Chapter 17, Problem 76A

(a)

Interpretation Introduction

Interpretation:

The effect of temperature on the equilibrium state of the given reaction is to be explained.

Concept introduction:

By changing the temperature, the equilibrium state is also changing.

Answer to Problem 76A

This reaction is an exothermic reaction. The equilibrium state for an exothermic reaction is decreases as temperature is increases.

Explanation of Solution

The given reaction is

${\text{2O}}_{\text{3}}\left(\text{g}\right)\rightleftharpoons {\text{3O}}_{\text{2}}\left(\text{g}\right)\text{+Heat}$

This reaction is an exothermic reaction.

If the temperature is decreased, the equilibrium will change in the direction of exothermic reaction or forward reaction. The temperature affects a reaction in two ways such that

1. It increase rate of reaction so that the equilibrium is reached earlier.
2. It affects the equilibrium constant.

(b)

Interpretation Introduction

Interpretation:

. The effect of temperature on the equilibrium state of the given reaction is to be explained

Concept introduction:

By changing the temperature, the equilibrium state is also changing

Answer to Problem 76A

This reaction is an endothermic reaction. The equilibrium state for an endothermic reaction is increases as temperature is increases.

Explanation of Solution

The given reaction is

${\text{Heat+H}}_{\text{2}}\left(\text{g}\right){\text{+F}}_{\text{2}}\left(\text{g}\right)\rightleftharpoons \text{2HF}\left(\text{g}\right)$

This is an endothermic reaction

If the temperature is increased in the direction of endothermic reaction, which tends to undo the effect of added heat. The equilibrium shifts towards the direction in which heat is absorbed to relieve the system of the stress of added heat.

The temperature affects a reaction in two ways such that

1. It increase rate of reaction so that the equilibrium is reached earlier.
2. It affects the equilibrium constant.