Ch. 18 - Rank each group of compounds from most reactive to...Ch. 18 - Prob. 56PCh. 18 - Prob. 57PCh. 18 - For each of the following components, indicate the...Ch. 18 - Prob. 59PCh. 18 - Prob. 60PCh. 18 - Describe two ways to prepare anisole from benzene.Ch. 18 - Prob. 62PCh. 18 - The following tertiary alkyl bromides undergo an...Ch. 18 - An aromatic hydrocarbon with a molecular formula...Ch. 18 - Show how the following compounds can be...Ch. 18 - Use the four compounds shown below to answer the...Ch. 18 - a. Rank the following esters from most reactive to...Ch. 18 - A mixture of 0.10 mol benzene and 0.10 mol...Ch. 18 - Prob. 69PCh. 18 - Prob. 70PCh. 18 - Benzene underwent a Friedel-Crafts acylation...Ch. 18 - Prob. 72PCh. 18 - Prob. 73PCh. 18 - Friedel-Crafts alkylations can be carried out with...Ch. 18 - Show how the following compounds can be prepared...Ch. 18 - Prob. 76PCh. 18 - Prob. 77PCh. 18 - a. Describe four ways the following reaction can...Ch. 18 - Propose a mechanism for each of the following...Ch. 18 - How can you prepare the following compounds with...Ch. 18 - Describe how naphthalene can he prepared from the...Ch. 18 - Using resonance contributors for the carbocation...Ch. 18 - Prob. 83PCh. 18 - What reagents are required to carry out the...Ch. 18 - Prob. 85PCh. 18 - Prob. 86PCh. 18 - Prob. 87PCh. 18 - Propose a mechanism for each of the following...Ch. 18 - P-Fluoronitrobenzene is more reactive toward...Ch. 18 - When heated with chromic acid, compound A forms...Ch. 18 - Show how the following compounds can be prepared...Ch. 18 - How can you distinguish the following compounds...Ch. 18 - Describe how mescaline can be synthesized from...Ch. 18 - Propose a mechanism for the following reaction...Ch. 18 - Propose a mechanism for each of the following...Ch. 18 - Describe how 3-methyl-1-phenyl-3-pentanol can he...Ch. 18 - An unknown compound reacts with ethyl chloride and...Ch. 18 - a. Explain why the following reaction leads to the...Ch. 18 - Explain why hydroxide ion catalyzes the reaction...Ch. 18 - Prob. 100PCh. 18 - Prob. 101PCh. 18 - a. How can aspirin be synthesized from benzene? b....Ch. 18 - Prob. 103PCh. 18 - Show how Novocain, a painkiller used frequently by...Ch. 18 - Prob. 105PCh. 18 - Saccharin, an artificial sweetener, is about 300...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- An unknown compound has a molecular formula of C,H,O. Its IR spectrum shows prominent absorptions at 2980, 2960, and 1718 cm . It exhibits the following signals in its H NMR spectrum (ppm): 1.06 (triplet, 3H), 2.12 (singlet, 3H), 2.45 (quartet, 2H); and the following signals in its ¹3C NMR spectrum ( ppm): 7.6, 29.5, 36.8, 208.8. Draw the structure of the unknown compound. Click and drag to start drawing a structure. 0 X 0:0arrow_forwardCompounds A and B are isomers having the molecular formula C4H8O3. Identify A and B on the basis of their 1H NMR spectra.Compound A: δ 1.3 (3H, triplet); 3.6 (2H, quartet); 4.1 (2H, singlet); 11.1 (1H, broad singlet)Compound B: δ 2.6 (2H, triplet); 3.4 (3H, singlet); 3.7 (2H triplet); 11.3 (1H, broad singlet)arrow_forwardThe 'H NMR spectrum of compound A (C3H100) has four signals: a multiplet at 8 = 7.25-7.32 ppm (5 H), a singlet at d = 5.17 ppm (1 H), a quartet at d = 4.98 ppm (1 H), and a doublet at ô = 1.49 ppm (3 H). There are 6 signals in its 13C NMR spectrum. The IR spectrum has a broad absorption in the -3200 cm-1 region. Compound A reacts with KMNO4 in a basic solution followed by acidification to give compound B with the molecular formula C7H6O2. Draw structures for compounds A and B.arrow_forward
