Organic Chemistry
Organic Chemistry
4th Edition
ISBN: 9780073402772
Author: Janice G. Smith
Publisher: MCG
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Chapter 18, Problem 18.48P

For each N-substituted benzene, predict whether the compound reacts faster than, slower than, or at a similar rate to benzene in electrophilic aromatic substitution. Then draw the major product(s) formed when each compound reacts with a general electrophile E + .

a. Chapter 18, Problem 18.48P, 18.49 For each N-substituted benzene, predict whether the compound reacts faster than, slower than, , example  1 b. Chapter 18, Problem 18.48P, 18.49 For each N-substituted benzene, predict whether the compound reacts faster than, slower than, , example  2 c. Chapter 18, Problem 18.48P, 18.49 For each N-substituted benzene, predict whether the compound reacts faster than, slower than, , example  3 d. Chapter 18, Problem 18.48P, 18.49 For each N-substituted benzene, predict whether the compound reacts faster than, slower than, , example  4

Expert Solution
Check Mark
Interpretation Introduction

(a)

Interpretation: The given compound reacts faster than, slower than, or at equal rate to benzene in electrophilic aromatic substitution is to be predicted and the major product(s) formed by the reaction between given compound and general electrophile E+ is to be drawn.

Concept introduction: The replacement or substitution of one functional group with another different functional group in any chemical reaction is termed as substitution reaction. The electron deficient chemical species that contains positive charge are known as electrophile. In electrophilic aromatic substitution reaction, electrophile takes the position of hydrogen atom by attacking the electron rich carbon atom of benzene.

Answer to Problem 18.48P

The given compound reacts faster in electrophilic substitution reaction than benzene ring. The major product formed by the reaction between given compound and general electrophile E+ is shown below:

Organic Chemistry, Chapter 18, Problem 18.48P , additional homework tip  1

Explanation of Solution

The electron donating groups or activating groups make benzene ring more electron rich, as a result the compound reacts faster in electrophilic substitution reaction than benzene ring. On the other hand, the electron withdrawing groups or deactivating groups make benzene ring less electron rich; as a result the compound reacts slower in electrophilic substitution reaction than benzene ring.

In the given compound, benzene ring is attached to NR2 group, which is a strong electron donating group. Therefore, the given compound reacts faster in electrophilic substitution reaction than benzene ring.

The activating groups are ortho, para directing whereas the deactivating groups are meta directing. The major product formed by the reaction between given compound and general electrophile E+ is shown in Figure 1.

Organic Chemistry, Chapter 18, Problem 18.48P , additional homework tip  2

Figure 1

Conclusion

The given compound reacts faster in electrophilic substitution reaction than benzene ring. The major product formed by the reaction between given compound and general electrophile E+ is shown in Figure 1.

Expert Solution
Check Mark
Interpretation Introduction

(b)

Interpretation: The given compound reacts faster than, slower than, or at equal rate to benzene in electrophilic aromatic substitution is to be predicted and the major product(s) formed by the reaction between given compound and general electrophile E+ is to be drawn.

Concept introduction: The replacement or substitution of one functional group with another different functional group in any chemical reaction is termed as substitution reaction. The electron deficient chemical species that contains positive charge are known as electrophile. In electrophilic aromatic substitution reaction, electrophile takes the position of hydrogen atom by attacking the electron rich carbon atom of benzene.

Answer to Problem 18.48P

The given compound reacts slower in electrophilic substitution reaction than benzene ring. The major product formed by the reaction between given compound and general electrophile E+ is shown below:

Organic Chemistry, Chapter 18, Problem 18.48P , additional homework tip  3

Explanation of Solution

The electron donating groups or activating groups make benzene ring more electron rich, as a result the compound reacts faster in electrophilic substitution reaction than benzene ring. On the other hand, the electron withdrawing groups or deactivating groups make benzene ring less electron rich; as a result the compound reacts slower in electrophilic substitution reaction than benzene ring.

