In the following exercises, solve for the antiderivative ∫ f of with C = 0, the given interval [a, b]. Approximate a value of C, if possible, such that adding C to the antidelivative gives the same value as the definite integral F ( x ) = ∫ a x f ( t ) d t . 417. [T] ∫ 1 x x 2 − 4 d x over [2, 6]
In the following exercises, solve for the antiderivative ∫ f of with C = 0, the given interval [a, b]. Approximate a value of C, if possible, such that adding C to the antidelivative gives the same value as the definite integral F ( x ) = ∫ a x f ( t ) d t . 417. [T] ∫ 1 x x 2 − 4 d x over [2, 6]
In the following exercises, solve for the antiderivative
∫
f
of with C = 0, the given interval [a, b]. Approximate a value of C, if possible, such that adding C to the antidelivative gives the same value as the definite integral
F
(
x
)
=
∫
a
x
f
(
t
)
d
t
.
417. [T]
∫
1
x
x
2
−
4
d
x
over [2, 6]
With differentiation, one of the major concepts of calculus. Integration involves the calculation of an integral, which is useful to find many quantities such as areas, volumes, and displacement.
Q2*) In question P3 we showed that a minimal surface of revolution is given by revolution (about the x-axis)
of the catenary, with equation y = C cosh ((x – B)/C).
-
(a) Suppose, without loss of generality, that the catenary passes through the initial point
P = (x1,y1) = (0, 1). First deduce an expression for the one-parameter family of catenaries passing
through point P. Next calculate the value of x at which y takes its minimum value. By using the inequality
cosh > √2
(you might like to think about how to prove this), show that there are points Q for which it is impossible to find
a catenary passing through both P and Q. In particular, show that it is impossible to find a catenary joining
the points (0, 1) and (2, 1).
(b) A minimal surface of revolution can be realised experimentally by soap films attached to circular wire
frames (see this link and this link for examples). The physical reason for this is that the surface tension, which
is proportional to the area, is being minimised.…
Q3*) Consider the integral
I
Yn, Y₁, Y2, . . ., Y'n) dã,
[F(x, Y 1, Y2, · · Yng)
= -
where y1, 2, ...y are dependent variables, dependent on x. If F is not explicitly dependent on x, deduce
the equivalent of the Beltrami identity. Optional: Give an example of a function F(y1, Y2, Y₁, y2), and write
down the Euler-Lagrange equations and Beltrami Identity for your example. Does having this Beltrami Identity
help solve the problem?
Write an integral that is approximated by the following Riemann sum. Substitute a
into the Riemann sum below where a is the last non-zero digit of your banner ID.
You do not need to evaluate the integral.
2000
(10
1
((10-a) +0.001) (0.001)
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, subject and related others by exploring similar questions and additional content below.
Fundamental Theorem of Calculus 1 | Geometric Idea + Chain Rule Example; Author: Dr. Trefor Bazett;https://www.youtube.com/watch?v=hAfpl8jLFOs;License: Standard YouTube License, CC-BY