8th Edition

ISBN: 9780134042282

Author: Paula Yurkanis Bruice

Publisher: PEARSON

Concept explainers

Chemical equilibrium and ionic equilibrium are two major concepts in chemistry. Ionic equilibrium deals with the equilibrium involved in an ionization process while chemical equilibrium deals with the equilibrium during a chemical change. Ionic equilibri…

Arrhenius Acid

Arrhenius acid act as a good electrolyte as it dissociates to its respective ions in the aqueous solutions. Keeping it similar to the general acid properties, Arrhenius acid also neutralizes bases and turns litmus paper into red.

Bronsted Lowry Base In Inorganic Chemistry

Bronsted-Lowry base in inorganic chemistry is any chemical substance that can accept a proton from the other chemical substance it is reacting with.

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Textbook Question

Chapter 17, Problem 58P

In the presence of excess base and excess halogen, a methyl ketone is converted to a carboxylate ion. The reaction is known as the haloform reaction because one of the products is haloform (chloroform, bromoform, or iodoform). Before spectroscopy became a routine analytical tool, the haloform reaction served as a test for methyl ketones: the formation of iodoform, a bright yellow compound, signaled that a methyl ketone was present. Why do only methyl ketones form a haloform?

Chapter 17, Problem 58P, In the presence of excess base and excess halogen, a methyl ketone is converted to a carboxylate

Definition Definition Organic compounds that have a carbonyl group, C = O, as their functional group. The carbonyl group in ketones is placed somewhere in the middle of the molecular structure, which means, the C=O is attached to two alkyl groups or benzene rings. Just like all other homologous series, the naming of ketones is done using a common suffix “-one”. The general molecular formula is C n H 2n O. Functional group of a ketone

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Chapter 17, Problem 57P

Chapter 17, Problem 59P

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Chapter 17 Solutions

Organic Chemistry (8th Edition)

Ch. 17.1 - Prob. 1P Ch. 17.1 - Prob. 2P Ch. 17.1 - Prob. 3P Ch. 17.1 - Prob. 4P Ch. 17.1 - Rank the compounds in each of the following groups...Ch. 17.2 - Explain why 92% of 2,4-pemtanedione exists as the...Ch. 17.3 - Draw the enol tautomers for each of the following...Ch. 17.3 - Prob. 8P Ch. 17.4 - Prob. 9P Ch. 17.4 - Prob. 10P

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