Chapter 17, Problem 2STP

Interpretation Introduction

Interpretation: The amount of heat that must be added is to be determined.

Concept Introduction: The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

Mathematically it is represented by

  $\text{Q=m×C×ΔT}$

  $\text{Q}$ = Heat absorbed or released

  $\text{m}$ = mass of the substance

  $\text{C}$ = heat capacity of the substance

  $\text{ΔT}$ = change in temperature

Answer to Problem 2STP

  $3.7\text{ kJ}$

Explanation of Solution

It is given that $\text{178 g}$ of liquid water is to be heated by $5.0\text{°C}$ .

Putting in the values, we get:

  $Q$ = Heat absorbed by water = ?

  $m$ = mass of water = $\text{178 g}$

  $C$ = heat capacity of water = $\text{4}\text{.184 J/g°C}$

  $\Delta T$ = change in temperature = $5.0\text{°C}$

Putting in the values we get,

  $\begin{array}{l}\text{Q=178g×4}\text{.184 J/g°C×5}\text{.0°C}\\ \text{Q= 3723 J=}\frac{3723}{1000}\text{kJ}=3.7\text{kJ}\end{array}$