Chapter 17, Problem 53A

Interpretation Introduction

Interpretation: The heat required to raise the temperature of $\text{400}\text{.0 g}$ of silver by $\text{45°C}$ is to be found out.

Concept Introduction: The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

Answer to Problem 53A

The heat required to raise the temperature of $\text{400}\text{.0 g}$ of silver by $\text{45°C}$ is $\text{4194 Joules}$ .

Explanation of Solution

Mathematically it is represented by

  $\text{Q=m×C×ΔT}$

  $\text{Q}$ = Heat absorbed

  $\text{m}$ = mass of substance

  $\text{C}$ = heat capacity of substance (silver) = $\text{0}\text{.233 J/g°C}$

  $\text{ΔT}$ = change in temperature

It is given that $\text{400}\text{.0 g}$ of silver absorbs a certain amount of heat of and its temperature increases by $\text{45°C}$ .

Putting in the values, we get:

  $\begin{array}{l}\text{Q=400}\text{.0g×0}\text{.233 J/g°C×45°C}\\ \text{Q=4194 J }\end{array}$