Chapter 17, Problem 17.78P

(a)

Interpretation Introduction

Interpretation:

The given reaction is

  ${\text{4Fe}}_{\text{3}}{\text{O}}_{\text{4}}{\text{(s) + O}}_{\text{2}}\text{(g)}\rightleftharpoons {\text{6Fe}}_{\text{2}}{\text{O}}_{\text{3}}\text{(s)}{\text{K}}_{\text{p}}\text{=2}{\text{.5×10}}^{\text{87}}\text{ at 298 K}$

${\text{P}}_{{\text{O}}_{\text{2}}}$ has to be calculated at equilibrium.

(b)

Interpretation Introduction

Interpretation:

The given reaction is

  ${\text{4Fe}}_{\text{3}}{\text{O}}_{\text{4}}{\text{(s) + O}}_{\text{2}}\text{(g)}\rightleftharpoons {\text{6Fe}}_{\text{2}}{\text{O}}_{\text{3}}\text{(s)}{\text{K}}_{\text{p}}\text{=2}{\text{.5×10}}^{\text{87}}\text{ at 298 K}$

${\text{P}}_{{\text{O}}_{\text{2}}}$ in air is $\text{0}\text{.21 atm}$, to reach equilibrium, in which direction the reaction will proceed has to be given.

(c)

Interpretation Introduction

Interpretation:

The given reaction is

  ${\text{4Fe}}_{\text{3}}{\text{O}}_{\text{4}}{\text{(s) + O}}_{\text{2}}\text{(g)}\rightleftharpoons {\text{6Fe}}_{\text{2}}{\text{O}}_{\text{3}}\text{(s)}{\text{K}}_{\text{p}}\text{=2}{\text{.5×10}}^{\text{87}}\text{ at 298 K}$

${\text{K}}_{\text{c}}\text{ at 298 K}$ has to be calculated.