(a) Interpretation: The position of protons bonded to the s p 2 hybridized carbons (absorbs in the 1 H NMR spectrum) in the 1 H NMR spectrum of given compound is to be estimated. Concept introduction: The protons present on s p 2 hybridized carbons in aromatic hydrocarbon are highly deshielded and show absorption at 6.5 − 8 ppm . The protons present in non aromatic hydrocarbon are highly shielded and show absorption at 4.5 − 6 ppm .

Question

2. Name the following hydrocarbons. (9 marks) a) HHHHHHHH H-C-C- H-O-S b) HCEC-CH3 H H H H H d) c) H C=C- H H H e) CH3 CH3 CH2CH=CH-CH=CHCH3 HHHH H-C-C-C-C-H H HH H f) large CH2CH3 pola H3C section lovels tower, able ocart firs g) Tower H3C-CH2 then in H3C-CH-CH-CH3 enblbano bne noitsidab Copyright © 2008. Durham Continuing Education CH3

Answer 1

Question

Chapter 17, Problem 17.9P

Interpretation Introduction

(a)

Interpretation: The position of protons bonded to the sp2 hybridized carbons (absorbs in the 1H NMR spectrum) in the 1H NMR spectrum of given compound is to be estimated.

Concept introduction: The protons present on sp2 hybridized carbons in aromatic hydrocarbon are highly deshielded and show absorption at 6.5−8 ppm. The protons present in non aromatic hydrocarbon are highly shielded and show absorption at 4.5−6 ppm.

Interpretation Introduction

(b)

Interpretation: The position of protons bonded to the sp2 hybridized carbons (absorbs in the 1H NMR spectrum) in the 1H NMR spectrum of given compound is to be estimated.

Concept introduction: The protons present on sp2 hybridized carbons in aromatic hydrocarbon are highly deshielded and show absorption at 6.5−8 ppm. The protons present in non aromatic hydrocarbon are highly shielded and show absorption at 4.5−6 ppm.

Interpretation Introduction

(c)

Interpretation: The position of protons bonded to the sp2 hybridized carbons (absorbs in the 1H NMR spectrum) of given compound are to be estimated.

Concept introduction: The protons present on sp2 hybridized carbons in aromatic hydrocarbon are highly deshielded and show absorption at 6.5−8 ppm. The protons present in non aromatic hydrocarbon are highly shielded and show absorption at 4.5−6 ppm.

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2. Name the following hydrocarbons. (9 marks) a) HHHHHHHH H-C-C- H-O-S b) HCEC-CH3 H H H H H d) c) H C=C- H H H e) CH3 CH3 CH2CH=CH-CH=CHCH3 HHHH H-C-C-C-C-H H HH H f) large CH2CH3 pola H3C section lovels tower, able ocart firs g) Tower H3C-CH2 then in H3C-CH-CH-CH3 enblbano bne noitsidab Copyright © 2008. Durham Continuing Education CH3

Name the molecules & Identify any chiral center CH3CH2CH2CHCH₂CH₂CH₂CH₂ OH CH₂CHCH2CH3 Br CH3 CH3CHCH2CHCH2CH3 CH3

Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electrons-pushing arrows for the following reaction or mechanistic step(s).

Answer 2

Question

Chapter 17, Problem 17.9P

Interpretation Introduction

(a)

Interpretation: The position of protons bonded to the sp2 hybridized carbons (absorbs in the 1H NMR spectrum) in the 1H NMR spectrum of given compound is to be estimated.

Concept introduction: The protons present on sp2 hybridized carbons in aromatic hydrocarbon are highly deshielded and show absorption at 6.5−8 ppm. The protons present in non aromatic hydrocarbon are highly shielded and show absorption at 4.5−6 ppm.

Interpretation Introduction

(b)

Interpretation: The position of protons bonded to the sp2 hybridized carbons (absorbs in the 1H NMR spectrum) in the 1H NMR spectrum of given compound is to be estimated.

Concept introduction: The protons present on sp2 hybridized carbons in aromatic hydrocarbon are highly deshielded and show absorption at 6.5−8 ppm. The protons present in non aromatic hydrocarbon are highly shielded and show absorption at 4.5−6 ppm.

