Electronics Fundamentals: Circuits, Devices & Applications
8th Edition
ISBN: 9780135072950
Author: Thomas L. Floyd, David Buchla
Publisher: Prentice Hall
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Textbook Question
Chapter 17, Problem 2ST
The n-region in a pnp transistor is the
- base
- collector
- emitter
- case
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PSD
A certain signal f(t) has the following PSD (assume 12 load):
| Sƒ(w) = π[e¯\w\ + 8(w − 2) + +8(w + 2)]
(a) What is the mean power in the bandwidth w≤ 1 rad/sec?
(b) What is the mean power in the bandwidth 0.99 to 1.01 rad/sec?
(c) What is the mean power in the bandwidth 1.99 to 2.01 rad/sec?
(d) What is the total mean power in (t)?
Pav=
+
2T
SfLw) dw
- SALW)
Chapter 17 Solutions
Electronics Fundamentals: Circuits, Devices & Applications
Ch. 17 - In a bipolar transistor, if the base-emitter...Ch. 17 - When a transistor is saturated. an increase in...Ch. 17 - Prob. 3TFQCh. 17 - The power gain of a CC amplifier is the same as...Ch. 17 - A class B amplifier is more efficient than a class...Ch. 17 - A JFET is always operated with the gate-source...Ch. 17 - Prob. 7TFQCh. 17 - The transconductance of a FET is the ratio of ac...Ch. 17 - Prob. 9TFQCh. 17 - The input to a feedback oscillator is only the...
Ch. 17 - The n-type regions in an npn bipolar junction...Ch. 17 - The n-region in a pnp transistor is the base...Ch. 17 - Prob. 3STCh. 17 - Prob. 4STCh. 17 - Prob. 5STCh. 17 - Alpha () is the ratio of collector current to...Ch. 17 - If the beta of a certain transistor operating in...Ch. 17 - If the base current of a transistor operating in...Ch. 17 - Prob. 9STCh. 17 - When the gate-to-source voltage of an n-channel...Ch. 17 - When a negative gate-to-source voltage is applied...Ch. 17 - Prob. 12STCh. 17 - If the capacitor from emitter to ground in a CE...Ch. 17 - When the collector resistor in a CE amplifier is...Ch. 17 - The input resistance of a CE amplifier is affected...Ch. 17 - The output signal of a CE amplifier is always in...Ch. 17 - The output signal of a common-collector amplifier...Ch. 17 - The largest theoretical voltage gain obtainable...Ch. 17 - In a class A amplifier, the output signal is...Ch. 17 - A class A amplifier conducts for 90 of input cycle...Ch. 17 - Prob. 21STCh. 17 - Feedback oscillators operate on the principle of...Ch. 17 - What is the value of IC for IE=5.34mA and IB=475A?Ch. 17 - Prob. 2PCh. 17 - Prob. 3PCh. 17 - In a certain transistor circuit, the base current...Ch. 17 - Find IB,IE, and in Figure 17-70 given that DC=0.98...Ch. 17 - The transistor in Figure 17-70 is replaced with...Ch. 17 - Prob. 7PCh. 17 - Prob. 8PCh. 17 - Determine IB,IC, and VC in Figure 17-72.Ch. 17 - For the circuit in Figure 17-73, find VB,VE,IE,IC,...Ch. 17 - In Figure 17-73, what is VCE? What are the Q-point...Ch. 17 - A transistor amplifier has a voltage gain of 50....Ch. 17 - To achieve an output of 10 V with an input of300...Ch. 17 - A 50 mV signal is applied to the base of a...Ch. 17 - Determine the voltage gain for Figure 17-74.Ch. 17 - Determine each of the dc voltages, VB,VC, and VE,...Ch. 17 - Determine the following dc values for the...Ch. 17 - Determine the following ac values for the...Ch. 17 - The amplifier in Figure 17-76 has a variable gain...Ch. 17 - If a load resistance of 600 is placed on the...Ch. 17 - Determine the voltage gain for the...Ch. 17 - What is the total input resistance in Figure...Ch. 17 - A load resistance is capacitively coupled in the...Ch. 17 - Prob. 24PCh. 17 - Determine the maximum peak output voltage and peak...Ch. 17 - The efficiency of a certain class B push-pull...Ch. 17 - Prob. 27PCh. 17 - The transistor in Figure 17-80 has a DC of 150....Ch. 17 - The VGS of ap-channel JFET is increased from 1 V...Ch. 17 - Why must the gate-to-source voltage of an...Ch. 17 - Draw the schematic symbols for n-channel and...Ch. 17 - Explain why both types of MOSFETs have an...Ch. 17 - In what mode is an n-channel D-MOSFET operating...Ch. 17 - A certain E-MOSFET has a VGS(th)=3V. What is the...Ch. 17 - For each circuit in Figure 17-81, determine VDS...Ch. 17 - Prob. 36PCh. 17 - Each E-MOSFET in Figure 17-83 has a VGS(th) of +5...Ch. 17 - Prob. 38PCh. 17 - Find the gain of each amplifier in Figure 17-85.Ch. 17 - Determine the gain of each amplifier in Figure...Ch. 17 - If the voltage gain of the amplifier portion of a...Ch. 17 - Generally describe the change required to the...Ch. 17 - Prob. 43PCh. 17 - Prob. 44PCh. 17 - Prob. 47PCh. 17 - Prob. 48PCh. 17 - Prob. 49PCh. 17 - Prob. 50PCh. 17 - Prob. 51PCh. 17 - Prob. 52PCh. 17 - Open file P17-53. Determine if the circuit is...
