To determine The kinetic energy of an electron while leaving the parallel plates. Explanation The initial kinetic energy of the electron is 2.0 × 10 − 15 J , potential difference is 100.0 kV , distance between the deflecting parallel plates is 12.0 mm and the deflected distance is 3.0 mm . Write the expression for conservation of energy K f + U f = K i + U i (I) Here, K f is the final kinetic energy, K i is the initial kinetic energy, U f is the final potential energy and U i is the initial kinetic energy. Rearrange (I) K f − K i = U i − U f Write the expression for change in kinetic energy K f − K i = − Δ U (II) Here, Δ U is the change in electric potential energy. Work done by the electric field is the negative of change in potential energy. Substitute − W f for Δ U K f − K i = − ( − W f ) (III) Here, W f is the work done by the field. Write the expression for work done in moving an electron. W f = − e E ( − Δ y ) Here, − e is the charge of the electron, E is the electric field and Δ y is the distance through which the electron is deflected. The negative sign in front of denotes the electron being moved in the direction opposite to the electric field. Substitute for W f in (III) and rearrange for K f K f = K i + e E Δ y (IV) Write the expression for electric field between two parallel plates

5th Edition

ISBN: 9781260486919

Author: GIAMBATTISTA

Publisher: MCG

See similar textbooks

Concept explainers

Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

Videos

Question

Chapter 17, Problem 50P

To determine

The kinetic energy of an electron while leaving the parallel plates.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 17, Problem 49P

Chapter 17, Problem 51P

Students have asked these similar questions

If a planet orbits twice as far from the sun as earth does, what is its orbital period in earth years?\

can someone help me with explaining part B?

Those are the answers I got, can someone make sure they are correct?

Chapter 17 Solutions

Physics

Ch. 17.1 - 17.1 Two Point Charges with Like Signs Two point...Ch. 17.1 - Prob. 17.1CP Ch. 17.1 - Prob. 17.2PP Ch. 17.2 - Prob. 17.2CP Ch. 17.2 - Prob. 17.3PP Ch. 17.2 - Prob. 17.4PP Ch. 17.2 - Prob. 17.5PP Ch. 17.2 - Prob. 17.6PP Ch. 17.3 - Conceptual Practice Problem 17.7 Equipotential...Ch. 17.3 - Prob. 17.3CP

