Organic Chemistry
4th Edition
ISBN: 9780073402772
Author: Janice G. Smith
Publisher: MCG
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 18, Problem 18.74P
Interpretation Introduction
Interpretation:
The structure of BHT is to be predicted and a stepwise mechanism that illustrates its formation is to be drawn.
Concept introduction:
Spectroscopy method is used to identify the structure of the molecule. It is based on the interactions between matter and
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
What is the structure of an unknown compound with molecular formula C6H15N that gives the following 1H NMR absorptions: 0.9 (singlet, 1 H), 1.10 (triplet, 3 H), 1.15 (singlet, 9 H), and 2.6 (quartet, 2 H) ppm?
How can 1H NMR distinguish between the compounds in the following pairs?
What is the structure of a compound of molecular formula C10H14O2 that shows a strong IR absorption at 3150–2850 cm-1 and gives the following 1H NMR absorptions: 1.4 (triplet, 6 H), 4.0 (quartet, 4 H), and 6.8 (singlet, 4 H) ppm?
Chapter 18 Solutions
Organic Chemistry
Ch. 18 - Prob. 18.1PCh. 18 - Prob. 18.2PCh. 18 - Prob. 18.3PCh. 18 - Prob. 18.4PCh. 18 - Prob. 18.5PCh. 18 - What acid chloride would be needed to prepare each...Ch. 18 - Prob. 18.7PCh. 18 - Draw a stepwise mechanism for the following...Ch. 18 - Prob. 18.9PCh. 18 - Prob. 18.10P
Ch. 18 - Prob. 18.11PCh. 18 - Prob. 18.12PCh. 18 - Problem 18.14 Draw all resonance structures for...Ch. 18 - Classify each substituent as electron donating or...Ch. 18 - Prob. 18.15PCh. 18 - Label each compound as more or less reactive than...Ch. 18 - Rank the following compounds in order of...Ch. 18 - Problem 18.18 Rank the following compounds in...Ch. 18 - Prob. 18.19PCh. 18 - Problem 18.20 Draw the products of each...Ch. 18 - Prob. 18.21PCh. 18 - Prob. 18.22PCh. 18 - Devise a synthesis of each compound from the...Ch. 18 - Problem 18.24 Draw the products of each...Ch. 18 - Problem 18.25 Draw a stepwise mechanism for the...Ch. 18 - Problem 18.26 Draw the products of each...Ch. 18 - Prob. 18.27PCh. 18 - Prob. 18.28PCh. 18 - Problem 18.29 How could you use ethylbenzene to...Ch. 18 - Prob. 18.30PCh. 18 - Problem 18.31 What steps are needed to convert...Ch. 18 - Problem 18.32 Synthesize each compound from...Ch. 18 - Synthesize each compound from benzene.Ch. 18 - Prob. 18.34PCh. 18 - 18.35 What is the major product formed by an...Ch. 18 - Draw the products formed when phenol (C6H5OH) is...Ch. 18 - Prob. 18.37PCh. 18 - Draw the products of each reaction. a. e. i. b. f....Ch. 18 - What products are formed when benzene is treated...Ch. 18 - Draw the products of each reaction. a.d. b.e. c.f.Ch. 18 - You have learned two ways to make an alkyl...Ch. 18 - Prob. 18.42PCh. 18 - Prob. 18.43PCh. 18 - 18.45 Explain why each of the following reactions...Ch. 18 - Prob. 18.45PCh. 18 - 18.47 For each of the following substituted...Ch. 18 - Which benzene ring in each compound is more...Ch. 18 - 18.49 For each N-substituted benzene, predict...Ch. 18 - Explain each statement in detail using resonance...Ch. 18 - Prob. 18.50PCh. 18 - Explain why the meta product is formed in the...Ch. 18 - 18.53 Rank the aryl halides in each group in order...Ch. 18 - Prob. 18.53PCh. 18 - 18.54 Draw a stepwise mechanism for the following...Ch. 18 - Prob. 18.55PCh. 18 - 18.56 Draw a stepwise, detailed mechanism for the...Ch. 18 - Prob. 18.57PCh. 18 - 18.58 Draw a stepwise mechanism for the following...Ch. 18 - Draw a stepwise mechanism for the following...Ch. 18 - Prob. 18.60PCh. 18 - Draw a stepwise mechanism for the following...Ch. 18 - Prob. 18.62PCh. 18 - Prob. 18.63PCh. 18 - Synthesize each compound from benzene and any...Ch. 18 - Synthesize each compound from benzene and any...Ch. 18 - Synthesize each compound from toluene (C6H5CH3)...Ch. 18 - Prob. 18.67PCh. 18 - Use the reactions in this chapter along with those...Ch. 18 - Prob. 18.69PCh. 18 - Prob. 18.70PCh. 18 - Problem 18.69 Identify the structures of isomers A...Ch. 18 - Prob. 18.72PCh. 18 - Problem 18.71 Compound X (molecular formula ) was...Ch. 18 - Prob. 18.74PCh. 18 - The NMR spectrum of phenol () shows three...Ch. 18 - Explain the reactivity and orientation effects...Ch. 18 - Prob. 18.77PCh. 18 - Prob. 18.78PCh. 18 - Prob. 18.79PCh. 18 - Prob. 18.80P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- Compound H (C8H6O3) gives a precipitate when treated with hydroxylamine in