Chapter 17, Problem 58QAP

. Write the balanced chemical equation describing the dissolving of each of the following sparingly soluble salts in water. Write the expression for K_spfor each process.

a. NiS(s)

c. BaCrO₄(s)

b. CuCO₃(s)

d. Ag₃PO₄(s)

Interpretation Introduction

(a)

Interpretation:

The balanced equation for the reaction describing the dissolution of the given sparingly soluble salt in water is to be stated. The ${\text{K}}_{\text{sp}}$ expression for the given sparingly soluble salt is to be stated.

Concept Introduction:

The solubility product is represented by ${\text{K}}_{\text{sp}}$. The solubility product describes the solubility of the solid substance in the solvent at the particular temperature. The term “solubility product” is only used for those substances that are not completely soluble in water.

Answer to Problem 58QAP

The balanced equation for the reaction describing the dissolving of $\text{NiS}(s)$ in water is,

$\text{NiS}(s)\rightleftharpoons {\text{Ni}}^{2+}(aq)+{\text{S}}^{2-}(aq)$

The solubility product for $\text{NiS}(s)$ is,

${\text{K}}_{\text{sp}}=[{\text{Ni}}^{2+}][{\text{S}}^{2-}]$

Where, ${\text{K}}_{\text{sp}}$ is the solubility product.

Explanation of Solution

The balanced equation for the reaction describing the dissolving of $\text{NiS}(s)$ in water is,

$\text{NiS}(s)\rightleftharpoons {\text{Ni}}^{2+}(aq)+{\text{S}}^{2-}(aq)$

The forward reaction shows the dissolution of $\text{NiS}(s)$ and backward reaction shows the reformation of the solid.

The solubility product for $\text{NiS}(s)$ is,

${\text{K}}_{\text{sp}}=[{\text{Ni}}^{2+}][{\text{S}}^{2-}]$

Where, ${\text{K}}_{\text{sp}}$ is the solubility product.

Interpretation Introduction

(b)

Interpretation:

The balanced equation for the reaction describing the dissolution of the given sparingly soluble salt in water is to be stated. The ${\text{K}}_{\text{sp}}$ expression for the given sparingly soluble salt is to be stated.

Concept Introduction:

The solubility product is represented by ${\text{K}}_{\text{sp}}$. The solubility product describes the solubility of the solid substance in the solvent at the particular temperature. The term “solubility product” is only used for those substances that are not completely soluble in water.

Answer to Problem 58QAP

The balanced equation for the reaction describing the dissolving of ${\text{CuCO}}_3(s)$ in water is,

${\text{CuCO}}_3(s)\rightleftharpoons {\text{Cu}}^{2+}(aq)+{\text{CO}}_3^{2-}(aq)$

The solubility product for ${\text{CuCO}}_3(s)$ is,

${\text{K}}_{\text{sp}}=[{\text{Cu}}^{2+}][{\text{CO}}_3^{2-}]$

Where, ${\text{K}}_{\text{sp}}$ is the solubility product.

Explanation of Solution

The balanced equation for the reaction describing the dissolving of ${\text{CuCO}}_3(s)$ in water is,

${\text{CuCO}}_3(s)\rightleftharpoons {\text{Cu}}^{2+}(aq)+{\text{CO}}_3^{2-}(aq)$

The forward reaction shows the dissolving of ${\text{CuCO}}_3(s)$ and backward reaction shows the reformation of the solid.

The solubility product for ${\text{CuCO}}_3(s)$ is,

${\text{K}}_{\text{sp}}=[{\text{Cu}}^{2+}][{\text{CO}}_3^{2-}]$

Where, ${\text{K}}_{\text{sp}}$ is the solubility product.

Interpretation Introduction

(c)

Interpretation:

The balanced equation for the reaction describing the dissolution of the given sparingly soluble salt in water is to be stated. The ${\text{K}}_{\text{sp}}$ expression for the given sparingly soluble salt is to be stated.

Concept Introduction:

The solubility product is represented by ${\text{K}}_{\text{sp}}$. The solubility product describes the solubility of the solid substance in the solvent at the particular temperature. The term “solubility product” is only used for those substances that are not completely soluble in water.

Answer to Problem 58QAP

The balanced equation for the reaction describing the dissolving of ${\text{BaCrO}}_4(s)$ in water is,

${\text{BaCrO}}_4(s)\rightleftharpoons {\text{Ba}}^{2+}(aq)+{\text{CrO}}_4^{2-}(aq)$

The solubility product for ${\text{BaCrO}}_4(s)$ is,

${\text{K}}_{\text{sp}}=[{\text{Ba}}^{2+}][{\text{CrO}}_4^{2-}]$

Where, ${\text{K}}_{\text{sp}}$ is the solubility product.

Explanation of Solution

The balanced equation for the reaction describing the dissolving of ${\text{BaCrO}}_4(s)$ in water is,

${\text{BaCrO}}_4(s)\rightleftharpoons {\text{Ba}}^{2+}(aq)+{\text{CrO}}_4^{2-}(aq)$

The forward reaction shows the dissolving of ${\text{BaCrO}}_4(s)$ and backward reaction shows the reformation of the solid.

The solubility product for ${\text{BaCrO}}_4(s)$ is,

${\text{K}}_{\text{sp}}=[{\text{Ba}}^{2+}][{\text{CrO}}_4^{2-}]$

Where, ${\text{K}}_{\text{sp}}$ is the solubility product.

Interpretation Introduction

(d)

Interpretation:

The balanced equation for the reaction describing the dissolution of the given sparingly soluble salt in water is to be stated. The ${\text{K}}_{\text{sp}}$ expression for the given sparingly soluble salt is to be stated.

Concept Introduction:

The solubility product is represented by ${\text{K}}_{\text{sp}}$. The solubility product describes the solubility of the solid substance in the solvent at the particular temperature. The term “solubility product” is only used for those substances that are not completely soluble in water.

Answer to Problem 58QAP

The balanced equation for the reaction describing the dissolving of ${\text{Ag}}_3{\text{PO}}_{\text{4}}(s)$ in water is,

${\text{Ag}}_3{\text{PO}}_{\text{4}}(s)\rightleftharpoons {\text{Ag}}^{+}(aq)+{\text{PO}}_4^{3-}(aq)$

The solubility product for ${\text{Ag}}_3{\text{PO}}_{\text{4}}(s)$ is,

${\text{K}}_{\text{sp}}=[{\text{Ag}}^{+}][{\text{PO}}_4^{3-}]$

Where, ${\text{K}}_{\text{sp}}$ is the solubility product.

Explanation of Solution

The balanced equation for the reaction describing the dissolving of ${\text{Ag}}_3{\text{PO}}_{\text{4}}(s)$ in water is,

${\text{Ag}}_3{\text{PO}}_{\text{4}}(s)\rightleftharpoons {\text{Ag}}^{+}(aq)+{\text{PO}}_4^{3-}(aq)$

The forward reaction shows the dissolving of ${\text{Ag}}_3{\text{PO}}_{\text{4}}(s)$ and backward reaction shows the reformation of the solid.

The solubility product for ${\text{Ag}}_3{\text{PO}}_{\text{4}}(s)$ is,

${\text{K}}_{\text{sp}}=[{\text{Ag}}^{+}][{\text{PO}}_4^{3-}]$

Where, ${\text{K}}_{\text{sp}}$ is the solubility product.