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- An AM modulation waveform signal:- p(t)=(8+4 cos 1000πt + 4 cos 2000πt) cos 10000nt (a) Sketch the amplitude spectrum of p(t). (b) Find total power, sideband power and power efficiency. (c) Find the average power containing of each sideband.arrow_forwardCan you rewrite the solution because it is unclear? AM (+) = 8(1+ 0.5 cos 1000kt +0.5 ros 2000ks) = cos 10000 πt. 8 cos wat + 4 cos wit + 4 cos Wat coswet. -Jet jooort J11000 t = 4 e jqooort jgoort +4e + e +e j 12000rt. 12000 kt + e +e jooxt igoo t te (w) = 8ES(W- 100007) + 8IS (W-10000) USBarrow_forwardCan you rewrite the solution because it is unclear? AM (+) = 8(1+0.5 cos 1000kt +0.5 ros 2000 thts) = cos 10000 πt. 8 cos wat + 4 cos wit + 4 cos Wat coswet. J4000 t j11000rt $14+) = 45 jqooort +4e + e + e j 12000rt. 12000 kt + e +e +e Le jsoort -; goon t te +e Dcw> = 885(W- 100007) + 8 IS (W-10000) - USBarrow_forward
- Can you rewrite the solution because it is unclear? Q2 AM ①(+) = 8 (1+0.5 cos 1000πt +0.5 ros 2000kt) $4+) = 45 = *cos 10000 πt. 8 cos wat + 4 cosat + 4 cos Wat coswet. j1000016 +4e -j10000πt j11000Rt j gooort -j 9000 πt + e +e j sooort te +e J11000 t + e te j 12000rt. -J12000 kt + с = 8th S(W- 100007) + 8 IS (W-10000) <&(w) = USB -5-5 -4-5-4 b) Pc 2² = 64 PSB = 42 + 4 2 Pt Pc+ PSB = y = Pe c) Puss = PLSB = = 32 4² = 8 w 32+ 8 = × 100% = 140 (1)³×2×2 31 = 20% x 2 = 3w 302 USB 4.5 5 5.6 6 ms Ac = 4 mi = 0.5 mz Ac = 4 ५ M2 = =0.5arrow_forwardA. Draw the waveform for the following binary sequence using Bipolar RZ, Bipolar NRZ, and Manchester code. Data sequence= (00110100) B. In a binary PCM system, the output signal-to-quantization ratio is to be hold to a minimum of 50 dB. If the message is a single tone with fm-5 kHz. Determine: 1) The number of required levels, and the corresponding output signal-to-quantizing noise ratio. 2) Minimum required system bandwidth.arrow_forwardFind Io using Mesh analysisarrow_forward
- FM station of 100 MHz carrier frequency modulated by a 20 kHz sinusoid with an amplitude of 10 volt, so that the peak frequency deviation is 25 kHz determine: 1) The BW of the FM signal. 2) The approximated BW if the modulating signal amplitude is increased to 50 volt. 3) The approximated BW if the modulating signal frequency is increased by 70%. 4) The amplitude of the modulating signal if the BW is 65 kHz.arrow_forwardAn FDM is used to multiplex two groups of signals using AM-SSB, the first group contains 25 speech signals, each has maximum frequency of 4 kHz, the second group contains 15 music signals, each has maximum frequency of 10 kHz. A guard bandwidth of 500 Hz is used bety each two signals and before the first one. 1. Find the BWmultiplexing 2. Find the BWtransmission if the multiplexing signal is modulated using AM-DSB-LC.arrow_forwardAn FM signal with 75 kHz deviation, has an input signal-to-noise ratio of 18 dB, with a modulating frequency of 15 kHz. 1) Find SNRO at demodulator o/p. 2) Find SNRO at demodulator o/p if AM is used with m=0.3. 3) Compare the performance in case 1) and 2).. Hint: for single tone AM-DSB-LC, SNR₁ = (2m²) (4)arrow_forward
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