Explanation Given: Surface S represented by the parametric curve G ( u , v ) = ( ( 1 + v cos u 2 ) cos u , ( 1 + v cos u 2 ) sin u , v sin u 2 ) ; 0 ≤ u ≤ 2 π , − 1 2 ≤ v ≤ 1 2 N ( u , 0 ) = ( cos u sin u 2 , sin u sin u 2 , − cos u 2 ) is a unit vector that varies continuously but that N ( 2 π , 0 ) = − N ( 0 , 0 ) shows that the surface S is not orientable. Proof: Here the Surface represented by the parametric curve G ( u , v ) = ( ( 1 + v cos u 2 ) cos u , ( 1 + v cos u 2 ) sin u , v sin u 2 ) ; 0 ≤ u ≤ 2 π , − 1 2 ≤ v ≤ 1 2 in the form of frustum of cone and thereby the lower part of the surface would be circle, i.e., cross sectional part of the bottom of the solid would be a circle. In the parametric curve G ( u , v ) = ( ( 1 + v cos u 2 ) cos u , ( 1 + v cos u 2 ) sin u , v sin u 2 ) ; 0 ≤ u ≤ 2 π , − 1 2 ≤ v ≤ 1 2 The x , y and z components are x = ( 1 + v cos u 2 ) cos u = cos u + v cos u cos u 2 y = ( 1 + v cos u 2 ) sin u = sin u + v cos u 2 sin u z = v sin u 2 where, 0 ≤ u ≤ 2 π , − 1 2 ≤ v ≤ 1 2 Now for xy -plane z = 0 ⇒ v sin u 2 = 0 ⇒ v = 0 or sin u 2 = 0 ⇒ v = 0 or u 2 = n π ⇒ v = 0 or u = 2 n π Now, u = 2 n π ⇒ u = 2 π , 4 π , .. , 2 n π Since, 0 ≤ u ≤ 2 π , − 1 2 ≤ v ≤ 1 2 ⇒ u ≠ 2 n π ⇒ v = 0 Now, for v = 0, the equation of surface becomes G ( u , 0 ) = ( ( 1 + 0 × cos u 2 ) cos u , ( 1 + 0 × cos u 2 ) sin u , 0 × sin u 2 ) ⇒ G ( u , 0 ) = ( cos u , sin u , 0 ) Also, ‖ G ( u , 0 ) ‖ = ‖ ( cos u , sin u , 0 ) ‖ = cos 2 u + sin 2 u + 0 = 1 Thus, the intersection of the surface S with the xy -plane is the unit circle given by G ( u , 0 ) = ( cos u , sin u , 0 ) . Now, we need to determine the vector normal to the surface which is given by n → = ∂ ∂ u ( G ( u , v ) ) × ∂ ∂ v ( G ( u , v ) ) ⇒ n → = ∂ ∂ u ( ( ( 1 + v cos u 2 ) cos u , ( 1 + v cos u 2 ) sin u , v sin u 2 ) ) × ∂ ∂ v ( ( ( 1 + v cos u 2 ) cos u , ( 1 + v cos u 2 ) sin u , v sin u 2 ) ) ⇒ n → = ∂ ∂ u ( ( cos u + v cos u cos u 2 , sin u + v sin u cos u 2 , v sin u 2 ) ) × ∂ ∂ v ( ( cos u + v cos u cos u 2 , sin u + v sin u cos u 2 , v sin u 2 ) ) ⇒ n → = ( − sin u + v ( − cos u 2 sin u − 1 2 cos u sin u 2 ) , cos u + v ( cos u 2 cos u − 1 2 sin u sin u 2 ) , v 2 cos u 2 ) × ( cos u 2 cos u , cos u 2 sin u , sin u 2 ) ⇒ n → = ( − sin u + ( − v cos u 2 sin u − v 2 cos u sin u 2 ) , cos u + ( v cos u 2 cos u − v 2 sin u sin u 2 ) , v 2 cos u 2 ) × ( cos u 2 cos u , cos u 2 sin u , sin u 2 ) ⇒ n → = ( { ( cos u + ( v cos u 2 cos u − v 2 sin u sin u 2 ) ) sin u 2 − ( v 2 cos u 2 ) ( cos u 2 sin u ) } , { ( v 2 cos u 2 ) cos u 2 cos u − ( − sin u + ( − v cos u 2 sin u − v 2 cos u sin u 2 ) ) sin u 2 } , { ( − sin u + ( − v cos u 2 sin u − v 2 cos u sin u 2 ) ) cos u 2 sin u − ( cos u + ( v cos u 2 cos u − v 2 sin u sin u To determine (b) To Calculate: The surface area of given surface S . To determine (c) To Calculate: The given surface integral.

