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(a)
Interpretation:The equilibrium expression of
Concept introduction: Heterogeneous equilibrium can be defined as equilibrium where the components (reactants and products) are present in different phases.
(a)
Answer to Problem 25A
The equilibrium expression is
Explanation of Solution
Equilibrium expressions used to determine the changes in concentration that happens as the reaction approaches equilibrium. Aqueous solutions and gases change their concentrations considerably during the course of reaction. On the other hand, pure liquids and solids do not change their concentration much as reaction moves towards equilibrium since they are present in large excess.
Hence pure liquids and solids are not included in equilibrium expression equation.
The reaction is:
The equilibrium expression is
(b)
Interpretation: The equilibrium expression of heterogeneous equilibrium needs to be determined.
Concept introduction: Heterogeneous equilibrium can be defined as equilibrium where the components (reactants and products) are present in different phases.
(b)
Answer to Problem 25A
The equilibrium expression is
Explanation of Solution
Equilibrium expressions used to determine the changes in concentration that happens as the reaction approaches equilibrium. Aqueous solutions and gases change their concentrations considerably during the course of reaction. On the other hand, pure liquids and solids do not change their concentration much as reaction moves towards equilibrium since they are present in large excess.
Hence pure liquids and solids are not included in equilibrium expression equation.
The reaction is:
The equilibrium expression is
(c)
Interpretation: The equilibrium expression of heterogeneous equilibrium needs to be determined.
Concept introduction: Heterogeneous equilibrium can be defined as equilibrium where the components (reactants and products) are present in different phases.
(c)
Answer to Problem 25A
The equilibrium expression is
Explanation of Solution
Equilibrium expressions used to determine the changes in concentration that happens as the reaction approaches equilibrium. Aqueous solutions and gases change their concentrations considerably during the course of reaction. On the other hand, pure liquids and solids do not change their concentration much as reaction moves towards equilibrium since they are present in large excess.
Hence pure liquids and solids are not included in equilibrium expression equation.
The reaction is:
The equilibrium expression is
Chapter 17 Solutions
World of Chemistry
- 6. Consider the following exothermic reaction below. 2Cu2+(aq) +41 (aq)2Cul(s) + 12(aq) a. If Cul is added, there will be a shift left/shift right/no shift (circle one). b. If Cu2+ is added, there will be a shift left/shift right/no shift (circle one). c. If a solution of AgNO3 is added, there will be a shift left/shift right/no shift (circle one). d. If the solvent hexane (C6H14) is added, there will be a shift left/shift right/no shift (circle one). Hint: one of the reaction species is more soluble in hexane than in water. e. If the reaction is cooled, there will be a shift left/shift right/no shift (circle one). f. Which of the changes above will change the equilibrium constant, K?arrow_forwardShow work. don't give Aiarrow_forwardShow work with explanation needed. don't give Ai generated solutionarrow_forward
- Show work with explanation needed. Don't give Ai generated solutionarrow_forward7. Calculate the following for a 1.50 M Ca(OH)2 solution. a. The concentration of hydroxide, [OH-] b. The concentration of hydronium, [H3O+] c. The pOH d. The pHarrow_forwardA first order reaction is 46.0% complete at the end of 59.0 minutes. What is the value of k? What is the half-life for this reaction? HOW DO WE GET THERE? The integrated rate law will be used to determine the value of k. In [A] [A]。 = = -kt What is the value of [A] [A]。 when the reaction is 46.0% complete?arrow_forward
- 3. Provide the missing compounds or reagents. 1. H,NNH КОН 4 EN MN. 1. HBUCK = 8 хно Panely prowseful kanti-chuprccant fad, winddively, can lead to the crading of deduc din-willed, tica, The that chemooices in redimi Грин. " like (for alongan Ridovi MN نيا . 2. Cl -BuO 1. NUH 2.A A -BuOK THE CF,00,H Ex 5)arrow_forward2. Write a complete mechanism for the reaction shown below. NaOCH LOCH₁ O₂N NO2 CH₂OH, 20 °C O₂N NO2arrow_forward4. Propose a synthesis of the target molecules from the respective starting materials. a) b) LUCH C Br OHarrow_forward
- The following mechanism for the gas phase reaction of H2 and ICI that is consistent with the observed rate law is: step 1 step 2 slow: H2(g) +ICI(g) → HCl(g) + HI(g) fast: ICI(g) + HI(g) → HCl(g) + |2(g) (1) What is the equation for the overall reaction? Use the smallest integer coefficients possible. If a box is not needed, leave it blank. + → + (2) Which species acts as a catalyst? Enter formula. If none, leave box blank: (3) Which species acts as a reaction intermediate? Enter formula. If none, leave box blank: (4) Complete the rate law for the overall reaction that is consistent with this mechanism. (Use the form k[A][B]"..., where '1' is understood (so don't write it) for m, n etc.) Rate =arrow_forwardPlease correct answer and don't use hand rating and don't use Ai solutionarrow_forward1. For each of the following statements, indicate whether they are true of false. ⚫ the terms primary, secondary and tertiary have different meanings when applied to amines than they do when applied to alcohols. • a tertiary amine is one that is bonded to a tertiary carbon atom (one with three C atoms bonded to it). • simple five-membered heteroaromatic compounds (e.g. pyrrole) are typically more electron rich than benzene. ⚫ simple six-membered heteroaromatic compounds (e.g. pyridine) are typically more electron rich than benzene. • pyrrole is very weakly basic because protonation anywhere on the ring disrupts the aromaticity. • thiophene is more reactive than benzene toward electrophilic aromatic substitution. • pyridine is more reactive than nitrobenzene toward electrophilic aromatic substitution. • the lone pair on the nitrogen atom of pyridine is part of the pi system.arrow_forward
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