Chapter 17.5, Problem 17.7AFP

Interpretation Introduction

Interpretation : The equilibrium partial pressure of ${\text{H}}_{\text{2}}\text{S}$ should be calculated for the decomposition of hydrogen sulfide if the $K_c$ of reaction is $\text{2}\text{.25 }\times {\text{ 10}}^{\text{-4}}$ at $1130°C$ and ${\text{P}}_{{\text{H}}_{\text{2}}}\text{ = 0}\text{.370 atm}$ , ${\text{P}}_{{\text{S}}_{\text{2}}}\text{ = 0}\text{.185 atm}$ .

Concept Introduction : ${\text{K}}_{\text{p}}$ or $\text{Kc}$ are the equilibrium constants for the reaction which are ratio of gaseous and aqueous products and reactant molecules.

  $\text{A + B }\rightleftharpoons \text{C + D }$

  $K=Kc=\frac{[aC][aD]}{[aA][aB]}$

  $K=Kp=\frac{[PC][PD]}{[PA][PB]}$

Here ‘a’ represent the active mass and ‘P’ represents the partial pressure.