The solution of the inequality − 1 ≤ − 3 x + 5 7 ≤ 2 and to graph the solution set. The solution set of the inequality − 1 ≤ − 3 x + 5 7 ≤ 2 is − 3 ≤ x ≤ 4 . Calculation: The given inequality is − 1 ≤ − 3 x + 5 7 ≤ 2 . Multiply each part by 7 using the multiplication property of the inequality, which says that if c > 0 , then a < b becomes a c < b c and if c < 0 , then a > b becomes a c < b c . − 7 ≤ − 3 x + 5 ≤ 14 Subtract 5 from each part using the addition of the constant property of inequality, which says that if a < b , then a < b becomes a + c < b + c . − 12 ≤ − 3 x ≤ 9 Divide each part by − 3 using the multiplication property of the inequality, which says that if c > 0 , then a < b becomes a c < b c and if c < 0 , then a > b becomes a c < b c . 4 ≥ x ≥ − 3 − 3 ≤ x ≤ 4 The solution set of the inequality is all real numbers, which are greater than or equal to − 3 and less than or equal to 4 , denoted by − 3 , 4 . Graph: The graph of the solution set is shown as: The bracket at x = − 3 and x = 4 means that the point is included in the solution set.
The solution of the inequality − 1 ≤ − 3 x + 5 7 ≤ 2 and to graph the solution set. The solution set of the inequality − 1 ≤ − 3 x + 5 7 ≤ 2 is − 3 ≤ x ≤ 4 . Calculation: The given inequality is − 1 ≤ − 3 x + 5 7 ≤ 2 . Multiply each part by 7 using the multiplication property of the inequality, which says that if c > 0 , then a < b becomes a c < b c and if c < 0 , then a > b becomes a c < b c . − 7 ≤ − 3 x + 5 ≤ 14 Subtract 5 from each part using the addition of the constant property of inequality, which says that if a < b , then a < b becomes a + c < b + c . − 12 ≤ − 3 x ≤ 9 Divide each part by − 3 using the multiplication property of the inequality, which says that if c > 0 , then a < b becomes a c < b c and if c < 0 , then a > b becomes a c < b c . 4 ≥ x ≥ − 3 − 3 ≤ x ≤ 4 The solution set of the inequality is all real numbers, which are greater than or equal to − 3 and less than or equal to 4 , denoted by − 3 , 4 . Graph: The graph of the solution set is shown as: The bracket at x = − 3 and x = 4 means that the point is included in the solution set.
Solution Summary: The author calculates the solution of the inequality -1le -3x+57 le 2 and graphs it.
To calculate: The solution of the inequality −1≤−3x+57≤2 and to graph the solution set.
The solution set of the inequality −1≤−3x+57≤2 is −3≤x≤4.
Calculation:
The given inequality is −1≤−3x+57≤2.
Multiply each part by 7 using the multiplication property of the inequality, which says that if c>0, then a<b becomes ac<bc and if c<0, then a>b becomes ac<bc.
−7≤−3x+5≤14
Subtract 5 from each part using the addition of the constant property of inequality, which says that if a<b, then a<b becomes a+c<b+c.
−12≤−3x≤9
Divide each part by −3 using the multiplication property of the inequality, which says that if c>0, then a<b becomes ac<bc and if c<0, then a>b becomes ac<bc.
4≥x≥−3−3≤x≤4
The solution set of the inequality is all real numbers, which are greater than or equal to −3 and less than or equal to 4, denoted by −3,4.
Graph:
The graph of the solution set is shown as:
The bracket at x=−3 and x=4 means that the point is included in the solution set.
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