Introduction to General, Organic and Biochemistry
Introduction to General, Organic and Biochemistry
12th Edition
ISBN: 9780357391594
Author: Frederick A. Bettelheim; William H. Brown; Mary K. Campbell
Publisher: Cengage Learning US
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Chapter 18, Problem 25P
Interpretation Introduction

Interpretation:The reason of vinegar like odor from an aspirin bottle if left open to air needs to be explained.

Concept introduction:Aspirin is a phenolic ester of salicylic acid and acetic acid. Esters of salicylic acid possess pain relieving ability.

The structure of Aspirin is as follows:

  Introduction to General, Organic and Biochemistry, Chapter 18, Problem 25P

The hydrolysis of ester results in the formation of carboxylic acid and alcohol.

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Using reaction free energy to predict equilibrium composition Consider the following equilibrium: 2NO(g) +Cl₂ (g) = 2NOC1 (g) AGº = -41. kJ Now suppose a reaction vessel is filled with 8.90 atm of chlorine (C12) and 5.71 atm of nitrosyl chloride (NOC1) at 1075. °C. Answer the following questions about this system: rise Under these conditions, will the pressure of NOCI tend to rise or fall? x10 fall Is it possible to reverse this tendency by adding NO? In other words, if you said the pressure of NOCI will tend to rise, can that be changed to a tendency to fall by adding NO? Similarly, if you said the pressure of NOCI will tend to fall, can that be changed to a tendency to rise by adding NO? yes no If you said the tendency can be reversed in the second question, calculate the minimum pressure of NO needed to reverse it. Round your answer to 2 significant digits. atm ☑ 18 Ar
Identifying the major species in weak acid or weak base equilibria The preparations of two aqueous solutions are described in the table below. For each solution, write the chemical formulas of the major species present at equilibrium. You can leave out water itself. Write the chemical formulas of the species that will act as acids in the 'acids' row, the formulas of the species that will act as bases in the 'bases' row, and the formulas of the species that will act as neither acids nor bases in the 'other' row. You will find it useful to keep in mind that HCN is a weak acid. acids: 0.29 mol of NaOH is added to 1.0 L of a 1.2M HCN solution. bases: ☑ other: 0.09 mol of HCl is added to acids: 1.0 L of a solution that is bases: 0.3M in both HCN and KCN. other: 0,0,... ? 00. 18 Ar 日
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General Chemistry | Acids & Bases; Author: Ninja Nerd;https://www.youtube.com/watch?v=AOr_5tbgfQ0;License: Standard YouTube License, CC-BY