Chemistry: The Science in Context (Fifth Edition)
Chemistry: The Science in Context (Fifth Edition)
5th Edition
ISBN: 9780393614046
Author: Thomas R. Gilbert, Rein V. Kirss, Natalie Foster, Stacey Lowery Bretz, Geoffrey Davies
Publisher: W. W. Norton & Company
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Chapter 18, Problem 18.89QP

(a)

Interpretation Introduction

Interpretation: The information regarding fuel cells having alkali metal carbonates as electrolytes that can make use of Methane as a fuel and the conversion of Methane into Hydrogen in a two step process is given. Various questions based on this concept have to be answered.

Concept introduction: The device that converts the chemical energy from fuel into electrical energy is called fuel cell. Here reaction occurs because of the oxidation of fuel.

To determine: The oxidation number of Carbon and Hydrogen in reactants and products.

(a)

Expert Solution
Check Mark

Answer to Problem 18.89QP

Solution

The oxidation state of Carbon and Hydrogen in equation CH4(g)+H2O(g)CO(g)+3H2(g) is,

  • The oxidation number of Hydrogen is +1_ and C is -4_ in CH4 .
  • The oxidation number of Hydrogen is +1_ in H2O .
  • The oxidation number of C is +2_ in CO
  • As there is no difference of electronegativity in H2 , the oxidation number of Hydrogen is zero.

The oxidation state of Carbon and Hydrogen in equation CO(g)+H2O(g)H2(g)+CO2(g) is,

  • The oxidation number of C is +2_ in CO .
  • The oxidation number of Hydrogen is +1_ in H2O .
  • As there is no difference of electronegativity in H2 , the oxidation number of Hydrogen is zero.
  • The oxidation number of C is +4_ in CO2 .

Explanation of Solution

Explanation

The given reaction is,

CH4(g)+H2O(g)CO(g)+3H2(g)

The oxidation number of Carbon in CH4 is,

x+4(+1)=0x=04x=-4_

The oxidation number of Hydrogen is +1_ and C is -4_ .

The oxidation number of Hydrogen in H2O is,

2x+1(2)=02x=0+22x=2x=1_

The oxidation number of Hydrogen is +1_ .

The oxidation number of Carbon in CO is,

x+1(2)=0x=0+2x=2_

The oxidation number of C is +2_ .

As there is no difference of electronegativity in H2 , the oxidation number of Hydrogen is zero.

The given reaction is,

CO(g)+H2O(g)H2(g)+CO2(g)

The oxidation number of Carbon in CO is,

x+1(2)=0x=0+2x=2_

The oxidation number of C is +2_ .

The oxidation number of Hydrogen in H2O is,

2x+1(2)=02x=0+22x=2x=1_

The oxidation number of Hydrogen is +1_ .

As there is no difference of electronegativity in H2 , the oxidation number of Hydrogen is zero.

The oxidation number of Carbon in CO2 is,

x+2(2)=0x=0+4x=4_

The oxidation number of C is +4_ .

As there is no difference of electronegativity in H2 , the oxidation number of Hydrogen is zero.

(b)

Interpretation Introduction

To determine: The value of ΔG°rxn for each of the given reactions and overall reaction.

(b)

Expert Solution
Check Mark

Answer to Problem 18.89QP

Solution

The value of ΔG°rxn for equation (1) is 142.2kJ_ .

The value of ΔG°rxn for equation (2) is -28.6kJ_ .

The value of ΔG°rxn for overall reaction is 113.6kJ_ -28.6kJ_ .

Explanation of Solution

Explanation

The given reaction is,

CH4(g)+H2O(g)CO(g)+3H2(g) (1)

The standard free energy change is given as,

ΔG°rxn=mΔG°ProductsnΔG°Reactants

Where,

  • m is the coefficient of reactants.
  • n is the coefficients of products.
  • ΔG°Reactants is the standard free energy change of reactants.
  • ΔG°Products is the standard free energy change of products.

The heat of reaction for the above reaction is,

ΔG°rxn=((ΔGf°)CO+3×(ΔGf°)H2)((Δ(Gf°)CH4)+((ΔGf°)H2O))

The value of (ΔGf°)CO is 137.2kJ/mol , (ΔGf°)H2 is 0.0kJ/mol , (Δ(Gf°)CH4) is 50.8kJ/mol and (ΔGf°)H2O is 228.6kJ/mol .

Substitute these values in above equation as,

ΔG°rxn1=((ΔGf°)CO+3×(ΔGf°)H2)((Δ(Gf°)CH4)+((ΔGf°)H2O))=((1mol(137.2kJ/mol)+3mol×0kJ/mol)(1mol(50.8kJ/mol)+1mol(228.6kJ/mol)))=137.2kJ+279.4kJ=142.2kJ_

The given reaction is,

CO(g)+H2O(g)H2(g)+CO2(g) (2)

The heat of reaction for the above reaction is,

ΔG°rxn=((ΔGf°)CO+(ΔGf°)H2)((Δ(Gf°)CO2)+((ΔGf°)H2O))

The value of (ΔGf°)CO is 137.2kJ/mol , (ΔGf°)H2 is 0.0kJ/mol , (Δ(Gf°)CO2) is 394.4kJ/mol and (ΔGf°)H2O is 228.6kJ/mol .