4th Edition

ISBN: 9781319050733

Author: Rogawski

Publisher: MAC HIGHER

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Question

Chapter 17.5, Problem 38E

To determine

(a)

To Verify:

The given norm condition.

To determine

(b)

To Calculate:

The surface area of given surface S.

To determine

(c)

To Calculate:

The given surface integral.

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Chapter 17.5, Problem 37E

Chapter 17, Problem 1CRE

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2. [-/1 Points] DETAILS MY NOTES SESSCALCET2 6.4.006.MI. Use the Table of Integrals to evaluate the integral. (Remember to use absolute values where appropriate. Use C for the constant of integration.) 7y2 y² 11 dy Need Help? Read It Master It SUBMIT ANSWER 3. [-/1 Points] DETAILS MY NOTES SESSCALCET2 6.4.009. Use the Table of Integrals to evaluate the integral. (Remember to use absolute values where appropriate. Use C for the constant of integration.) tan³(12/z) dz Need Help? Read It Watch It SUBMIT ANSWER 4. [-/1 Points] DETAILS MY NOTES SESSCALCET2 6.4.014. Use the Table of Integrals to evaluate the integral. (Use C for the constant of integration.) 5 sinб12x dx Need Help? Read It

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y"-9y+20y= 80t-156 y(0) = −6, y'(0) = 5 y(t) =

Chapter 17 Solutions

CALCULUS (CLOTH)

Ch. 17.1 - Prob. 1PQ Ch. 17.1 - Prob. 2PQ Ch. 17.1 - Prob. 3PQ Ch. 17.1 - Prob. 4PQ Ch. 17.1 - Prob. 1E Ch. 17.1 - Prob. 2E Ch. 17.1 - Prob. 3E Ch. 17.1 - Prob. 4E Ch. 17.1 - Prob. 5E Ch. 17.1 - Prob. 6E

