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Concept explainers
(a)
Interpretation: The classification of the given
Concept introduction: The simplest hydrolyzed form that is obtained from the carbohydrates is known as monosaccharide. Monosaccharide is categorized into two types. The first type of monosaccharide is aldoses and the second type of monosaccharide is ketoses. Aldoses sugar possesses
Monosaccharides are also classified on the basis of the number of carbon atoms present in it. For example, the sugar that contains five carbon atoms is known as pentoses sugar and the sugar that contains six carbon atoms is known as hexoses sugar.
(b)
Interpretation: The classification of the given
Concept introduction: The simplest hydrolyzed form that is obtained from the carbohydrates is known as monosaccharide. Monosaccharide is categorized into two types. The first type of monosaccharide is aldoses and the second type of monosaccharide is ketoses. Aldoses sugar possesses aldehyde as a functional group and the ketoses sugar possesses ketone as a functional group.
Monosaccharides are also classified on the basis of the number of carbon atoms present in it. For example, the sugar that contains five carbon atoms is known as pentoses sugar and the sugar that contains six carbon atoms is known as hexoses sugar.
(c)
Interpretation: The classification of the given
Concept introduction: The simplest hydrolyzed form that is obtained from the carbohydrates is known as monosaccharide. Monosaccharide is categorized into two types. The first type of monosaccharide is aldoses and the second type of monosaccharide is ketoses. Aldoses sugar possesses aldehyde as a functional group and the ketoses sugar possesses ketone as a functional group.
Monosaccharides are also classified on the basis of the number of carbon atoms present in it. For example, the sugar that contains five carbon atoms is known as pentoses sugar and the sugar that contains six carbon atoms is known as hexoses sugar.
(d)
Interpretation: The classification of the given
Concept introduction: The simplest hydrolyzed form that is obtained from the carbohydrates is known as monosaccharide. Monosaccharide is categorized into two types. The first type of monosaccharide is aldoses and the second type of monosaccharide is ketoses. Aldoses sugar possesses aldehyde as a functional group and the ketoses sugar possesses ketone as a functional group.
Monosaccharides are also classified on the basis of the number of carbon atoms present in it. For example, the sugar that contains five carbon atoms is known as pentoses sugar and the sugar that contains six carbon atoms is known as hexoses sugar.
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Chapter 18 Solutions
Bundle: General, Organic, and Biological Chemistry, 7th + OWLv2 Quick Prep for General Chemistry, 4 terms (24 months) Printed Access Card
- please helparrow_forwardPredict the products of the following reactions. Draw mechanism arrows for each step for a, b, and c. a.) HBr b.) HI H₂O H2SO4 d.) C12 HO H2SO4 1.) BH3 2.) H2O2, NaOHarrow_forwardK for the following reaction is 0.11 at constant temperature. If the equilibrium concentration of HCl is 0.5 M, what is the equilibrium concentration of NH3. NH4CI(s) ⇌ NH3(g) + HCI(g)arrow_forward
- please help by Draw the following structures (Lewis or line-angle drawing).arrow_forwardplease helparrow_forwardConsider the reaction: 2 A (aq) ⇌ B(aq) Given the following KC values and starting with the initial concentration of A = 4.00 M, complete ICE diagram(s)and find the equilibrium concentrations for A and B.A) KC = 4.00B) KC = 200C) KC = 8.00 x10-3arrow_forward
- 5) Consider the reaction: Cl2 (g) + F2 (g) ⟷ 2 ClF (g) KP=? The partial pressure of 203 kPa for Cl2 and a partial pressure of 405 kPa for F2. Upon reaching equilibrium, thepartial pressure of ClF is 180 kPa. Calculate the equilibrium concentrations and then find the value for KP.arrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forward(9 Pts) In one of the two Rare Earth element rows of the periodic table, identify an exception tothe general ionization energy (IE) trend. For the two elements involved, answer the followingquestions. Be sure to cite sources for all physical data that you use.a. (2 pts) Identify the two elements and write their electronic configurations.b. (2 pts) Based on their configurations, propose a reason for the IE trend exception.c. (5 pts) Calculate effective nuclear charges for the last electron in each element and theAllred-Rochow electronegativity values for the two elements. Can any of these valuesexplain the IE trend exception? Explain how (not) – include a description of how IErelates to electronegativity.arrow_forward
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