Substitute these values in above equation as,

ΔG°rxn2=((ΔGf°)CO2+(ΔGf°)H2)((Δ(Gf°)CO)+((ΔGf°)H2O))=((1mol(394.4kJ/mol)+1mol×0kJ/mol)(1mol(137.2kJ/mol)+1mol(228.6kJ/mol)))=394.4kJ+365.8kJ=-28.6kJ_

Add the equation (1) and (20 and cancel the similar terms on both the sides of the reaction,

CH4(g)+2H2O(g)CO2(g)+4H2(g)

The value of ΔG°rxn for the above reaction is given as,

ΔG°rxn=ΔG°rxn1+ΔG°rxn2=142.2kJ28.6kJ=113.6kJ_

Conclusion

  1. a. The oxidation state of Carbon and Hydrogen in equation CH4(g)+H2O(g)CO(g)+3H2(g) is,
  • The oxidation number of Hydrogen is +1_ and C is -4_ in CH4 .
  • The oxidation number of Hydrogen is +1_ in H2O .
  • The oxidation number of C is +2_ in CO
  • As there is no difference of electronegativity in H2 , the oxidation number of Hydrogen is zero.

The oxidation state of Carbon and Hydrogen in equation CO(g)+H2O(g)H2(g)+CO2(g) is,

  • The oxidation number of C is +2_ in CO .
  • The oxidation number of Hydrogen is +1_ in H2O .
  • As there is no difference of electronegativity in H2 , the oxidation number of Hydrogen is zero.
  • The oxidation number of C is +4_ in CO2 .
  1. b. The value of ΔG°rxn for equation (1) is 142.2kJ_ .

    The value of ΔG°rxn for equation (2) is -28.6kJ_ .

    The value of ΔG°rxn for overall reaction is 113.6kJ_

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Chapter 18 Solutions

Chemistry: The Science in Context (Fifth Edition)

Ch. 18 - Prob. 18.3VPCh. 18 - Prob. 18.4VPCh. 18 - Prob. 18.5VPCh. 18 - Prob. 18.6VPCh. 18 - Prob. 18.7VPCh. 18 - Prob. 18.8VPCh. 18 - Prob. 18.9VPCh. 18 - Prob. 18.10VPCh. 18 - Prob. 18.11QPCh. 18 - Prob. 18.12QPCh. 18 - Prob. 18.13QPCh. 18 - Prob. 18.14QPCh. 18 - Prob. 18.15QPCh. 18 - Prob. 18.16QPCh. 18 - Prob. 18.17QPCh. 18 - Prob. 18.18QPCh. 18 - Prob. 18.19QPCh. 18 - Prob. 18.20QPCh. 18 - Prob. 18.21QPCh. 18 - Prob. 18.22QPCh. 18 - Prob. 18.23QPCh. 18 - Prob. 18.24QPCh. 18 - Prob. 18.25QPCh. 18 - Prob. 18.26QPCh. 18 - Prob. 18.27QPCh. 18 - Prob. 18.28QPCh. 18 - Prob. 18.29QPCh. 18 - Prob. 18.30QPCh. 18 - Prob. 18.31QPCh. 18 - Prob. 18.32QPCh. 18 - Prob. 18.33QPCh. 18 - Prob. 18.34QPCh. 18 - Prob. 18.35QPCh. 18 - Prob. 18.36QPCh. 18 - Prob. 18.37QPCh. 18 - Prob. 18.38QPCh. 18 - Prob. 18.39QPCh. 18 - Prob. 18.40QPCh. 18 - Prob. 18.41QPCh. 18 - Prob. 18.42QPCh. 18 - Prob. 18.43QPCh. 18 - Prob. 18.44QPCh. 18 - Prob. 18.45QPCh. 18 - Prob. 18.46QPCh. 18 - Prob. 18.47QPCh. 18 - Prob. 18.48QPCh. 18 - Prob. 18.49QPCh. 18 - Prob. 18.50QPCh. 18 - Prob. 18.51QPCh. 18 - Prob. 18.52QPCh. 18 - Prob. 18.53QPCh. 18 - Prob. 18.54QPCh. 18 - Prob. 18.55QPCh. 18 - Prob. 18.56QPCh. 18 - Prob. 18.57QPCh. 18 - Prob. 18.58QPCh. 18 - Prob. 18.59QPCh. 18 - Prob. 18.60QPCh. 18 - Prob. 18.61QPCh. 18 - Prob. 18.62QPCh. 18 - Prob. 18.63QPCh. 18 - Prob. 18.64QPCh. 18 - Prob. 18.65QPCh. 18 - Prob. 18.66QPCh. 18 - Prob. 18.67QPCh. 18 - Prob. 18.68QPCh. 18 - Prob. 18.69QPCh. 18 - Prob. 18.70QPCh. 18 - Prob. 18.71QPCh. 18 - Prob. 18.72QPCh. 18 - Prob. 18.73QPCh. 18 - Prob. 18.74QPCh. 18 - Prob. 18.75QPCh. 18 - Prob. 18.76QPCh. 18 - Prob. 18.77QPCh. 18 - Prob. 18.78QPCh. 18 - Prob. 18.79QPCh. 18 - Prob. 18.80QPCh. 18 - Prob. 18.81QPCh. 18 - Prob. 18.82QPCh. 18 - Prob. 18.83QPCh. 18 - Prob. 18.84QPCh. 18 - Prob. 18.85QPCh. 18 - Prob. 18.86QPCh. 18 - Prob. 18.87QPCh. 18 - Prob. 18.88QPCh. 18 - Prob. 18.89QPCh. 18 - Prob. 18.90QPCh. 18 - Prob. 18.91APCh. 18 - Prob. 18.92APCh. 18 - Prob. 18.93APCh. 18 - Prob. 18.94APCh. 18 - Prob. 18.95APCh. 18 - Prob. 18.96APCh. 18 - Prob. 18.97APCh. 18 - Prob. 18.98APCh. 18 - Prob. 18.99APCh. 18 - Prob. 18.100AP
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