(a)
Interpretation:
The
Concept Introduction:
Amides are formed by a reaction with a carboxylic acid and an amine which are the
The mechanism for formation of an amide is as follows taking example of propanoic acid and ethylamine:
The hydrolysis of amide so formed can give back the carboxylic acid and amine.
(b)
Interpretation:
The carboxylic acid and amine or ammonia needs to be identified from which each amide be synthesized.
Concept Introduction:
Amides are formed by a reaction with a carboxylic acid and an amine which are the functional groups. This results in the formation of amide bond, in which OH group of carboxylic acid reacts with one of the H in amine group and CO-NH bond is formed. This bond is known as an amide bond.
The mechanism for formation of an amide is as follows taking example of propanoic acid and ethylamine:
The hydrolysis of amide so formed can give back the carboxylic acid and amine.
(c)
Interpretation:
The carboxylic acid and amine or ammonia needs to be identified from which each amide be synthesized.
Concept Introduction:
Amides are formed by a reaction with a carboxylic acid and an amine which are the functional groups. This results in the formation of amide bond, in which OH group of carboxylic acid reacts with one of the H in amine group and CO-NH bond is formed. This bond is known as an amide bond.
The mechanism for formation of an amide is as follows taking example of propanoic acid and ethylamine:
The hydrolysis of amide so formed can give back the carboxylic acid and amine.
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Chapter 18 Solutions
Introduction to General, Organic and Biochemistry
- Consider the following gas chromatographs of Compound A, Compound B, and a mixture of Compounds A and B. Inject A B mixture Area= 9 Area = 5 Area = 3 Area Inject . མི། Inject J2 What is the percentage of Compound B in the the mixture?arrow_forwardRank these according to stability. CH3 H3C CH3 1 CH3 H3C 1 most stable, 3 least stable O 1 most stable, 2 least stable 2 most stable, 1 least stable O2 most stable, 3 least stable O3 most stable, 2 least stable O3 most stable, 1 least stable CH3 2 CH3 CH3 H₂C CH3 3 CH3 CHarrow_forwardConsider this IR and NMR: INFRARED SPECTRUM TRANSMITTANCE 0.8- 0.6 0.4 0.2 3000 10 9 8 00 HSP-00-541 7 CO 6 2000 Wavenumber (cm-1) сл 5 ppm 4 M Which compound gave rise to these spectra? N 1000 1 0arrow_forward
- Consider this reaction (molecular weights are under each compound): HC=CH + 2 HCI --> C2H4Cl 2 MW = 26 36.5 99 If 4.4 g of HC=CH are reacted with 110 mL of a 2.3 M HCI solution, and 6.0 g of product are actually produced, what is the percent yield?arrow_forwardWhat is the name of the major product of this reaction? OH CH3 H₂SO4, heat 1-methylcyclohexene O2-methyl-1-cyclohexene O 3-mthylcyclohexene 1-methyl-2-cyclohexenearrow_forwardWe added a brown solution of Br2 to one of our products, and the brown color disappeared. This indicated that our product wasarrow_forward
- Rank the following according to reactivity toward nitration: a) benzene b) bromobenzene c) nitrobenzene d) phenol Od) greatest, c) least Od) greatest, b) least Od) greatest, a) least a) greatest, b) least a) greatest, c) least Oa) greatest, d) least Ob) greatest, a) least O b) greatest, c) least Ob) greatest, d) least O c) greatest, a) least O c) greatest, b) least O c) greatest, d) leastarrow_forwardO-Nitrophenol was distilled over with the steam in our experiment while the other isomer did not. This is due to: O intramolecular hydrogen bonding in the ortho isomer O intermolecular hydrogen bonding in the the ortho isomer O the ortho isomer has a lower density O the ortho isomer has a lower molecular weightarrow_forwardK 44% Problem 68 of 15 Submit Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps. :6: :: :CI: CI CI: :0:0 Select to Add Arrows Select to Add Arrows H H Cl CI: CI CI: Select to Add Arrows Select to Add Arrows H :CI: Alarrow_forward
- I I H :0: Submit Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps. 0:0 :0: CI ΑΙ :CI: :CI: :0: CI Select to Add Arrows Select to Add Arrows cl. :0: Cl © ハ CI:: CI H CO Select to Add Arrows Select to Add Arrows 10: AI ::arrow_forwardOrder the following compounds from slowest to fastest in a nucleophilic acyl substitution reaction. ii 요 OB D A E C OCE Darrow_forwardI need the most help figuring out how to find [I^-] mol/ L, [S2O8^2-] mol/L. 1st and 2nd Blank columns.arrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_ios
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