CHEMISTRY  MOLECULAR NATURE OF MATTER
CHEMISTRY MOLECULAR NATURE OF MATTER
9th Edition
ISBN: 9781266177835
Author: SILBERBERG
Publisher: MCG
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Chapter 17.6, Problem B17.1P

(a)

Interpretation Introduction

Interpretation:

The enzyme inhibited by F has to be mentioned.

Concept Introduction:

Enzymes are biological catalysts. Enzyme binds the substrate to its active site and enhances the rate of reaction. In addition to active site enzyme also contains an inhibitor site where an inhibitor can bind and deform the shape of active site. When the shape of active site got changed, substrate can no longer bind with enzyme so the catalytic activity stops.

For regulating the metabolic activities in order to prevent the excess product formation in the cell, the final product of a pathway act as an inhibitor and stops the catalytic activity of the regulatory enzyme in the first step.

(b)

Interpretation Introduction

Interpretation:

The enzyme that is inhibited by I has to be mentioned.

Concept Introduction:

Enzymes are biological catalysts. Enzyme binds the substrate to its active site and enhances the rate of reaction. In addition to active site enzyme also contains an inhibitor site where an inhibitor can bind and deform the shape of active site. When the shape of active site got changed, substrate can no longer bind with enzyme so the catalytic activity stops.

For regulating the metabolic activities in order to prevent the excess product formation in the cell, the final product of a pathway act as an inhibitor and stops the catalytic activity of the regulatory enzyme in the first step.

(c)

Interpretation Introduction

Interpretation:

Disadvantage of inhibiting enzyme 1 by F has to be explained.

Concept Introduction:

Enzymes are biological catalysts. Enzyme binds the substrate to its active site and enhances the rate of reaction. In addition to active site enzyme also contains an inhibitor site where an inhibitor can bind and deform the shape of active site. When the shape of active site got changed, substrate can no longer bind with enzyme so the catalytic activity stops.

For regulating the metabolic activities in order to prevent the excess product formation in the cell, the final product of a pathway act as an inhibitor and stops the catalytic activity of the regulatory enzyme in the first step.

(d)

Interpretation Introduction

Interpretation:

Disadvantage of inhibiting enzyme 6 by F has to be explained.

Concept Introduction:

Enzymes are biological catalysts. Enzyme binds the substrate to its active site and enhances the rate of reaction. In addition to active site enzyme also contains an inhibitor site where an inhibitor can bind and deform the shape of active site. When the shape of active site got changed, substrate can no longer bind with enzyme so the catalytic activity stops.

For regulating the metabolic activities in order to prevent the excess product formation in the cell, the final product of a pathway act as an inhibitor and stops the catalytic activity of the regulatory enzyme in the first step.

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6. Consider the following exothermic reaction below. 2Cu2+(aq) +41 (aq)2Cul(s) + 12(aq) a. If Cul is added, there will be a shift left/shift right/no shift (circle one). b. If Cu2+ is added, there will be a shift left/shift right/no shift (circle one). c. If a solution of AgNO3 is added, there will be a shift left/shift right/no shift (circle one). d. If the solvent hexane (C6H14) is added, there will be a shift left/shift right/no shift (circle one). Hint: one of the reaction species is more soluble in hexane than in water. e. If the reaction is cooled, there will be a shift left/shift right/no shift (circle one). f. Which of the changes above will change the equilibrium constant, K?
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Chapter 17 Solutions