In the given compound, benzene ring is attached to N+H(CH3)2 group, which is a strong electron withdrawing group. Therefore, the given compound reacts slower in electrophilic substitution reaction than benzene ring.

The activating groups are ortho, para directing whereas the deactivating groups are meta directing. The major product formed by the reaction between given compound and general electrophile E+ is shown in Figure 2.

Organic Chemistry, Chapter 18, Problem 18.48P , additional homework tip  4

Figure 2

Conclusion

The given compound reacts slower in electrophilic substitution reaction than benzene ring. The major product formed by the reaction between given compound and general electrophile E+ is shown in Figure 2.

Expert Solution
Check Mark
Interpretation Introduction

(c)

Interpretation: The given compound reacts faster than, slower than, or at equal rate to benzene in electrophilic aromatic substitution is to be predicted and the major product(s) formed by the reaction between given compound and general electrophile E+ is to be drawn.

Concept introduction: The replacement or substitution of one functional group with another different functional group in any chemical reaction is termed as substitution reaction. The electron deficient chemical species that contains positive charge are known as electrophile. In electrophilic aromatic substitution reaction, electrophile takes the position of hydrogen atom by attacking the electron rich carbon atom of benzene.

Answer to Problem 18.48P

The given compound reacts slower in electrophilic substitution reaction than benzene ring. The major product formed by the reaction between given compound and general electrophile E+ is shown below:

Organic Chemistry, Chapter 18, Problem 18.48P , additional homework tip  5

Explanation of Solution

The electron donating groups or activating groups make benzene ring more electron rich, as a result the compound reacts faster in electrophilic substitution reaction than benzene ring. On the other hand, the electron withdrawing groups or deactivating groups make benzene ring less electron rich; as a result the compound reacts slower in electrophilic substitution reaction than benzene ring.

In the given compound, benzene ring is attached to NO2 and N+(CH3)3 groups. Both of these groups are strong electron withdrawing group. Therefore, the given compound reacts slower in electrophilic substitution reaction than benzene ring.

The activating groups are ortho, para directing whereas the deactivating groups are meta directing. The major product formed by the reaction between given compound and general electrophile E+ is shown in Figure 3.

Organic Chemistry, Chapter 18, Problem 18.48P , additional homework tip  6

Figure 3

Conclusion

The given compound reacts slower in electrophilic substitution reaction than benzene ring. The major product formed by the reaction between given compound and general electrophile E+ is shown in Figure 3.

Expert Solution
Check Mark
Interpretation Introduction

(d)

Interpretation: The given compound reacts faster than, slower than, or at equal rate to benzene in electrophilic aromatic substitution is to be predicted and the major product(s) formed by the reaction between given compound and general electrophile E+ is to be drawn.

Concept introduction: The replacement or substitution of one functional group with another different functional group in any chemical reaction is termed as substitution reaction. The electron deficient chemical species that contains positive charge are known as electrophile. In electrophilic aromatic substitution reaction, electrophile takes the position of hydrogen atom by attacking the electron rich carbon atom of benzene.

Answer to Problem 18.48P

The given compound reacts at a similar rate to benzene in electrophilic substitution reaction. The major product formed by the reaction between given compound and general electrophile E+ is shown below:

Organic Chemistry, Chapter 18, Problem 18.48P , additional homework tip  7

Explanation of Solution

The electron donating groups or activating groups make benzene ring more electron rich, as a result the compound reacts faster in electrophilic substitution reaction than benzene ring. On the other hand, the electron withdrawing groups or deactivating groups make benzene ring less electron rich; as a result the compound reacts slower in electrophilic substitution reaction than benzene ring.

In the given compound, benzene ring is attached to NR2 and NO2 groups. The NO2 group is a strong electron withdrawing group and NR2 group is a strong electron donating group. Therefore, the given compound reacts at a similar rate to benzene in electrophilic substitution reaction.

The activating groups are ortho, para directing whereas the deactivating groups are meta directing. The major product formed by the reaction between given compound and general electrophile E+ is shown in Figure 4.

