Concept explainers
a.
Interpretation:
Stage of catabolism in that cleavage of protein with chymotrypsin has to be determined.
Concept Introduction:
Catabolic pathways are organized in four stages as follows:
Digestion is the first stage for energy production. In this stage, food molecules like carbohydrates, proteins, and triacylglycerols break down into smaller units by hydrolysis. These units are utilized in further stages of energy and also consumed by body in
Acetyl CoA formation is the second stage for energy production. In this stage, monosaccharides, amino acids, and fatty acids are reduced to form two-carbon units. This two carbon unit is bonded to coenzyme A to form acetyl CoA.
Citric acid cycle is the third stage for energy production. In this stage, acetyl CoA is oxidized to form
Electron transport chain and oxidative phosphorylation is the fourth stage for energy production. In this stage,
a.

Explanation of Solution
Chymotrypsin is enzyme that known to break protein into individual amino acids. It is used in small intestine. It functions to target only
Since chymotrypsin breaks long protein into smaller amino acid molecules thus it occurs in stage (1).
b.
Interpretation:
Stage of catabolism in that oxidation of fatty acid to acetyl CoA has to be determined.
Concept Introduction:
Refer to part a.
b.

Explanation of Solution
Long fatty acid reduced to two-carbon unit that is acetyl CoA in stage (2) of catabolism. This stage converts monosaccharides, amino acids, and fatty acids into acetyl CoA.
c.
Interpretation:
Stage of catabolism in that oxidation of malate to oxaloacetate with
Concept Introduction:
Refer to part a.
c.

Explanation of Solution
Conversion of malate to oxaloacetate is taken place in citric acid cycle. Citric acid cycle is part of stage (3) of catabolism. Thus oxidation of malate to oxaloacetate with
d.
Interpretation:
Stage of catabolism in that conversion of ADP to ATP with ATP synthase has to be determined.
Concept Introduction:
Refer to part a.
d.

Explanation of Solution
Conversion of ADP to ATP with ATP synthase is taken place in electron transport chain. In electron transport chain,
e.
Interpretation:
Stage of catabolism in that hydrolysis of starch to glucose with amylase has to be determined.
Concept Introduction:
Refer to part a.
e.

Explanation of Solution
Conversion of starch to glucose with amylase is a conversion of polysaccharides to small unit of monosaccharides. Since large molecule broken into small molecule comes under stage (1) of catabolism thus hydrolysis of starch to glucose with amylase occurs in stage (1) of catabolism.
Want to see more full solutions like this?
Chapter 18 Solutions
PRIN.OF GENERAL,ORGANIC+BIOLOG.CHEM.
- OH 1. NaOCH2CH3 Q 2. CH3CH2Br (1 equiv) H3O+ Select to Draw 1. NaOCH2 CH3 2. CH3Br (1 equiv) heat Select to Edit Select to Drawarrow_forwardComplete and balance the following half-reaction in acidic solution. Be sure to include the proper phases for all species within the reaction. S₂O₃²⁻(aq) → S₄O₆²⁻(aq)arrow_forwardQ Select to Edit NH3 (CH3)2CHCI (1 equiv) AICI 3 Select to Draw cat. H2SO4 SO3 (1 equiv) HO SOCl2 pyridine Select to Edit >arrow_forward
- Complete and balance the following half-reaction in basic solution. Be sure to include the proper phases for all species within the reaction. Zn(s) → Zn(OH)₄²⁻(aq)arrow_forwardb. ὋΗ CH3CH2OH H2SO4arrow_forwardFor the reaction A (g) → 3 B (g), Kp = 0.379 at 298 K. What is the value of ∆G for this reaction at 298 K when the partial pressures of A and B are 5.70 atm and 0.250 atm?arrow_forward
- 14. Calculate the concentrations of Ag+, Ag(S2O3), and Ag(S2O3)23- in a solution prepared by mixing 150.0 mL of 1.00×10-3 M AgNO3 with 200.0 mL of 5.00 M Na2S2O3 Ag+ + S20 Ag(S203)¯ K₁ = 7.4 × 108 Ag(S203)¯ + S20¯ = Ag(S203) K₂ = 3.9 x 104arrow_forwardΗΝ, cyclohexanone pH 4-5 Draw Enamine I I CH3CH2Br THF, reflux H3O+ I Drawing Draw Iminium Ionarrow_forward:0: :0: Select to Add Arrows :0: (CH3)2NH :0: ■ Select to Add Arrows :0: :0: (CH3)2NH ■ Select to Add Arrowsarrow_forward
- Draw the product of the following H action sequence. Ignore any inorganic byproducts formed. 1. (CH3CH2)2CuLi, THF 2. CH3Br Q Atoms, Bonds and Rings H Charges ㅁarrow_forwardPlease help me with this the problem is so confusingarrow_forward14 Question (1 point) Disiamylborane adds to a triple bond to give an alkenylborane. Upon oxidation with OH, H2O2, the alkenylborane will form an enol that tautomerizes to an aldehyde. In the first box below, draw the mechanism arrows for the reaction of disiamylborane with the alkyne, and in the last box draw the structure of the aldehyde. 4th attempt Feedback i > 3rd attempt OH, H2O2 i See Periodic Table See Hintarrow_forward
- General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage LearningOrganic And Biological ChemistryChemistryISBN:9781305081079Author:STOKER, H. Stephen (howard Stephen)Publisher:Cengage Learning,Introduction to General, Organic and BiochemistryChemistryISBN:9781285869759Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar TorresPublisher:Cengage Learning
- Chemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage LearningChemistry In FocusChemistryISBN:9781305084476Author:Tro, Nivaldo J., Neu, Don.Publisher:Cengage Learning





