Chapter 17, Problem 57QAP

. Write the balanced chemical equation describing the dissolving of each of the following sparingly soluble salts in water. Write the expression for K for each process.

a. AgIO₃(s)

c. Zn₃(PO₄)₂(s)

b. Sn(OH)₂(s)

d. BaF₂(s)

Interpretation Introduction

(a)

Interpretation:

The balanced chemical equation along with its expression for ${\text{K}}_{\text{sp}}$ which describes the dissolving of the given sparingly soluble salts in water are to be stated.

Concept Introduction:

The chemical equilibrium is the state in which the rates of both forward and backward reactions become equal. The concentration of both reactants and products do not change on reaching an equilibrium state.

The general chemical equation is shown below.

$\text{aA}+\text{bB}\rightleftharpoons \text{cC}+\text{dD}$

The general equilibrium expression for a reaction is shown below.

$\text{K}=\frac{{\left[\text{C}\right]}^{\text{c}}{\left[\text{D}\right]}^{\text{d}}}{{\left[\text{A}\right]}^{\text{a}}{\left[\text{B}\right]}^{\text{b}}}$.

Answer to Problem 57QAP

The balanced chemical equation describing dissolution of ${\text{AgIO}}_{\text{3}}\left(\text{s}\right)$ in water along with its expression for ${\text{K}}_{\text{sp}}$ is,

${\text{AgIO}}_{\text{3}}\left(\text{s}\right)\rightleftharpoons {\text{Ag}}^{+}\left(\text{a}\text{q}\right)+{\text{IO}}_3^{-}\left(\text{a}\text{q}\right)$.

Explanation of Solution

The given sparingly soluble salt is ${\text{AgIO}}_{\text{3}}\left(\text{s}\right)$.

The balanced chemical equation of ${\text{AgIO}}_{\text{3}}\left(\text{s}\right)$ that describes its dissolution in water is shown below.

${\text{AgIO}}_{\text{3}}\left(\text{s}\right)\rightleftharpoons {\text{Ag}}^{+}\left(\text{a}\text{q}\right)+{\text{IO}}_3^{-}\left(\text{a}\text{q}\right)$

The expression of ${\text{K}}_{\text{sp}}$ for the above chemical equation is shown below.

${\text{K}}_{\text{sp}}=\left[{\text{Ag}}^{+}\right]\left[{\text{IO}}_3^{-}\right]$.

Interpretation Introduction

(b)

Interpretation:

The balanced chemical equation along with its expression for ${\text{K}}_{\text{sp}}$ which describes the dissolving of the given sparingly soluble salts in water are to be stated.

Concept Introduction:

The chemical equilibrium is the state in which the rates of both forward and backward reactions become equal. The concentration of both reactants and products do not change on reaching an equilibrium state.

The general chemical equation is shown below.

$\text{aA}+\text{bB}\rightleftharpoons \text{cC}+\text{dD}$

The general equilibrium expression for a reaction is shown below.

$\text{K}=\frac{{\left[\text{C}\right]}^{\text{c}}{\left[\text{D}\right]}^{\text{d}}}{{\left[\text{A}\right]}^{\text{a}}{\left[\text{B}\right]}^{\text{b}}}$.

Answer to Problem 57QAP

The balanced chemical equation describing the dissolution of $\text{Sn}{\left(\text{OH}\right)}_{\text{2}}\left(\text{s}\right)$ in water along with its expression for ${\text{K}}_{\text{sp}}$ is,

$\text{Sn}{\left(\text{OH}\right)}_{\text{2}}\left(\text{s}\right)\rightleftharpoons {\text{Sn}}^{2+}\left(\text{a}\text{q}\right)+2{\text{OH}}^{-}\left(\text{a}\text{q}\right)$.

Explanation of Solution

The given sparingly soluble salt is $\text{Sn}{\left(\text{OH}\right)}_{\text{2}}\left(\text{s}\right)$.

The balanced chemical equation of $\text{Sn}{\left(\text{OH}\right)}_{\text{2}}\left(\text{s}\right)$ that describes its dissolution in water is shown below.

$\text{Sn}{\left(\text{OH}\right)}_{\text{2}}\left(\text{s}\right)\rightleftharpoons {\text{Sn}}^{2+}\left(\text{a}\text{q}\right)+2{\text{OH}}^{-}\left(\text{a}\text{q}\right)$

The expression of ${\text{K}}_{\text{sp}}$ for the above chemical equation is shown below.

${\text{K}}_{\text{sp}}=\left[{\text{Sn}}^{2+}\right]{\left[{\text{OH}}^{-}\right]}^2$

Therefore, the balanced chemical equation along with its expression for ${\text{K}}_{\text{sp}}$ which describes the dissolving of the given sparingly soluble salts in water have been rightfully stated.