Interpretation Introduction

(c)

Interpretation: The position of protons bonded to the sp2 hybridized carbons (absorbs in the 1H NMR spectrum) of given compound are to be estimated.

Concept introduction: The protons present on sp2 hybridized carbons in aromatic hydrocarbon are highly deshielded and show absorption at 6.5−8 ppm. The protons present in non aromatic hydrocarbon are highly shielded and show absorption at 4.5−6 ppm.

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Answer 3

Question

Chapter 17, Problem 17.9P

Interpretation Introduction

(a)

Interpretation: The position of protons bonded to the sp2 hybridized carbons (absorbs in the 1H NMR spectrum) in the 1H NMR spectrum of given compound is to be estimated.

Concept introduction: The protons present on sp2 hybridized carbons in aromatic hydrocarbon are highly deshielded and show absorption at 6.5−8 ppm. The protons present in non aromatic hydrocarbon are highly shielded and show absorption at 4.5−6 ppm.

Interpretation Introduction

(b)

Interpretation: The position of protons bonded to the sp2 hybridized carbons (absorbs in the 1H NMR spectrum) in the 1H NMR spectrum of given compound is to be estimated.

Concept introduction: The protons present on sp2 hybridized carbons in aromatic hydrocarbon are highly deshielded and show absorption at 6.5−8 ppm. The protons present in non aromatic hydrocarbon are highly shielded and show absorption at 4.5−6 ppm.

Interpretation Introduction

(c)

Interpretation: The position of protons bonded to the sp2 hybridized carbons (absorbs in the 1H NMR spectrum) of given compound are to be estimated.

Concept introduction: The protons present on sp2 hybridized carbons in aromatic hydrocarbon are highly deshielded and show absorption at 6.5−8 ppm. The protons present in non aromatic hydrocarbon are highly shielded and show absorption at 4.5−6 ppm.

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Answer 4

Question

Chapter 17, Problem 17.9P

Interpretation Introduction

(a)

Interpretation: The position of protons bonded to the sp2 hybridized carbons (absorbs in the 1H NMR spectrum) in the 1H NMR spectrum of given compound is to be estimated.

Concept introduction: The protons present on sp2 hybridized carbons in aromatic hydrocarbon are highly deshielded and show absorption at 6.5−8 ppm. The protons present in non aromatic hydrocarbon are highly shielded and show absorption at 4.5−6 ppm.

Interpretation Introduction

(b)

Interpretation: The position of protons bonded to the sp2 hybridized carbons (absorbs in the 1H NMR spectrum) in the 1H NMR spectrum of given compound is to be estimated.

Concept introduction: The protons present on sp2 hybridized carbons in aromatic hydrocarbon are highly deshielded and show absorption at 6.5−8 ppm. The protons present in non aromatic hydrocarbon are highly shielded and show absorption at 4.5−6 ppm.

Interpretation Introduction

(c)

Interpretation: The position of protons bonded to the sp2 hybridized carbons (absorbs in the 1H NMR spectrum) of given compound are to be estimated.

Concept introduction: The protons present on sp2 hybridized carbons in aromatic hydrocarbon are highly deshielded and show absorption at 6.5−8 ppm. The protons present in non aromatic hydrocarbon are highly shielded and show absorption at 4.5−6 ppm.

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Answer 5

Chapter 17, Problem 17.9P

Interpretation Introduction

(a)

Interpretation: The position of protons bonded to the sp2 hybridized carbons (absorbs in the 1H NMR spectrum) in the 1H NMR spectrum of given compound is to be estimated.

Concept introduction: The protons present on sp2 hybridized carbons in aromatic hydrocarbon are highly deshielded and show absorption at 6.5−8 ppm. The protons present in non aromatic hydrocarbon are highly shielded and show absorption at 4.5−6 ppm.

Interpretation Introduction

(b)

Interpretation: The position of protons bonded to the sp2 hybridized carbons (absorbs in the 1H NMR spectrum) in the 1H NMR spectrum of given compound is to be estimated.