CHEMISTRY MOLECULAR NATURE OF MATTER

Ch. 17.5 - Prob. 17.6AFPCh. 17.5 - Prob. 17.6BFPCh. 17.5 - Prob. 17.7AFPCh. 17.5 - Prob. 17.7BFPCh. 17.5 - Prob. 17.8AFPCh. 17.5 - Prob. 17.8BFPCh. 17.5 - Prob. 17.9AFPCh. 17.5 - Prob. 17.9BFPCh. 17.5 - An inorganic chemist studying the reactions of...Ch. 17.5 - Prob. 17.10BFPCh. 17.6 - In a study of glass etching, a chemist examines...Ch. 17.6 - Prob. 17.11BFPCh. 17.6 - Prob. 17.12AFPCh. 17.6 - Prob. 17.12BFPCh. 17.6 - Prob. 17.13AFPCh. 17.6 - Should T be increased or decreased to yield more...Ch. 17.6 - Prob. 17.14AFPCh. 17.6 - Prob. 17.14BFPCh. 17.6 - Prob. 17.15AFPCh. 17.6 - Prob. 17.15BFPCh. 17.6 - Many metabolites are products in branched...Ch. 17 - Prob. 17.1PCh. 17 - When a chemical company employs a new reaction to...Ch. 17 - If there is no change in concentrations, why is...Ch. 17 - Prob. 17.4PCh. 17 - Prob. 17.5PCh. 17 - Prob. 17.6PCh. 17 - Prob. 17.7PCh. 17 - Prob. 17.8PCh. 17 - Prob. 17.9PCh. 17 - Does Q for the formation of 1 mol of NO from its...Ch. 17 - Does Q for the formation of 1 mol of NH3 from H2...Ch. 17 - Balance each reaction and write its reaction...Ch. 17 - Prob. 17.13PCh. 17 - Prob. 17.14PCh. 17 - Prob. 17.15PCh. 17 - Balance each of the following examples of...Ch. 17 - Balance each of the following examples of...Ch. 17 - Balance each of the following examples of...Ch. 17 - Balance each of the following examples of...Ch. 17 - Prob. 17.20PCh. 17 - Prob. 17.21PCh. 17 - Prob. 17.22PCh. 17 - Prob. 17.23PCh. 17 - Prob. 17.24PCh. 17 - Prob. 17.25PCh. 17 - When are Kc and Kp equal, and when are they not? Ch. 17 - A certain reaction at equilibrium has more moles...Ch. 17 - Prob. 17.28PCh. 17 - Determine Δngas for each of the following...Ch. 17 - Prob. 17.30PCh. 17 - Prob. 17.31PCh. 17 - Prob. 17.32PCh. 17 - Prob. 17.33PCh. 17 - Prob. 17.34PCh. 17 - The following molecular scenes depict the aqueous...Ch. 17 - At 425°C, Kp = 4.18 × 10−9 for the...Ch. 17 - At 100°C, Kp = 60.6 for the reaction 2NOBr(g) ⇌...Ch. 17 - The water-gas shift reaction plays a central role...Ch. 17 - In the 1980s, CFC-11 was one of the most heavily...Ch. 17 - For a problem involving the catalyzed reaction of...Ch. 17 - What is the basis of the approximation that avoids...Ch. 17 - Prob. 17.42PCh. 17 - Gaseous ammonia was introduced into a sealed...Ch. 17 - Prob. 17.44PCh. 17 - Prob. 17.45PCh. 17 - Prob. 17.46PCh. 17 - Prob. 17.47PCh. 17 - Prob. 17.48PCh. 17 - Prob. 17.49PCh. 17 - Prob. 17.50PCh. 17 - Nitrogen dioxide decomposes according to the...Ch. 17 - Hydrogen iodide decomposes according to the...Ch. 17 - Compound A decomposes according to the...Ch. 17 - Prob. 17.54PCh. 17 - Prob. 17.55PCh. 17 - Prob. 17.56PCh. 17 - A toxicologist studying mustard gas, S(CH2CH2Cl)2,...Ch. 17 - Prob. 17.58PCh. 17 - A key step in the extraction of iron from its ore...Ch. 17 - What does “disturbance” mean in Le Châtelier’s...Ch. 17 - Prob. 17.61PCh. 17 - Prob. 17.62PCh. 17 - Prob. 17.63PCh. 17 - Le Châtelier’s principle is related ultimately to...Ch. 17 - An equilibrium mixture of two solids and a gas, in...Ch. 17 - Consider this equilibrium system: CO(g) + Fe3O4(s)...Ch. 17 - Sodium bicarbonate undergoes thermal decomposition...Ch. 17 - Prob. 17.68PCh. 17 - Prob. 17.69PCh. 17 - Predict the effect of decreasing the container...Ch. 17 - Prob. 17.71PCh. 17 - Prob. 17.72PCh. 17 - Prob. 17.73PCh. 17 - Prob. 17.74PCh. 17 - Prob. 17.75PCh. 17 - Prob. 17.76PCh. 17 - The formation of methanol is important to the...Ch. 17 - Prob. 17.78PCh. 17 - The oxidation of SO2 is the key step in H2SO4...Ch. 17 - A mixture of 3.00 volumes of H2 and 1.00 volume of...Ch. 17 - You are a member of a research team of chemists...Ch. 17 - For the following equilibrium system, which of the...Ch. 17 - Prob. 17.83PCh. 17 - Prob. 17.84PCh. 17 - Prob. 17.85PCh. 17 - Prob. 17.86PCh. 17 - Prob. 17.87PCh. 17 - Prob. 17.88PCh. 17 - Prob. 17.89PCh. 17 - Prob. 17.90PCh. 17 - When 0.100 mol of CaCO3(s) and 0.100 mol of CaO(s)...Ch. 17 - Prob. 17.92PCh. 17 - Prob. 17.93PCh. 17 - Prob. 17.94PCh. 17 - Highly toxic disulfur decafluoride decomposes by a...Ch. 17 - A study of the water-gas shift reaction (see...Ch. 17 - Prob. 17.97PCh. 17 - Prob. 17.98PCh. 17 - Prob. 17.99PCh. 17 - Prob. 17.100PCh. 17 - Prob. 17.101PCh. 17 - Prob. 17.102PCh. 17 - The molecular scenes below depict the reaction Y ⇌...Ch. 17 - For the equilibrium H2S(g) ⇌ 2H2(g) + S2(g) Kc =...Ch. 17 - Prob. 17.105PCh. 17 - Prob. 17.106PCh. 17 - The kinetics and equilibrium of the decomposition...Ch. 17 - Isopentyl alcohol reacts with pure acetic acid to...Ch. 17 - Isomers Q (blue) and R (yellow) interconvert. They...Ch. 17 - Glauber’s salt, Na2SO4·10H2O, was used by J. R....Ch. 17 - Prob. 17.111PCh. 17 - Synthetic diamonds are made under conditions of...
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