INDUSTRIAL MOTOR CONTROL
7th Edition
ISBN: 9780357670590
Author: Herman
Publisher: CENGAGE L
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Chapter 17, Problem 5RQ
To determine
The device for which the cad cell is a common name.
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Chapter 17 Solutions
INDUSTRIAL MOTOR CONTROL
Ch. 17 - List the three major categories of photodetectors.Ch. 17 - In which category does the solar cell belong?Ch. 17 - In which category do phototransistors and...Ch. 17 - Prob. 4RQCh. 17 - Prob. 5RQCh. 17 - Prob. 6RQCh. 17 - What is the advantage of a photodetector that uses...Ch. 17 - An object is to be detected by reflecting light...Ch. 17 - How much voltage is produced by a silicon solar...
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- please solve and show workarrow_forwardA thin plastic membrane separates hydrogen from air. The molar concentrations of hydrogen in the membrane at the innner and outer surfaces are determined to be 0.045 and 0.002 kmol/m^3 respectiveley. The binary diffusion coefficent of hydrogen in plastic at the operation temp is 5.3*10^-10 m^2/s. Determine the mass flow rate of hydrogen by diffusion through the membrane under steady conditions if the thickeness of the membrane is 2mm and 0.5 mm.arrow_forwardCalculate the vertical cross section moment of inertia for Orientations 1 and 2. State which number is the higher moment of inertia using equation 1. Given: b1=1 in, h1=1.5 in, b2=1.5 in, h2=1 in, t=0.0625 in. Then calculate the maximum deflection for a point load of 8 lb on the free end of the beam using equation 2. Given: E=10.1*10^6 psi. 1. ((bh^3)/12) - (((b-2t)(h-2t)^3))/12) 2. S = (PL^3)/(3EI)arrow_forward
- 1-69E The pressure in a natural gas pipeline is measured by the manometer shown in Fig. P1-69E with one of the arms open to the atmosphere where the local atmospheric pressure is 14.2 psia. Determine the absolute pressure in the pipeline. Natural Gas 10 in 6 in FIGURE P1-69E Mercury SG= 13.6 Air 2 in + 25 in Waterarrow_forwardB 150 mm 120 mm PROBLEM 15.193 The L-shaped arm BCD rotates about the z axis with a constant angular velocity @₁ of 5 rad/s. Knowing that the 150-mm- radius disk rotates about BC with a constant angular velocity @2 of 4 rad/s, determine (a) the velocity of Point A, (b) the acceleration of Point A. Answers: V₁ =-(0.600 m/s)i + (0.750 m/s)j - (0.600 m/s)k a=-(6.15 m/s²)i- (3.00 m/s²)jarrow_forward3 Answer: 002 PROBLEM 15.188 The rotor of an electric motor rotates at the constant rate @₁ = 1800 rpm. Determine the angular acceleration of the rotor as the motor is rotated about the y axis with a constant angular velocity 2 x of 6 rpm counterclockwise when viewed from the positive y axis. α = (118.4 rad/s²)iarrow_forward
- 12 in.. 10 in. PROBLEM 15.187 At the instant considered the radar antenna shown rotates about the origin of coordinates with an angular velocity @ = ai + @j+wk Knowing that (VA) = 15 in./s, (VB), 9 in./s, and (VB), = 18 in./s, determine (a) the angular velocity of the antenna, (b) the velocity of point A. B 10 in. Answers: = (0.600 rad/s)i - (2.00 rad/s) j + (0.750 rad/s)k V₁ = (20.0 in./s)i + (15.00 in./s) j + (24.0 in./s)karrow_forward3. An engine has three cylinders spaced at 120° to each other. The crank torque diagram can be simplified to a triangle having the following values: Angle 0° Torque (Nm) 0 (a) What is the mean torque? 60° 4500 180° 180° to 360° 0 0 (b) What moment of inertia of flywheel is required to keep the speed to within 180 ± 3 rpm? (c) If one cylinder of the engine is made inoperative and it is assumed that the torque for this cylinder is zero for all crank angles, determine the fluctuation in speed at 180rpm for the same flywheel. (a) 3375 Nm (b) 50kgm (c) ±21 rpmarrow_forwardProb 5. Determine the largest load P that can be applied to the frame without causing either the average normal stress or the average shear stress at section a-a to exceed o-150 MPa and 1-60 MPa, respectively. Member CB has a square cross section of 25 mm on each side. 2 m FAC 1.5 m Facarrow_forward
- Derive the component transformation equations for tensors shown below where [C] = [BA] is the DCM (direction cosine matrix) from frame A to B. ^B [T] = [C]^A [T] [C]^Tarrow_forwardCalculate for the vertical cross section moment of inertia for both Orientations 1 and 2 of a 1 x 1.5 in. horizontal hollow rectangular beam with wall thickness of t = 0.0625 in. Use the equation: I = ((bh^3)/12) - (((b-2t)(h-2t)^3)/12)arrow_forwardPlease answer 'yes' or 'no' and 'is' or 'is not' for the following:arrow_forward
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