Organic Chemistry, Chapter 18, Problem 18.48P , additional homework tip  8

Figure 4

Conclusion

The given compound reacts at a similar rate to benzene in electrophilic substitution reaction. The major product formed by the reaction between given compound and general electrophile E+ is shown in Figure 4.

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Chapter 18 Solutions

Organic Chemistry

Ch. 18 - Prob. 18.11PCh. 18 - Prob. 18.12PCh. 18 - Problem 18.14 Draw all resonance structures for...Ch. 18 - Classify each substituent as electron donating or...Ch. 18 - Prob. 18.15PCh. 18 - Label each compound as more or less reactive than...Ch. 18 - Rank the following compounds in order of...Ch. 18 - Problem 18.18 Rank the following compounds in...Ch. 18 - Prob. 18.19PCh. 18 - Problem 18.20 Draw the products of each...Ch. 18 - Prob. 18.21PCh. 18 - Prob. 18.22PCh. 18 - Devise a synthesis of each compound from the...Ch. 18 - Problem 18.24 Draw the products of each...Ch. 18 - Problem 18.25 Draw a stepwise mechanism for the...Ch. 18 - Problem 18.26 Draw the products of each...Ch. 18 - Prob. 18.27PCh. 18 - Prob. 18.28PCh. 18 - Problem 18.29 How could you use ethylbenzene to...Ch. 18 - Prob. 18.30PCh. 18 - Problem 18.31 What steps are needed to convert...Ch. 18 - Problem 18.32 Synthesize each compound from...Ch. 18 - Synthesize each compound from benzene.Ch. 18 - Prob. 18.34PCh. 18 - 18.35 What is the major product formed by an...Ch. 18 - Draw the products formed when phenol (C6H5OH) is...Ch. 18 - Prob. 18.37PCh. 18 - Draw the products of each reaction. a. e. i. b. f....Ch. 18 - What products are formed when benzene is treated...Ch. 18 - Draw the products of each reaction. a.d. b.e. c.f.Ch. 18 - You have learned two ways to make an alkyl...Ch. 18 - Prob. 18.42PCh. 18 - Prob. 18.43PCh. 18 - 18.45 Explain why each of the following reactions...Ch. 18 - Prob. 18.45PCh. 18 - 18.47 For each of the following substituted...Ch. 18 - Which benzene ring in each compound is more...Ch. 18 - 18.49 For each N-substituted benzene, predict...Ch. 18 - Explain each statement in detail using resonance...Ch. 18 - Prob. 18.50PCh. 18 - Explain why the meta product is formed in the...Ch. 18 - 18.53 Rank the aryl halides in each group in order...Ch. 18 - Prob. 18.53PCh. 18 - 18.54 Draw a stepwise mechanism for the following...Ch. 18 - Prob. 18.55PCh. 18 - 18.56 Draw a stepwise, detailed mechanism for the...Ch. 18 - Prob. 18.57PCh. 18 - 18.58 Draw a stepwise mechanism for the following...Ch. 18 - Draw a stepwise mechanism for the following...Ch. 18 - Prob. 18.60PCh. 18 - Draw a stepwise mechanism for the following...Ch. 18 - Prob. 18.62PCh. 18 - Prob. 18.63PCh. 18 - Synthesize each compound from benzene and any...Ch. 18 - Synthesize each compound from benzene and any...Ch. 18 - Synthesize each compound from toluene (C6H5CH3)...Ch. 18 - Prob. 18.67PCh. 18 - Use the reactions in this chapter along with those...Ch. 18 - Prob. 18.69PCh. 18 - Prob. 18.70PCh. 18 - Problem 18.69 Identify the structures of isomers A...Ch. 18 - Prob. 18.72PCh. 18 - Problem 18.71 Compound X (molecular formula ) was...Ch. 18 - Prob. 18.74PCh. 18 - The NMR spectrum of phenol () shows three...Ch. 18 - Explain the reactivity and orientation effects...Ch. 18 - Prob. 18.77PCh. 18 - Prob. 18.78PCh. 18 - Prob. 18.79PCh. 18 - Prob. 18.80P
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