aqueous ethanol and a silver mirror when treated with Tollens solution. Following is its 1H-NMR spectrum. Deduce the structure of compound H.arrow_forwardFollowing are 1H-NMR spectra for compounds G, H, and I, each with the molecular formula C5H12O. Each is a liquid at room temperature, is slightly soluble in water, and reacts with sodium metal with the evolution of a gas. (a) Propose structural formulas of compounds G, H, and I. (b) Explain why there are four lines between 0.86 and 0.90 for compound G. (c) Explain why the 2H multiplets at 1.5 and 3.5 for compound H are so complex.arrow_forwardPropose a structural formula for each compound consistent with its 1H-NMR and 13C-NMR spectra. (a) C5H10O2 (b) C7H14O2 (c) C6 H12O2 (d) C7H12O4 (e) C4H7ClO2 (f) C4H6O2arrow_forward
- Compound X (molecular formula C10H120) was treated with NH2NH2, ¯OH to yield compound Y (molecular formula C10H14). Match the 1H NMR spectra of X and Y to the corresponding structures of X and Y. Compound NH2NH2 Compound 'H NMR of X 6 H OH Y 1 H 5H 8. 6. 4 ppm or H NMR of Y 6 H 2H 5H 1 H multiplet multiplet 8. 6. 4. 3. 1 nnm 2. 2. 3, O:arrow_forwardWhat is the structure of a compound of molecular formula C1H1402 that shows a strong IR absorption at 3150-2850 cm1 and gives the following 'H NMR absorptions: 1.4 (triplet, 6 H), 4.0 (quartet, 4 H), and 6.8 (singlet, 4 H) ppm?arrow_forwardUsing the following NMR data, and the molecular formula C9H120, select the best compound. NMR Data triplet 1.15 ppm (3H) quartet 2.75 ppm (2H) singlet 3.75 ppm (3H) split quartet 7.5 ppm (4H) Multiple choice options A: 1-ethyl-4-methoxybenzene B: 1-ethoxy-4-methylbenzene C: 1-bromo-4-methylbenzene D: 1-bromo-4-ethylbenzenearrow_forward
- Compound X (molecular formula C10H12O) was treated with NH2NH2, −OH to yield compound Y (molecular formula C10H14). Based on the 1HNMR spectra of X and Y given below, what are the structures of X and Y?arrow_forwardThe compound with the closed formula C4H9Br gives the following 1H NMR data. Write the clear formula of the compound with reasons. 1.0 ppm (triplet, 3 H); 1.7 ppm (dublet, 3H); 1.8 ppm (multiplet, 2H); 4.2 ppm (multiplet, 1H)arrow_forwardDeduce the structure of an unknown compound using the data. C,H,O: 10 NMR: 8 9.8 (1 H, s), 8 1.1 (9 H, s)arrow_forward
- 8) CH3 CH3 O 36 Hu H CH3 CH3 Fo H H Answer the following questions, which refer to the two acetonide diastereomers shown above. a) Would you expect any difference in the number of peaks in the ¹H NMR spectra of each acetonide? (Y or N). b) Would you expect any difference in the number of peaks in the 13C NMR spectra of each acetonide? (Y or N) c) Would you expect any difference in the integral values for the peaks in the ¹H NMR spectra of each acetonide? (Y or N) d) Would you expect any difference in the multiplicities for the peaks in the ¹H NMR spectra of each acetonide? (Y or N). e) Would you expect any difference in the chemical shifts for the peaks in the ¹H NMR spectra of each acetonide? (Y or N)arrow_forwardCompound A has molecular formula C7H7X. Its ¹H-NMR spectrum shows a singlet at 2.26 ppm and two doublets, one at 6.95 ppm and one at 7.28 ppm. The singlet has an integral of three and the doublets each have an integral of two. Its 13C- NMR shows five signals. The mass spectrum of A shows a peak at m/z 170 and another peak at m/z = 172; the relative height of the two peaks is 1:1 respectively. - Identify what atom X is, explaining your reasoning - Identify Compound A, explaining your reasoning Compound A is treated with a mixture of nitric and sulfuric acids to generate Compound B. The ¹H-NMR spectrum of B shows two singlets, one at 2.52 pm and one at 8.13 ppm. The 13C-NMR spectrum of B shows five signals. The mass spectrum of B shows a peak at m/z = 260 and another peak at m/z = 262; the relative height of the two peaks is 1:1 respectively. - Identify compound B, explaining your reasoning Compound B is treated with sodium ethoxide to generate compound C. The ¹H-NMR spectrum of C shows…arrow_forwardWhat is the 1H NMR data (chemical shift, integration, multiplicty) of hte compound shown below?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning
Organic Chemistry
Chemistry
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:Cengage Learning
IR Spectroscopy; Author: Professor Dave Explains;https://www.youtube.com/watch?v=_TmevMf-Zgs;License: Standard YouTube License, CC-BY