The graph of length versus temperature for mercury. Given: The length of column of mercury in the thermometer is 4 cm . The pressure of water is 1 atm The length of column of mercury in the thermometer is 4 cm . The thermometer in the boiling water is 24 cm . Introduction: Explanation: The graph of length of the mercury column versus temperature is: The equation for the graph is: L = m T + C Here, L is the length in cm , T is the temperature in Celsius and C is the intercept. Substitute 0.200 cm / °C for m and 4.0 cm for C in equation (1). L = ( 0.200 cm / °C ) T + 4.0 cm Conclusion:

Question

Want to see the full answer?

Answer 1

Question

Chapter 17, Problem 35P

(a)

To determine

The graph of length versus temperature for mercury.

Given:

The length of column of mercury in the thermometer is 4 cm .

The pressure of water is 1 atm

The length of column of mercury in the thermometer is 4 cm .

The thermometer in the boiling water is 24 cm .

Introduction:

Explanation:

The graph of length of the mercury column versus temperature is:

The equation for the graph is:

L=mT+C

Here, L is the length in cm , T is the temperature in Celsius and C is the intercept.

Substitute 0.200 cm/°C for m and 4.0 cm for C in equation (1).

L=(0.200 cm/°C)T+4.0 cm

Conclusion:

(b)

To determine

The length of the column when the temperature is 22.0 °C .

(b)

To determine

The temperature when the length of the mercury column is 25.4 cm .

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

For each of the actions depicted below, a magnet and/or metal loop moves with velocity v→ (v→ is constant and has the same magnitude in all parts). Determine whether a current is induced in the metal loop. If so, indicate the direction of the current in the loop, either clockwise or counterclockwise when seen from the right of the loop. The axis of the magnet is lined up with the center of the loop. For the action depicted in (Figure 5), indicate the direction of the induced current in the loop (clockwise, counterclockwise or zero, when seen from the right of the loop). I know that the current is clockwise, I just dont understand why. Please fully explain why it's clockwise, Thank you

A planar double pendulum consists of two point masses \[m_1 = 1.00~\mathrm{kg}, \qquad m_2 = 1.00~\mathrm{kg}\]connected by massless, rigid rods of lengths \[L_1 = 1.00~\mathrm{m}, \qquad L_2 = 1.20~\mathrm{m}.\]The upper rod is hinged to a fixed pivot; gravity acts vertically downward with\[g = 9.81~\mathrm{m\,s^{-2}}.\]Define the generalized coordinates \(\theta_1,\theta_2\) as the angles each rod makes with thedownward vertical (positive anticlockwise, measured in radians unless stated otherwise).At \(t=0\) the system is released from rest with \[\theta_1(0)=120^{\circ}, \qquad\theta_2(0)=-10^{\circ}, \qquad\dot{\theta}_1(0)=\dot{\theta}_2(0)=0 .\]Using the exact nonlinear equations of motion (no small-angle or planar-pendulumapproximations) and assuming the rods never stretch or slip, determine the angle\(\theta_2\) at the instant\[t = 10.0~\mathrm{s}.\]Give the result in degrees, in the interval \((-180^{\circ},180^{\circ}]\).

What are the expected readings of the ammeter and voltmeter for the circuit in the figure below? (R = 5.60 Ω, ΔV = 6.30 V) ammeter I =