Chapter 18, Problem 18.137MP

Interpretation Introduction

(a)

Interpretation:

The partial pressure of ${\text{SO}}_{\text{3}},{\text{ SO}}_{\text{2}}$ and ${\text{O}}_{\text{2}}$ needs to be determined at equilibrium.

Concept introduction:

The number of moles of gas can be calculated from mass and molar mass as follows:

$n=\frac{m}{M}$

Here, m is mass and M is molar mass

The ideal gas equation is represented as follows:

$PV=nRT$

Also, molarity of solution is represented as follows:

$M=\frac{n}{V}$

Thus, above ideal equation can be rewritten as follows:

$P=MRT$

Here, P is pressure, M is molarity, R is Universal gas constant and T is temperature.

Interpretation Introduction

(b)

Interpretation:

Whether the percent yield of ${\text{SO}}_{\text{3}}$ increases or decreases due to increase in temperature from 800 K to 1000 K needs to be determined.

Concept introduction:

The number of moles of gas can be calculated from mass and molar mass as follows:

$n=\frac{m}{M}$

Here, m is mass and M is molar mass

The ideal gas equation is represented as follows:

$PV=nRT$

Here, P is pressure, V is volume, n is number of moles, R is Universal gas constant and T is temperature.

Interpretation Introduction

(c)

Interpretation:

Whether the total pressure increases or decreases when temperature increases from 800 K to 1000 K. The total pressure at 1000 K needs to be calculated.

Concept introduction:

The number of moles of gas can be calculated from mass and molar mass as follows:

$n=\frac{m}{M}$

Here, m is mass and M is molar mass

The ideal gas equation is represented as follows:

$PV=nRT$

Here, P is pressure, V is volume, n is number of moles, R is Universal gas constant and T is temperature.