The solution of the given inequality, − 1 ≤ − x − 4 < 7 , and graph the solution set. The solution set of the given inequality, − 1 ≤ − x − 4 < 7 , is − 3 < x ≤ 5 . Calculation: Consider the given inequality, − 1 ≤ − x − 4 < 7 . Multiply each part by − 1 by using the multiplicative property of an inequality, according to which, if c > 0 , then a < b becomes a c < b c and if c < 0 , then a > b becomes a c < b c . 1 ≥ x − 4 > − 7 Add 4 from each part by using the property of addition of a constant to an inequality, according to which, if a < b , then a < b becomes a + c < b + c . 5 ≥ x > − 3 − 3 < x ≤ 5 The solution set of the given inequality is the set of all real numbers that are greater than − 3 and less than or equal to 5 which can be denoted by − 3 , 5 . Graph: The solution set of the inequality is shown in the graph. The parenthesis at x = − 3 means that this point is not included in the solution set. The bracket at x = 5 means that this point is included in the solution set.
The solution of the given inequality, − 1 ≤ − x − 4 < 7 , and graph the solution set. The solution set of the given inequality, − 1 ≤ − x − 4 < 7 , is − 3 < x ≤ 5 . Calculation: Consider the given inequality, − 1 ≤ − x − 4 < 7 . Multiply each part by − 1 by using the multiplicative property of an inequality, according to which, if c > 0 , then a < b becomes a c < b c and if c < 0 , then a > b becomes a c < b c . 1 ≥ x − 4 > − 7 Add 4 from each part by using the property of addition of a constant to an inequality, according to which, if a < b , then a < b becomes a + c < b + c . 5 ≥ x > − 3 − 3 < x ≤ 5 The solution set of the given inequality is the set of all real numbers that are greater than − 3 and less than or equal to 5 which can be denoted by − 3 , 5 . Graph: The solution set of the inequality is shown in the graph. The parenthesis at x = − 3 means that this point is not included in the solution set. The bracket at x = 5 means that this point is included in the solution set.
Solution Summary: The author calculates the solution set of the given inequality, -1le -(x-4)7, and graphs it.
To calculate: The solution of the given inequality, −1≤−x−4<7, and graph the solution set.
The solution set of the given inequality, −1≤−x−4<7, is −3<x≤5.
Calculation:
Consider the given inequality, −1≤−x−4<7.
Multiply each part by −1 by using the multiplicative property of an inequality, according to which, if c>0, then a<b becomes ac<bc and if c<0, then a>b becomes ac<bc.
1≥x−4>−7
Add 4 from each part by using the property of addition of a constant to an inequality, according to which, if a<b, then a<b becomes a+c<b+c.
5≥x>−3−3<x≤5
The solution set of the given inequality is the set of all real numbers that are greater than −3 and less than or equal to 5 which can be denoted by −3,5.
Graph:
The solution set of the inequality is shown in the graph.
The parenthesis at x=−3 means that this point is not included in the solution set.
The bracket at x=5 means that this point is included in the solution set.
1.
vector projection.
Assume, ER1001 and you know the following:
||||=4, 7=-0.5.7.
For each of the following, explicitly compute the value.
འབ
(a)
(b)
(c)
(d)
answer.
Explicitly compute ||y7||. Explain your answer.
Explicitly compute the cosine similarity of and y. Explain your
Explicitly compute (x, y). Explain your answer.
Find the projection of onto y and the projection of onto .
2.
Answer the following questions using vectors u and v.
--0-0-0
=
find the the cosine similarity and the angle between u and v.
འརྒྱ
(a)
(b)
find the scalar projection of u onto v.
(c)
find the projection of u onto v.
(d)
(e)
(f)
find the scalar projection of onto u.
find the projection of u onto u.
find the projection of u onto and the projection of onto . (Hint:
find the inner product and verify the orthogonality)
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