The solution of the inequality − 1 < 2 − x 3 < 1 and graph the solution set. The solution set of the inequality − 1 < 2 − x 3 < 1 is 3 < x < 9 . Calculation: The given inequality is − 1 < 2 − x 3 < 1 . Subtract 2 from each part using the addition of the constant property of the inequality, which says that if a < b , then a < b becomes a + c < b + c . − 3 < − x 3 < − 1 Multiply each part by − 3 using the multiplication property of the inequality, which says that if c > 0 , then a < b becomes a c < b c and if c < 0 , then a > b becomes a c < b c . 9 > x > 3 3 < x < 9 So, the solution set of the inequality is all real numbers, which are greater than 3 and less than 9, denoted by 3 , 9 . Graph: The graph of the solution set is shown as: The parenthesis at x = 3 and x = 9 means that the point is not included in the solution set.
The solution of the inequality − 1 < 2 − x 3 < 1 and graph the solution set. The solution set of the inequality − 1 < 2 − x 3 < 1 is 3 < x < 9 . Calculation: The given inequality is − 1 < 2 − x 3 < 1 . Subtract 2 from each part using the addition of the constant property of the inequality, which says that if a < b , then a < b becomes a + c < b + c . − 3 < − x 3 < − 1 Multiply each part by − 3 using the multiplication property of the inequality, which says that if c > 0 , then a < b becomes a c < b c and if c < 0 , then a > b becomes a c < b c . 9 > x > 3 3 < x < 9 So, the solution set of the inequality is all real numbers, which are greater than 3 and less than 9, denoted by 3 , 9 . Graph: The graph of the solution set is shown as: The parenthesis at x = 3 and x = 9 means that the point is not included in the solution set.
Solution Summary: The author calculates the solution of the inequality -12-x31 and graphs its solution set.
To calculate: The solution of the inequality −1<2−x3<1 and graph the solution set.
The solution set of the inequality −1<2−x3<1 is 3<x<9.
Calculation:
The given inequality is −1<2−x3<1.
Subtract 2 from each part using the addition of the constant property of the inequality, which says that if a<b, then a<b becomes a+c<b+c.
−3<−x3<−1
Multiply each part by −3 using the multiplication property of the inequality, which says that if c>0, then a<b becomes ac<bc and if c<0, then a>b becomes ac<bc.
9>x>33<x<9
So, the solution set of the inequality is all real numbers, which are greater than 3 and less than 9, denoted by 3,9.
Graph:
The graph of the solution set is shown as:
The parenthesis at x=3 and x=9 means that the point is not included in the solution set.
1.
vector projection.
Assume, ER1001 and you know the following:
||||=4, 7=-0.5.7.
For each of the following, explicitly compute the value.
འབ
(a)
(b)
(c)
(d)
answer.
Explicitly compute ||y7||. Explain your answer.
Explicitly compute the cosine similarity of and y. Explain your
Explicitly compute (x, y). Explain your answer.
Find the projection of onto y and the projection of onto .
2.
Answer the following questions using vectors u and v.
--0-0-0
=
find the the cosine similarity and the angle between u and v.
འརྒྱ
(a)
(b)
find the scalar projection of u onto v.
(c)
find the projection of u onto v.
(d)
(e)
(f)
find the scalar projection of onto u.
find the projection of u onto u.
find the projection of u onto and the projection of onto . (Hint:
find the inner product and verify the orthogonality)
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, algebra and related others by exploring similar questions and additional content below.