Interpretation Introduction

(c)

Interpretation:

The balanced chemical equation along with its expression for ${\text{K}}_{\text{sp}}$ which describes the dissolving of the given sparingly soluble salts in water are to be stated.

Concept Introduction:

The chemical equilibrium is the state in which the rates of both forward and backward reactions become equal. The concentration of both reactants and products do not change on reaching an equilibrium state.

The general chemical equation is shown below.

$\text{aA}+\text{bB}\rightleftharpoons \text{cC}+\text{dD}$

The general equilibrium expression for a reaction is shown below.

$\text{K}=\frac{{\left[\text{C}\right]}^{\text{c}}{\left[\text{D}\right]}^{\text{d}}}{{\left[\text{A}\right]}^{\text{a}}{\left[\text{B}\right]}^{\text{b}}}$.

Answer to Problem 57QAP

The balanced chemical equation describing dissolution of ${\text{Zn}}_{\text{3}}{\left({\text{PO}}_{\text{4}}\right)}_{\text{2}}\left(\text{s}\right)$ in water along with its expression for ${\text{K}}_{\text{sp}}$ is,

$\text{Sn}{\left(\text{OH}\right)}_{\text{2}}\left(\text{s}\right)\rightleftharpoons {\text{Sn}}^{2+}\left(\text{a}\text{q}\right)+2{\text{OH}}^{-}\left(\text{a}\text{q}\right)$.

Explanation of Solution

The given sparingly soluble salt is ${\text{Zn}}_{\text{3}}{\left({\text{PO}}_{\text{4}}\right)}_{\text{2}}\left(\text{s}\right)$.

The balanced chemical equation of ${\text{Zn}}_{\text{3}}{\left({\text{PO}}_{\text{4}}\right)}_{\text{2}}\left(\text{s}\right)$ that describes its dissolution in water is shown below.

${\text{Zn}}_{\text{3}}{\left({\text{PO}}_{\text{4}}\right)}_{\text{2}}\left(\text{s}\right)\rightleftharpoons 3{\text{Zn}}^{2+}\left(\text{a}\text{q}\right)+2{\text{PO}}_4^{3-}\left(\text{a}\text{q}\right)$

The expression of ${\text{K}}_{\text{sp}}$ for the above chemical equation is shown below.

${\text{K}}_{\text{sp}}={\left[{\text{Zn}}^{2+}\right]}^3{\left[{\text{PO}}_4^{3-}\right]}^2$

Therefore, the balanced chemical equation along with its expression for ${\text{K}}_{\text{sp}}$ which describes the dissolving of the given sparingly soluble salts in water have been rightfully stated.

Interpretation Introduction

(d)

Interpretation:

The balanced chemical equation along with its expression for ${\text{K}}_{\text{sp}}$ which describes the dissolving of the given sparingly soluble salts in water are to be stated.

Concept Introduction:

The chemical equilibrium is the state in which the rates of both forward and backward reactions become equal. The concentration of both reactants and products do not change on reaching an equilibrium state.

The general chemical equation is shown below.

$\text{aA}+\text{bB}\rightleftharpoons \text{cC}+\text{dD}$

The general equilibrium expression for a reaction is shown below.

$\text{K}=\frac{{\left[\text{C}\right]}^{\text{c}}{\left[\text{D}\right]}^{\text{d}}}{{\left[\text{A}\right]}^{\text{a}}{\left[\text{B}\right]}^{\text{b}}}$.

Answer to Problem 57QAP

The balanced chemical equation describing dissolution of ${\text{BaF}}_2\left(\text{s}\right)$ in water along with its expression for ${\text{K}}_{\text{sp}}$ is,

${\text{BaF}}_2\left(\text{s}\right)\rightleftharpoons {\text{Ba}}^{2+}\left(\text{a}\text{q}\right)+2{\text{F}}^{-}\left(\text{a}\text{q}\right)$.

Explanation of Solution

The given sparingly soluble salt is ${\text{BaF}}_2\left(\text{s}\right)$.

The balanced chemical equation of ${\text{BaF}}_2\left(\text{s}\right)$ that describes its dissolution in water is shown below.

${\text{BaF}}_2\left(\text{s}\right)\rightleftharpoons {\text{Ba}}^{2+}\left(\text{a}\text{q}\right)+2{\text{F}}^{-}\left(\text{a}\text{q}\right)$

The expression of ${\text{K}}_{\text{sp}}$ for the above chemical equation is shown below.

${\text{K}}_{\text{sp}}=\left[{\text{Ba}}^{2+}\right]{\left[{\text{F}}^{-}\right]}^2$

Therefore, the balanced chemical equation along with its expression for ${\text{K}}_{\text{sp}}$ which describes the dissolving of the given sparingly soluble salts in water have been rightfully stated.