- Compound B has molecular formula C9H12O. It shows five signals in the 1H-NMR spectrum - a doublet of integral 6 at 1.22 ppm, a septet of integral 1 at 2.86 ppm, a singlet of integral 1 at 5.34 ppm, a doublet of integral 2 at 6.70 ppm, and a doublet of integral 2 at 7.03 ppm. The 13C-NMR spectrum of B shows six unique signals (23.9, 34.0, 115.7, 128.7, 148.9, and 157.4). Identify B and explain your reasoning.arrow_forwardDraw the structure of all constitutional isomers that contain a ketone and have molecular formula C5H10O. Give the IUPAC name for each isomer and state how 13C NMR spectroscopy could be used to distinguish these isomers.arrow_forwardWhat is the structure of the compound with the formula C8H10O has six signals in its 13C-NMR spectrum. The IR spectrum shows signals at 3400 and 2900 cm-1, the 1H-NMR spectrum is: 1.19 ppm (3H triplet) 2.58 ppm (2H quartet) 4.65 ppm (1H broad singlet) 6.07 ppm (2H doublet) 7.05 ppm (2H doublet)arrow_forward
- For following substituted benzenes: [1] C6H5Br; [2] C6H5CN; [3] C6H5OCOCH3: Does the substituent activate or deactivate the benzene ring inelectrophilic aromatic substitution?arrow_forwardCompound A has molecular formula C7H7X. Its 1H-NMR spectrum shows a singlet at 2.26 ppm and two doublets, one at 6.95 ppm and one at 7.28 ppm. The singlet has an integral of three and the doublets each have an integral of two. Its 13C-NMR shows five signals. The mass spectrum of A shows a peak at m/z = 170 and another peak at m/z = 172; the relative height of the two peaks is 1:1 respectively. - Identify what atom X is, explaining your reasoning - Identify Compound A, explaining your reasoning Compound A is treated with a mixture of nitric and sulfuric acids to generate Compound B. The 1H-NMR spectrum of B shows two singlets, one at 2.52 pm and one at 8.13 ppm. The 13C-NMR spectrum of B shows five signals. The mass spectrum of B shows a peak at m/z = 260 and another peak at m/z = 262; the relative height of the two peaks is 1:1 respectively. - Identify compound B, explaining your reasoning Compound B is treated with sodium ethoxide to generate compound C. The 1H-NMR spectrum of C shows…arrow_forwardThree isomeric compounds, A, B, and C, all have molecular formulaC8H11N. The 1H NMR and IR spectral data of A, B, and C are given below.What are their structures?arrow_forward
- Compound A has molecular formula C7H7X. Its ¹H-NMR spectrum shows a singlet at 2.26 ppm and two doublets, one at 6.95 ppm and one at 7.28 ppm. The singlet has an integral of three and the doublets each have an integral of two. Its 13C- NMR shows five signals. The mass spectrum of A shows a peak at m/z 170 and another peak at m/z = 172; the relative height of the two peaks is 1:1 respectively. - Identify what atom X is, explaining your reasoning - Identify Compound A, explaining your reasoning Compound A is treated with a mixture of nitric and sulfuric acids to generate Compound B. The ¹H-NMR spectrum of B shows two singlets, one at 2.52 pm and one at 8.13 ppm. The 13C-NMR spectrum of B shows five signals. The mass spectrum of B shows a peak at m/z = 260 and another peak at m/z = 262; the relative height of the two peaks is 1:1 respectively. - Identify compound B, explaining your reasoning Compound B is treated with sodium ethoxide to generate compound C. The ¹H-NMR spectrum of C shows…arrow_forwardWhy is the structure of compound X? - how do I know??arrow_forwardAlthough benzene itself absorbs at 128 ppm in its 13C NMR spectrum, the carbons of substituted benzenes absorb either upeld or downeld from this value depending on the substituent. Explain the observed values for the carbon ortho to the given substituent in the monosubstituted benzene derivatives X and Y.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning
Organic Chemistry
Chemistry
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:Cengage Learning
General Chemistry | Acids & Bases; Author: Ninja Nerd;https://www.youtube.com/watch?v=AOr_5tbgfQ0;License: Standard YouTube License, CC-BY