Ch. 17.1 - Prob. 7E Ch. 17.1 - Prob. 8E Ch. 17.1 - Prob. 9E Ch. 17.1 - Prob. 10E Ch. 17.1 - Prob. 11E Ch. 17.1 - Prob. 12E Ch. 17.1 - Prob. 13E Ch. 17.1 - Prob. 14E Ch. 17.1 - Prob. 15E Ch. 17.1 - Prob. 16E Ch. 17.1 - Prob. 17E Ch. 17.1 - Prob. 18E Ch. 17.1 - Prob. 19E Ch. 17.1 - Prob. 20E Ch. 17.1 - Prob. 21E Ch. 17.1 - Prob. 22E Ch. 17.1 - Prob. 23E Ch. 17.1 - Prob. 24E Ch. 17.1 - Prob. 25E Ch. 17.1 - Prob. 26E Ch. 17.1 - Prob. 27E Ch. 17.1 - Prob. 28E Ch. 17.1 - Prob. 29E Ch. 17.1 - Prob. 30E Ch. 17.1 - Prob. 31E Ch. 17.1 - Prob. 32E Ch. 17.1 - Prob. 33E Ch. 17.1 - Prob. 34E Ch. 17.1 - Prob. 35E Ch. 17.1 - Prob. 36E Ch. 17.1 - Prob. 37E Ch. 17.1 - Prob. 38E Ch. 17.1 - Prob. 39E Ch. 17.1 - Prob. 40E Ch. 17.1 - Prob. 41E Ch. 17.1 - Prob. 42E Ch. 17.1 - Prob. 43E Ch. 17.1 - Prob. 44E Ch. 17.1 - Prob. 45E Ch. 17.1 - Prob. 46E Ch. 17.1 - Prob. 47E Ch. 17.1 - Prob. 48E Ch. 17.1 - Prob. 49E Ch. 17.1 - Prob. 50E Ch. 17.1 - Prob. 51E Ch. 17.1 - Prob. 52E Ch. 17.1 - Prob. 53E Ch. 17.1 - Prob. 54E Ch. 17.1 - Prob. 55E Ch. 17.1 - Prob. 56E Ch. 17.1 - Prob. 57E Ch. 17.2 - Prob. 1PQ Ch. 17.2 - Prob. 2PQ Ch. 17.2 - Prob. 3PQ Ch. 17.2 - Prob. 4PQ Ch. 17.2 - Prob. 1E Ch. 17.2 - Prob. 2E Ch. 17.2 - Prob. 3E Ch. 17.2 - Prob. 4E Ch. 17.2 - Prob. 5E Ch. 17.2 - Prob. 6E Ch. 17.2 - Prob. 7E Ch. 17.2 - Prob. 8E Ch. 17.2 - Prob. 9E Ch. 17.2 - Prob. 10E Ch. 17.2 - Prob. 11E Ch. 17.2 - Prob. 12E Ch. 17.2 - Prob. 13E Ch. 17.2 - Prob. 14E Ch. 17.2 - Prob. 15E Ch. 17.2 - Prob. 16E Ch. 17.2 - Prob. 17E Ch. 17.2 - Prob. 18E Ch. 17.2 - Prob. 19E Ch. 17.2 - Prob. 20E Ch. 17.2 - Prob. 21E Ch. 17.2 - Prob. 22E Ch. 17.2 - Prob. 23E Ch. 17.2 - Prob. 24E Ch. 17.2 - Prob. 25E Ch. 17.2 - Prob. 26E Ch. 17.2 - Prob. 27E Ch. 17.2 - Prob. 28E Ch. 17.2 - Prob. 29E Ch. 17.2 - Prob. 30E Ch. 17.2 - Prob. 31E Ch. 17.2 - Prob. 32E Ch. 17.2 - Prob. 33E Ch. 17.2 - Prob. 34E Ch. 17.2 - Prob. 35E Ch. 17.2 - Prob. 36E Ch. 17.2 - Prob. 37E Ch. 17.2 - Prob. 38E Ch. 17.2 - Prob. 39E Ch. 17.2 - Prob. 40E Ch. 17.2 - Prob. 41E Ch. 17.2 - Prob. 42E Ch. 17.2 - Prob. 43E Ch. 17.2 - Prob. 44E Ch. 17.2 - Prob. 45E Ch. 17.2 - Prob. 46E Ch. 17.2 - Prob. 47E Ch. 17.2 - Prob. 48E Ch. 17.2 - Prob. 49E Ch. 17.2 - Prob. 50E Ch. 17.2 - Prob. 51E Ch. 17.2 - Prob. 52E Ch. 17.2 - Prob. 53E Ch. 17.2 - Prob. 54E Ch. 17.2 - Prob. 55E Ch. 17.2 - Prob. 56E Ch. 17.2 - Prob. 57E Ch. 17.2 - Prob. 58E Ch. 17.2 - Prob. 59E Ch. 17.2 - Prob. 60E Ch. 17.2 - Prob. 61E Ch. 17.2 - Prob. 62E Ch. 17.2 - Prob. 63E Ch. 17.2 - Prob. 64E Ch. 17.2 - Prob. 65E Ch. 17.2 - Prob. 66E Ch. 17.2 - Prob. 67E Ch. 17.2 - Prob. 68E Ch. 17.2 - Prob. 69E Ch. 17.2 - Prob. 70E Ch. 17.2 - Prob. 71E Ch. 17.2 - Prob. 72E Ch. 17.2 - Prob. 73E Ch. 17.2 - Prob. 74E Ch. 17.2 - Prob. 75E Ch. 17.3 - Prob. 1PQ Ch. 17.3 - Prob. 2PQ Ch. 17.3 - Prob. 3PQ Ch. 