Chapter 18, Problem 18.51AP

(a)

Interpretation Introduction

Interpretation:

Chemical equation for conversion of $\text{fructose}\text{1,6-biphosphate}$ to $\text{fructose}\text{6-phosphate}$ has to be written.

Concept Introduction:

Nucleotide is defined as basic unit for formation of nucleic acid that is essential for completion of metabolic reactions in body. The three basic components of nucleotide are as follows:

1. Nitrogen-containing base

2. Pentose sugar

3. Phosphate group

Examples of nucleosides are GTP and ATP. Nucleotide on hydrolysis releases energy by cleavage of phosphoanhydride bond. The reaction of hydrolysis of ATP is as follows:

  $\text{ATP}+{\text{H}}_2\text{O}\to \text{ADP}+{\text{P}}_{\text{i}}+\text{energy}$

(b)

Interpretation Introduction

Interpretation:

Whether energy is released or absorbed in formation of $\text{fructose}\text{6-phosphate}$ by $\text{fructose}\text{1,6-biphosphate}$ has to be determined.

Concept Introduction:

Refer to part (a).

(c)

Interpretation Introduction

Interpretation:

Whether reaction is energetically favorable or not in formation of $\text{fructose}\text{6-phosphate}$ by $\text{fructose}\text{1,6-biphosphate}$ has to be determined.

Concept Introduction:

Refer to part (a).