The sine integral , defined as S ( x ) = ∫ 0 x sin t t d t is an important quantity in engineering. Although it does not have a simple closed formula, it is possible to estimate its behavior for large x. Show that for k ≥ 1 , | S ( 2 π k ) − S ( 2 π ( k + 1 ) ) | ≤ 1 k ( 2 k + 1 ) π . (Hint: sin ( t + π ) = − sin t )
The sine integral , defined as S ( x ) = ∫ 0 x sin t t d t is an important quantity in engineering. Although it does not have a simple closed formula, it is possible to estimate its behavior for large x. Show that for k ≥ 1 , | S ( 2 π k ) − S ( 2 π ( k + 1 ) ) | ≤ 1 k ( 2 k + 1 ) π . (Hint: sin ( t + π ) = − sin t )
The sine integral, defined as
S
(
x
)
=
∫
0
x
sin
t
t
d
t
is an important quantity in engineering. Although it does not have a simple closed formula, it is possible to estimate its behavior for large x. Show that for
k
≥
1
,
|
S
(
2
π
k
)
−
S
(
2
π
(
k
+
1
)
)
|
≤
1
k
(
2
k
+
1
)
π
. (Hint:
sin
(
t
+
π
)
=
−
sin
t
)
With differentiation, one of the major concepts of calculus. Integration involves the calculation of an integral, which is useful to find many quantities such as areas, volumes, and displacement.
7. Show that for R sufficiently large, the polynomial P(z) in Example 3, Sec. 5, satisfies
the inequality
|P(z)| R.
Suggestion: Observe that there is a positive number R such that the modulus of
each quotient in inequality (9), Sec. 5, is less than |an|/n when |z| > R.
9. Establish the identity
1-
1+z+z² +
2n+1
...
+z" =
1- z
(z1)
and then use it to derive Lagrange's trigonometric identity:
1
1+ cos cos 20 +... + cos no =
+
2
sin[(2n+1)0/2]
2 sin(0/2)
(0 < 0 < 2л).
Suggestion: As for the first identity, write S = 1+z+z² +...+z" and consider
the difference S - zS. To derive the second identity, write z =
eie in the first one.
8. Prove that two nonzero complex numbers z₁ and Z2 have the same moduli if and only if
there are complex numbers c₁ and c₂ such that Z₁ = c₁C2 and Z2 = c1c2.
Suggestion: Note that
(i≤
exp (101+0) exp (01-02)
and [see Exercise 2(b)]
2
02
Ꮎ
-
= = exp(i01)
exp(101+0) exp (i 01 - 02 ) = exp(102).
i
2
2
University Calculus: Early Transcendentals (4th Edition)
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