Chapter 17, Problem 59A

Interpretation Introduction

Interpretation:

The concentration of Cl₂under the given conditionshave to be calculated.

Concept Introduction:

Chemical equilibrium: Chemical equilibrium is a state of a chemical reaction when the rate of forward reaction is equal to the rate of backward reaction. The chemical reaction follows the law of mass action. The law of mass action states that the rate of a chemical reaction is directly proportional to the product of active masses of the reactants.

Answer to Problem 59A

The concentration of Cl₂under the given conditions is 9.0 × 10-3.

Explanation of Solution

Data given: K_eq = 4.5× 10-3

  $\begin{array}{l}PC{l}_5(g)\rightleftharpoons PC{l}_3(g)+C{l}_2(g)\\ K_{eq}=\frac{[PC{l}_3][C{l}_2]}{[PC{l}_5]}\\ Giventhat,[PC{l}_5]=2[PC{l}_3]\\ K_{eq}=\frac{[PC{l}_3][C{l}_2]}{2[PC{l}_3]}=\frac{[C{l}_2]}{2}\\ [C{l}_2]=K_{eq}\times 2\\ =4.5\times 10^{-3}\times 2=9.0\times 10^{-3}\end{array}$