Organic Chemistry (8th Edition)
8th Edition
ISBN: 9780134042282
Author: Paula Yurkanis Bruice
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Concept explainers
Textbook Question
Chapter 17, Problem 79P
A carboxylic arid is formed when an α-haloketone reacts with hydroxide ion. This reaction is called a Favorskii reaction. Propose a mechanism for the following Favorskii reaction. (Hint: In the first step, HO- removes a proton from the α-carbon that is not bonded to Br; a three-membered ring is formed in the second step; and HO- is a nucleophile in the thud step.)
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
A carboxylic acid is formed when an a-haloketone reacts with hydroxide ion. This reaction is called a Favorskii reaction. Propose a mechanism for the following Favorskii reaction. (Hint: In the first step, HO- removes a proton from the a-carbon that is not bonded to Br; a three-membered ring is formed in the second step; and HO- is a nucleophile in the third step.)
H
Br
Br2
CH2Cl2
H,
Br
Electrophilic addition of bromine, Brɔ, to alkenes yields a 1,2-dibromoalkane. The reaction proceeds through a cyclic intermediate known as a bromonium ion. The reaction occurs in an
anhydrous solvent such as CH2Clɔ.
In the second step of the reaction, bromide is the nucleophile and attacks at one of the carbons of the bromonium ion to yield the product. Due to steric clashes, the bromide ion always attacks
the carbon from the opposite face of the bromonium ion so that a product with anti stereochemistry is formed.
Draw curved arrows to show the movement of electrons in this step of the mechanism.
Arrow-pushing Instructions
H
Br
H-
Br
H.
:Br:
Proviouc
Noxt
Br
Brz
CH3
CH3
H3C
CH2CI2
H3C
Br
Electrophilic addition of bromine, Br2; to alkenes yields a 1,2-dibromoalkane. The reaction proceeds through a cyclic intermediate known as a bromonium ion.
The reaction occurs in an anhydrous solvent such as CH,Cl).
In the second step of the reaction, bromide is the nucleophile and attacks at one of the carbons of the bromonium ion to yield the product. Due to steric clashes,
the bromide ion always attacks the carbon from the opposite face of the bromonium ion so that a product with anti stereochemistry is formed.
Draw curved arrows to show the movement of electrons in this step of the mechanism.
Arrow-pushing Instructions
Br:
:Br:
.CH3
H3C
H3C
CH3
Br:
Chapter 17 Solutions
Organic Chemistry (8th Edition)
Ch. 17.1 - Prob. 1PCh. 17.1 - Prob. 2PCh. 17.1 - Prob. 3PCh. 17.1 - Prob. 4PCh. 17.1 - Rank the compounds in each of the following groups...Ch. 17.2 - Explain why 92% of 2,4-pemtanedione exists as the...Ch. 17.3 - Draw the enol tautomers for each of the following...Ch. 17.3 - Prob. 8PCh. 17.4 - Prob. 9PCh. 17.4 - Prob. 10P
Ch. 17.5 - Show how the following compounds can be prepared...Ch. 17.6 - What compound is formed when a dilute solution of...Ch. 17.7 - Prob. 13PCh. 17.7 - Prob. 14PCh. 17.7 - How many stereoisomers are obtained from each of...Ch. 17.7 - Prob. 16PCh. 17.8 - Prob. 17PCh. 17.9 - Prob. 18PCh. 17.9 - What reagents should be used to prepare the...Ch. 17.10 - Prob. 20PCh. 17.10 - What aldehyde or ketone would be obtained when...Ch. 17.11 - Prob. 22PCh. 17.11 - How could you prepare the following compound using...Ch. 17.12 - Prob. 25PCh. 17.12 - What two carbonyl compound are required for the...Ch. 17.12 - Propose a mechanism for the following reaction:Ch. 17.13 - Draw the products of the following reactions:Ch. 17.13 - Prob. 29PCh. 17.13 - Prob. 30PCh. 17.14 - Prob. 31PCh. 17.15 - Write the mechanism for the reaction of a...Ch. 17.15 - Prob. 33PCh. 17.15 - Prob. 34PCh. 17.15 - Draw the product of the reaction of each of the...Ch. 17.16 - Draw the product obtained by heating each pair of...Ch. 17.16 - What two carbonyl compounds are needed to...Ch. 17.17 - Prob. 38PCh. 17.18 - Prob. 39PCh. 17.18 - Prob. 40PCh. 17.19 - Prob. 41PCh. 17.20 - Prob. 43PCh. 17.21 - Propose a mechanism for the formation of...Ch. 17.21 - Prob. 45PCh. 17.21 - a. If the biosynthesis of palmitic acid were...Ch. 17.21 - Prob. 47PCh. 17 - Prob. 48PCh. 17 - Prob. 49PCh. 17 - Number the following compounds in order of...Ch. 17 - The 1H NMR chemical shifts of nitromethane,...Ch. 17 - Prob. 52PCh. 17 - Draw the products of the following reactions: a....Ch. 17 - A racemic mixture of 2-methyl-1-phenyl-1-butanone...Ch. 17 - Draw the products of the following reaction:Ch. 17 - Prob. 56PCh. 17 - Prob. 57PCh. 17 - In the presence of excess base and excess halogen,...Ch. 17 - Identify A-L. (Hint: A shows three singles in its...Ch. 17 - Using cyclopentanone as the reactant, show the...Ch. 17 - Show how 4-methyl-3-hexanol can be synthesized...Ch. 17 - Show how the following compound can be synthesized...Ch. 17 - Show how the following compounds can be prepared...Ch. 17 - Prob. 64PCh. 17 - Prob. 65PCh. 17 - Indicate how each of the following compounds