(a) Explanation The energy stored in the capacitor is 450 J and the charge on the capacitor is 8.0 × 10 − 2 C . Write the expression for energy stored in the capacitor U = Q 2 2 C (I) Here, Q is the magnitude of charge on each plate of the capacitor, C is the capacitance of the capacitor and U is the energy stored in the capacitor. Rearrange (I) for C C = Q 2 2 U (II) Substitute 8 (b) To determine The potential difference between the plates.

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ISBN: 9781260486919

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Chapter 17, Problem 77P

(a)

To determine

The capacitance of the capacitor.

(b)

To determine

The potential difference between the plates.

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Chapter 17, Problem 76P

Chapter 17, Problem 78P

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Ch. 17.1 - 17.1 Two Point Charges with Like Signs Two point...Ch. 17.1 - Prob. 17.1CP Ch. 17.1 - Prob. 17.2PP Ch. 17.2 - Prob. 17.2CP Ch. 17.2 - Prob. 17.3PP Ch. 17.2 - Prob. 17.4PP Ch. 17.2 - Prob. 17.5PP Ch. 17.2 - Prob. 17.6PP Ch. 17.3 - Conceptual Practice Problem 17.7 Equipotential...Ch. 17.3 - Prob. 17.3CP

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