Concept explainers
(a)
Interpretation: The number of carbons in
Concept introduction: Open chain structures of monosaccharides which contain five or more carbon atoms exist in equilibrium with two cyclic structures. These cyclic structures are the dominating forms at equilibrium. The carbonyl group in the open-chain structure of monosaccharide reacts intramolecularly with a hydroxyl group which results in the formation of cyclic forms. These cyclic compounds are called cyclic hemiacetals.
(b)
Interpretation: The number of carbons in
Concept introduction: Open chain structures of monosaccharides which contain five or more carbon atoms exist in equilibrium with two cyclic structures. These cyclic structures are the dominating forms at equilibrium. The carbonyl group in the open-chain structure of monosaccharide reacts intramolecularly with a hydroxyl group which results in the formation of cyclic forms. These cyclic compounds are called cyclic hemiacetals.
(c)
Interpretation: The number of carbons in
Concept introduction: Open chain structures of monosaccharides which contain five or more carbon atoms exist in equilibrium with two cyclic structures. These cyclic structures are the dominating forms at equilibrium. The carbonyl group in the open-chain structure of monosaccharide reacts intramolecularly with a hydroxyl group which results in the formation of cyclic forms. These cyclic compounds are called cyclic hemiacetals.
(d)
Interpretation: The number of carbons in
Concept introduction: Open chain structures of monosaccharides which contain five or more carbon atoms exist in equilibrium with two cyclic structures. These cyclic structures are the dominating forms at equilibrium. The carbonyl group in the open-chain structure of monosaccharide reacts intramolecularly with a hydroxyl group which results in the formation of cyclic forms. These cyclic compounds are called cyclic hemiacetals.
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Chapter 18 Solutions
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- Following are Fischer projections for a group of five-carbon sugars, all of which are aldopentoses. Identify the pairs that are enantiomers and the pairs that are epimers. (The sugars shown here are not all of the possible five-carbon sugars.) 1 СНО 2 СНО СНО Н-С—ОН Н-С—ОН Н—С—ОН Н-С—ОН НО —С—Н Н-С—ОН Н- С—ОН НО—С— Н НО—С—Н CH̟OH CH̟OH ČH̟OH в iоchemistry |61 STATE ATION Republic of the Philippines Romblon State University Romblan, Philippines 4 СНО 5 СНО 6 СНО НО—С—Н Н-С—ОН НО -С—Н Н—С—ОН НО -С—Н НО -С—Н H-C–OH Н-С—ОН НО—С—Н CH,OH ČH,OH CH,OHarrow_forwardDraw the two possible Haworth structures (both alpha and beta anomers) for the following monosaccharides and give their corresponding systematic names. [Show the stepwise process] (a) D- Fructosearrow_forwardFollowing are Fischer projections for a groupof five-carbon sugars, all of which are aldopentoses. Identify thepairs that are enantiomers and the pairs that are epimers. (Thesugars shown here are not all of the possible five-carbon sugars.)arrow_forward
- Following are Fischer projections for a group of five-carbon sugars, all of which are aldopentoses. Identify the pairs that are enantiomers and the pairs that are epimers СНО СНО СНО H-C-OH H-C-OH H-C-OH H-C-OH Но-С—н H-C-OH H-C-OH Но-ҫ—н Но—с—н CHOH CHĻOH ČH,OH СНО СНО СНО Но —С— н H-C-OH HO-C-H Н—С—он Но -С—н HO-C-H H-c-OH H-C-OH HO-C-H CH̟OH ČHĻOH ČHĻOH Pairs of Enantiomers Pairs of Epimersarrow_forwardFollowing are Fischer projections for a group of five-carbon sugars, all of which are aldopentoses. Identify the pairs that are enantiomers. CHO сно H-C- OH H-C-OH H-C- OH но-с — н н-с—он но- ČHOH ČH,OH сно CHO Н-с—он но—с— н H-C- OH H-C-OH но—с—н Н-с—он ČHOH ČH,OH сно сно н-с—он но—с —н но—с— н но -с — н H-C- OH но- C-H ČH,OH ČH,OHarrow_forwardThe monosaccharide shown below is the CH₂OH OH OH beta- L- D- alpha- Он OH anomer.arrow_forward
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