17.3 - Prob. 4PQ Ch. 17.3 - Prob. 1E Ch. 17.3 - Prob. 2E Ch. 17.3 - Prob. 3E Ch. 17.3 - Prob. 4E Ch. 17.3 - Prob. 5E Ch. 17.3 - Prob. 6E Ch. 17.3 - Prob. 7E Ch. 17.3 - Prob. 8E Ch. 17.3 - Prob. 9E Ch. 17.3 - Prob. 10E Ch. 17.3 - Prob. 11E Ch. 17.3 - Prob. 12E Ch. 17.3 - 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Prob. 12E Ch. 17.5 - Prob. 13E Ch. 17.5 - Prob. 14E Ch. 17.5 - Prob. 15E Ch. 17.5 - Prob. 16E Ch. 17.5 - Prob. 17E Ch. 17.5 - Prob. 18E Ch. 17.5 - Prob. 19E Ch. 17.5 - Prob. 20E Ch. 17.5 - Prob. 21E Ch. 17.5 - Prob. 22E Ch. 17.5 - Prob. 23E Ch. 17.5 - Prob. 24E Ch. 17.5 - Prob. 25E Ch. 17.5 - Prob. 26E Ch. 17.5 - Prob. 27E Ch. 17.5 - Prob. 28E Ch. 17.5 - Prob. 29E Ch. 17.5 - Prob. 30E Ch. 17.5 - Prob. 31E Ch. 17.5 - Prob. 32E Ch. 17.5 - Prob. 33E Ch. 17.5 - Prob. 34E Ch. 17.5 - Prob. 35E Ch. 17.5 - Prob. 36E Ch. 17.5 - Prob. 37E Ch. 17.5 - Prob. 38E Ch. 17 - Prob. 1CRE Ch. 17 - Prob. 2CRE Ch. 17 - Prob. 3CRE Ch. 17 - Prob. 4CRE Ch. 17 - Prob. 5CRE Ch. 17 - Prob. 6CRE Ch. 17 - Prob. 7CRE Ch. 17 - Prob. 8CRE Ch. 17 - Prob. 9CRE Ch. 17 - Prob. 10CRE Ch. 17 - Prob. 11CRE Ch. 17 - Prob. 12CRE Ch. 17 - Prob. 13CRE Ch. 17 - Prob. 14CRE Ch. 17 - Prob. 15CRE Ch. 17 - Prob. 16CRE Ch. 17 - Prob. 17CRE Ch. 17 - Prob. 18CRE Ch. 17 - Prob. 19CRE Ch. 17 - Prob. 20CRE Ch. 17 - Prob. 21CRE Ch. 17 - Prob. 22CRE Ch. 17 - Prob. 23CRE Ch. 17 - Prob. 24CRE Ch. 17 - Prob. 25CRE Ch. 17 - Prob. 26CRE Ch. 17 - Prob. 27CRE Ch. 17 - Prob. 28CRE Ch. 17 - Prob. 29CRE Ch. 17 - Prob. 30CRE Ch. 17 - Prob. 31CRE Ch. 17 - Prob. 32CRE Ch. 17 - Prob. 33CRE Ch. 17 - Prob. 34CRE Ch. 17 - Prob. 35CRE Ch. 17 - Prob. 36CRE Ch. 17 - Prob. 37CRE Ch. 17 - Prob. 38CRE Ch. 17 - Prob. 39CRE Ch. 17 - Prob. 40CRE Ch. 17 - Prob. 41CRE Ch. 17 - Prob. 42CRE Ch. 17 - Prob. 43CRE Ch. 17 - Prob. 44CRE Ch. 17 - Prob. 45CRE Ch. 17 - Prob. 46CRE Ch. 17 - Prob. 47CRE Ch. 17 - Prob. 48CRE Ch. 17 - Prob. 49CRE Ch. 17 - Prob. 50CRE Ch. 17 - Prob. 51CRE Ch. 17 - Prob. 52CRE Ch. 17 - Prob. 53CRE Ch. 17 - Prob. 54CRE Ch. 17 - Prob. 55CRE Ch. 17 - Prob. 56CRE Ch. 17 - Prob. 57CRE Ch. 17 - Prob. 58CRE Ch. 17 - Prob. 59CRE Ch. 17 - Prob. 60CRE Ch. 17 - Prob. 61CRE

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(a) To Verify: The given norm condition.

Solution Summary: The author shows that the surface S is not orientable. The parametric curve G is a unit vector that varies continuously.

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(a) To Verify: The given norm condition.

(b) To Calculate: The surface area of given surface S.

(c) To Calculate: The given surface integral.

Want to see the full answer?

Chapter 17 Solutions

(a)

To Verify:

The given norm condition.

(b)

To Calculate:

The surface area of given surface S.

(c)

To Calculate:

The given surface integral.