All the resonance forms for the sigma complexes that correspond to bromination of aniline at the ortho, meta and para positions are to be drawn. Concept introduction: Nitrogen atom of − NH 2 group in aniline contains a nonbonding pair of electrons. It is a strong activating group. It makes the aromatic ring more electron rich as compared to anisole. The sigma complex formed during the electrophilic substitution reaction is resonance stablised due to non bonding electrons of nitrogen. Aniline give ortho and para substituted products. To determine: All the resonance forms for the sigma complexes that correspond to bromination of aniline at the ortho, meta and para positions.

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8:57 PM Sun Jan 26 Content ← Explanation Page X Content X ALEKS Jade Nicol - Le A https://www-av C www-awa.aleks.com O States of Matter Understanding consequences of important physical properties of liquids ? QUESTION Liquid A is known to have a lower viscosity and lower surface tension than Liquid B. Use these facts to predict the result of each experiment in the table below, if you can. experiment Liquid A and Liquid B are each pumped through tubes with an inside diameter of 27.0 mm, and the pressures PA and PB needed to produce a steady flow of 2.4 mL/s are measured. 25.0 mL of Liquid A are poured into a beaker, and 25.0 mL of Liquid B are poured into an identical beaker. Stirrers in each beaker are connected to motors, and the forces FA and FB needed to stir each liquid at a constant rate are measured. predicted outcome OPA will be greater than PB OPA will be less than PB OPA will be equal to PB It's impossible to predict whether PA or PB will be greater without more information.…

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Chapter 17.6B, Problem 17.8P

Interpretation Introduction

Interpretation: All the resonance forms for the sigma complexes that correspond to bromination of aniline at the ortho, meta and para positions are to be drawn.

Concept introduction: Nitrogen atom of −NH2 group in aniline contains a nonbonding pair of electrons. It is a strong activating group. It makes the aromatic ring more electron rich as compared to anisole. The sigma complex formed during the electrophilic substitution reaction is resonance stablised due to non bonding electrons of nitrogen. Aniline give ortho and para substituted products.

To determine: All the resonance forms for the sigma complexes that correspond to bromination of aniline at the ortho, meta and para positions.

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8:57 PM Sun Jan 26 Content ← Explanation Page X Content X ALEKS Jade Nicol - Le A https://www-av C www-awa.aleks.com O States of Matter Understanding consequences of important physical properties of liquids ? QUESTION Liquid A is known to have a lower viscosity and lower surface tension than Liquid B. Use these facts to predict the result of each experiment in the table below, if you can. experiment Liquid A and Liquid B are each pumped through tubes with an inside diameter of 27.0 mm, and the pressures PA and PB needed to produce a steady flow of 2.4 mL/s are measured. 25.0 mL of Liquid A are poured into a beaker, and 25.0 mL of Liquid B are poured into an identical beaker. Stirrers in each beaker are connected to motors, and the forces FA and FB needed to stir each liquid at a constant rate are measured. predicted outcome OPA will be greater than PB OPA will be less than PB OPA will be equal to PB It's impossible to predict whether PA or PB will be greater without more information.…

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5. Please draw in the blanks the missing transition states and the correlated products. Explicitly display relevant absolute stereochemical configuration. MeOH I OMe H Endo transition state, dienophile approaching from the bottom of diene + H ཎྞཾ ཌཱརཱ༔,_o OMe H H OMe Endo transition state, dienophile approaching from the top of diene or from the bottom but horizontally flipped (draw one) + Exo transition state, dienophile approaching from the top of diene or from the bottom but horizontally flipped (draw one) Exo transition state, dienophile approaching from the top of diene or from the bottom but horizontally flipped (draw one) MeO H H MeO H MeO H MeO H H