Ch. 17.4 - Prob. 17.8PP Ch. 17.5 - Prob. 17.5CP Ch. 17.5 - Prob. 17.9PP Ch. 17.6 - Prob. 17.6CP Ch. 17.6 - Prob. 17.10PP Ch. 17.6 - Prob. 17.11PP Ch. 17.7 - Practice Problem 17.12 Charge and Stored Energy...Ch. 17 - Prob. 1CQ Ch. 17 - 2. Dry air breaks down for a voltage of about 3000...Ch. 17 - 3. A bird is perched on a high-voltage power line...Ch. 17 - 4. A positive charge is initially at rest in an...Ch. 17 - 5. Points A and B are at the same potential. What...Ch. 17 - Prob. 6CQ Ch. 17 - 7. Why are all parts of a conductor at the same...Ch. 17 - Prob. 8CQ Ch. 17 - Prob. 9CQ Ch. 17 - Prob. 11CQ Ch. 17 - Prob. 12CQ Ch. 17 - Prob. 13CQ Ch. 17 - Prob. 14CQ Ch. 17 - Prob. 15CQ Ch. 17 - Prob. 16CQ Ch. 17 - Prob. 17CQ Ch. 17 - Prob. 18CQ Ch. 17 - Prob. 19CQ Ch. 17 - Prob. 20CQ Ch. 17 - Prob. 21CQ Ch. 17 - Prob. 10CQ Ch. 17 - Prob. 1MCQ Ch. 17 - Prob. 2MCQ Ch. 17 - Prob. 3MCQ Ch. 17 - Prob. 4MCQ Ch. 17 - Prob. 5MCQ Ch. 17 - Prob. 6MCQ Ch. 17 - Prob. 7MCQ Ch. 17 - Prob. 8MCQ Ch. 17 - Prob. 9MCQ Ch. 17 - Prob. 10MCQ Ch. 17 - Prob. 11MCQ Ch. 17 - Prob. 12MCQ Ch. 17 - 1. In each of five situations, two point charges...Ch. 17 - 2. Two point charges, +5.0 μC and −2.0 μC, are...Ch. 17 - 3. A hydrogen atom has a single proton at its...Ch. 17 - 4. How much work is done by an applied force that...Ch. 17 - 5. The nucleus of a helium atom contains two...Ch. 17 - 6. Three point charges are located at the corners...Ch. 17 - Problems 7-10. Two point charges ( + 10.0 nC and −...Ch. 17 - Problems 7-10. Two point charges ( + 10.0 nC and −...Ch. 17 - Problems 7-10. Two point charges ( + 10.0 nC and −...Ch. 17 - Problems 7–10. Two point charges ( +10.0 nC and...Ch. 17 - 11. Find the electric potential energy for the...Ch. 17 - 12. In the diagram, how much work is done by the...Ch. 17 - 13. In the diagram, how much work is done by the...Ch. 17 - Prob. 14P Ch. 17 - Prob. 15P Ch. 17 - 16. A point charge q = + 3.0 nC moves through a...Ch. 17 - 17. An electron is moved from point A, where the...Ch. 17 - 18. Find the electric field and the potential at...Ch. 17 - Prob. 19P Ch. 17 - 20. A charge of + 2.0 mC is located at x = 0, y =...Ch. 17 - 21. The electric potential at a distance of 20.0...Ch. 17 - 22. A spherical conductor with a radius of 75.0 cm...Ch. 17 - 23. A hollow metal sphere carries a charge of 6.0...Ch. 17 - 24. An array of four charges is arranged along the...Ch. 17 - 25. At a point P, a distance R0 from a positive...Ch. 17 - 26. Charges of + 2.0 nC and − 1.0 nC are located...Ch. 17 - Prob. 27P Ch. 17 - 28. (a) Find the potential at points a and b in...Ch. 17 - 29. (a) In the diagram, what are the potentials at...Ch. 17 - 30. (a) In the diagram, what are the potentials at...Ch. 17 - Prob. 31P Ch. 17 - 32. By rewriting each unit in terms of kilograms,...Ch. 17 - 33. Rank points A–E in order of the potential,...Ch. 17 - Prob. 34P Ch. 17 - Prob. 35P Ch. 17 - Prob. 36P Ch. 17 - Prob. 37P Ch. 17 - Prob. 38P Ch. 17 - Prob. 39P Ch. 17 - Prob. 40P Ch. 17 - Prob. 41P Ch. 17 - Prob. 43P Ch. 17 - 43. A positive point charge is located at the...Ch. 17 - Prob. 44P Ch. 17 - Prob. 45P Ch. 17 - 46. Point P is at a potential of 500.0 kV, and...Ch. 17 - 47. An electron is accelerated from rest through a...Ch. 17 - 48. As an electron moves through a region of...Ch. 17 - Prob. 49P Ch. 17 - 50. An electron beam is deflected upward through...Ch. 17 - 51. In the electron gun of Example 17.8, if the...Ch. 17 - 52. In the electron gun of Example 17.8, if the...Ch. 17 - 53. An electron (charge −e) is projected...Ch. 17 - 54. An alpha particle (charge +2e) moves through a...Ch. 17 - 55. In 1911, Ernest Rutherford discovered the...Ch. 17 - 56. The figure shows a graph of electric potential...Ch. 17 - 57. Repeat Problem 56 for an electron rather than...Ch. 17 - 58. A 2.0 μE capacitor is connected to a 9.0 V...Ch. 17 - 59. The plates of a 15.0 μE capacitor have net...Ch. 17 - 60. If a capacitor has a capacitance of 10.2 μE...Ch. 17 - 61. A parallel plate capacitor has a capacitance...Ch. 17 - 62. A parallel plate capacitor has plates of area...Ch. 17 - 63. A parallel plate capacitor has plates of area...Ch. 17 - Prob. 64P Ch. 17 - Prob. 65P Ch. 17 - Prob. 66P Ch. 17 - Prob. 67P Ch. 17 - Prob. 68P Ch. 17 - Prob. 69P Ch. 17 - Prob. 70P Ch. 17 - Prob. 71P Ch. 17 - Prob. 72P Ch. 17 - Prob. 73P Ch. 17 - Prob. 74P Ch. 17 - Prob. 75P Ch. 17 - Prob. 76P Ch. 17 - Prob. 77P Ch. 17 - 78. What is the maximum electric energy density...Ch. 17 - Prob. 79P Ch. 17 - Prob. 80P Ch. 17 - Prob. 81P Ch. 17 - Prob. 82P Ch. 17 - Prob. 83P Ch. 17 - 84. A parallel plate capacitor is composed of two...Ch. 17 - Prob. 85P Ch. 17 - 86. A parallel plate capacitor has a charge of...Ch. 17 - Prob. 87P Ch. 17 - Prob. 88P Ch. 17 - Prob. 89P Ch. 17 - Prob. 90P Ch. 17 - Prob. 91P Ch. 17 - Prob. 92P Ch. 17 - Prob. 93P Ch. 17 - Prob. 94P Ch. 17 - Prob. 95P Ch. 17 - Prob. 96P Ch. 17 - Prob. 97P Ch. 17 - Prob. 98P Ch. 17 - Prob. 99P Ch. 17 - Prob. 100P Ch. 17 - Prob. 101P Ch. 17 - Prob. 102P Ch. 17 - Prob. 103P Ch. 17 - Prob. 104P Ch. 17 - Prob. 105P Ch. 17 - 106. ✦ The potential difference across a cell...Ch. 17 - Prob. 107P Ch. 17 - Prob. 108P Ch. 17 - Prob. 109P Ch. 17 - Prob. 110P Ch. 17 - Prob. 111P Ch. 17 - Prob. 112P Ch. 17 - Prob. 113P Ch. 17 - Prob. 114P Ch. 17 - Prob. 115P Ch. 17 - Prob. 116P Ch. 17 - Prob. 117P Ch. 17 - Prob. 118P Ch. 17 - Prob. 119P Ch. 17 - Prob. 120P Ch. 17 - Prob. 121P Ch. 17 - Prob. 122P Ch. 17 - Prob. 123P Ch. 17 - Prob. 124P Ch. 17 - An air ionizer fillers particles of dust, pollen,...Ch. 17 - Prob. 126P Ch. 17 - Prob. 127P Ch. 17 - Prob. 128P Ch. 17 - Prob. 129P

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.