can...Ch. 17 - Prob. 67PCh. 17 - The ketone whose 1H NMR spectrum is shown here was...Ch. 17 - Indicate how the following compounds can be...Ch. 17 - Compound A with molecular formula C6H10 has two...Ch. 17 - Prob. 71PCh. 17 - Draw the products of the following reactions:Ch. 17 - Prob. 73PCh. 17 - a. Show how the amino acid alanine can be...Ch. 17 - Show how the following compounds can be...Ch. 17 - Prob. 76PCh. 17 - Explain why the following bromoketone forms...Ch. 17 - Prob. 78PCh. 17 - A carboxylic arid is formed when an -haloketone...Ch. 17 - An , -unsaturated carbonyl compound can be...Ch. 17 - What carbonyl compounds are required to prepare a...Ch. 17 - Prob. 82PCh. 17 - A Cannizzaro reaction is the reaction of an...Ch. 17 - Propose a mechanism for each of the following...Ch. 17 - The following reaction is known as the benzoni...Ch. 17 - Prob. 86PCh. 17 - Prob. 87PCh. 17 - Prob. 88PCh. 17 - Prob. 89PCh. 17 - Prob. 90PCh. 17 - Propose a mechanism for the following reaction:Ch. 17 - What reagents are required to convert the reactant...Ch. 17 - Starting with bromocyclohexane, how can each of...Ch. 17 - Describe how the following compounds can be...Ch. 17 - Prob. 4PCh. 17 - Describe three ways to synthesize the following...Ch. 17 - Explain why 92% of 2.4-pentanedione exists as the...Ch. 17 - Describe how the following compound can be...Ch. 17 - Prob. 8PCh. 17 - Prob. 9PCh. 17 - Prob. 10PCh. 17 - Show how the following compounds can be...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- Which of the following molecules is most nucleophilic? OA. NaOCH₂CH3 OB. CH3CH₂OH OC. NaOC6H5 OD. C₂H5OH 1 E.CH3COONaarrow_forwardConsider each elementary step present in the mechanism of an acid-catalyzed hydrolysis of a nitrile. Draw the organic intermediate after each elementary step. NOTE from Dr. Mahoney: Your mechanism will only cover the hydrolysis of a nitrile to an amide product. It will not cover the conversion of the amide to the final carboxylic acid H30* H₂O Step 3 Step 5 Step 4 11 Narrow_forwardThe behavior of esters and ketones in a reaction with a nucleophile is different because: 1) the carbonyl of the ketone is more positive. 2) the ester cannot form a tetrahedral intermediate. 3) the two oxygens of the ester sterically hinder the nucleophile attack. 4) there is a reasonable leaving group in the ester. O 2 O 4 O 1arrow_forward
- Provide the correct sequence of the steps involved in the following reaction: H3C CH2 H3C Br2 HBr но Br Step 1 [Choose] Nucleophilic attack on Bromine Carbocation rearrangement Proton transfer to bromide ion Step 2 Nucleophilic attack by water Leaving group leaves Nucleophilic attack by hydroxide Step 3 Generation of bromonium ion Step 4 [ Choose ]arrow_forwardWater acting as a nucleophile is observed to react with the following molecule. What is one likely new product of the first step of this reaction? OH O "N(CH3)2 OCH3 O carbonate O alkyl halide O ketone O amine O alcoholarrow_forwardComplete the reaction scheme below. Show all reagents and intermediates. No reaction is a possible answer. 1) CH3CH2M9B CH3OH H+ (ехcess) но 2) H30*, H2O B A OCH3arrow_forward
- Draw a plausible mechanism for the formation of phenol shown below. Provide explanations for each step in the mechanism. (HINT: The mechanism involves electrocyclic reactions, NOT sigmatropic rearrangements.) HOʻarrow_forwardDraw the mechanism for the reaction of an alkyl halide with sodium azide followed by reduction. Complete the mechanism of the initial step of the reaction, then identify the key intermediate and the product. Step 1: Draw curved arrows. o z + Na + || : z: I Step 2: Complete the intermediate. Na +arrow_forwardWrite mechanisms for each reactions.arrow_forward
- When the ketone and aldehyde shown below are treated with a base two possible products are formed. Discuss how each product is formed and provide a mechanism.arrow_forwardWhich best describes the first step of the mechanism of the reaction below? + CH₂MgBr H3C 1) ether 2) H3O+ → CH3 CH3MgBr acts as an nucleophile and attacks the carbonyl carbon. The carbonyl carbon acts as an nucleophile and attacks CH3MgBr. The methyl group on acetone leaves forming a carbonyl carbocation. O CH3MgBr acts as an electrophile and attacks the carbonyl oxygen.arrow_forwardSelect the reagent that you would use to convert an alkene to an epoxide. mCPBA 03, then DMS BH3-THF, then H2O2, H2O, NaOH Hg(OAc)2, H2O, then NaBH4arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning
Organic Chemistry
Chemistry
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:Cengage Learning
Enzymes - Effect of cofactors on enzyme; Author: Tutorials Point (India) Ltd;https://www.youtube.com/watch?v=AkAbIwxyUs4;License: Standard YouTube License, CC-BY
Enzyme Catalysis Part-I; Author: NPTEL-NOC IITM;https://www.youtube.com/watch?v=aZE740JWZuQ;License: Standard Youtube License