Concept introduction: The protons present on sp2 hybridized carbons in aromatic hydrocarbon are highly deshielded and show absorption at 6.5−8 ppm. The protons present in non aromatic hydrocarbon are highly shielded and show absorption at 4.5−6 ppm.

Interpretation Introduction

(c)

Interpretation: The position of protons bonded to the sp2 hybridized carbons (absorbs in the 1H NMR spectrum) of given compound are to be estimated.

Concept introduction: The protons present on sp2 hybridized carbons in aromatic hydrocarbon are highly deshielded and show absorption at 6.5−8 ppm. The protons present in non aromatic hydrocarbon are highly shielded and show absorption at 4.5−6 ppm.

Answer 6

Chapter 17, Problem 17.9P

Interpretation Introduction

(a)

Interpretation: The position of protons bonded to the sp2 hybridized carbons (absorbs in the 1H NMR spectrum) in the 1H NMR spectrum of given compound is to be estimated.

Concept introduction: The protons present on sp2 hybridized carbons in aromatic hydrocarbon are highly deshielded and show absorption at 6.5−8 ppm. The protons present in non aromatic hydrocarbon are highly shielded and show absorption at 4.5−6 ppm.

Answer 7

Chapter 17, Problem 17.9P

Interpretation Introduction

(a)

Interpretation: The position of protons bonded to the sp2 hybridized carbons (absorbs in the 1H NMR spectrum) in the 1H NMR spectrum of given compound is to be estimated.

Concept introduction: The protons present on sp2 hybridized carbons in aromatic hydrocarbon are highly deshielded and show absorption at 6.5−8 ppm. The protons present in non aromatic hydrocarbon are highly shielded and show absorption at 4.5−6 ppm.

Answer 8

Interpretation Introduction

(b)

Interpretation: The position of protons bonded to the sp2 hybridized carbons (absorbs in the 1H NMR spectrum) in the 1H NMR spectrum of given compound is to be estimated.

Concept introduction: The protons present on sp2 hybridized carbons in aromatic hydrocarbon are highly deshielded and show absorption at 6.5−8 ppm. The protons present in non aromatic hydrocarbon are highly shielded and show absorption at 4.5−6 ppm.

Answer 9

Interpretation Introduction

(b)

Interpretation: The position of protons bonded to the sp2 hybridized carbons (absorbs in the 1H NMR spectrum) in the 1H NMR spectrum of given compound is to be estimated.

Concept introduction: The protons present on sp2 hybridized carbons in aromatic hydrocarbon are highly deshielded and show absorption at 6.5−8 ppm. The protons present in non aromatic hydrocarbon are highly shielded and show absorption at 4.5−6 ppm.

Answer 10

Interpretation Introduction

(c)

Interpretation: The position of protons bonded to the sp2 hybridized carbons (absorbs in the 1H NMR spectrum) of given compound are to be estimated.

Concept introduction: The protons present on sp2 hybridized carbons in aromatic hydrocarbon are highly deshielded and show absorption at 6.5−8 ppm. The protons present in non aromatic hydrocarbon are highly shielded and show absorption at 4.5−6 ppm.

Answer 11

Interpretation Introduction

(c)

Interpretation: The position of protons bonded to the sp2 hybridized carbons (absorbs in the 1H NMR spectrum) of given compound are to be estimated.

Concept introduction: The protons present on sp2 hybridized carbons in aromatic hydrocarbon are highly deshielded and show absorption at 6.5−8 ppm. The protons present in non aromatic hydrocarbon are highly shielded and show absorption at 4.5−6 ppm.

Answer 12

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Answer 23

Ch. 17 - Prob. 17.1P Ch. 17 - Problem 17.2 What orbitals are used to form the...Ch. 17 - Problem-17.3. Give the IUPAC name for each...Ch. 17 - Prob. 17.4P Ch. 17 - Problem-17.5 What is the structure of propofol,...Ch. 17 - Problem 17.6 What is the structure of a compound...Ch. 17 - Problem 17.7 How many NMR signals does each...Ch. 17 - Prob. 17.8P Ch. 17 - Prob. 17.9P Ch. 17 - Prob. 17.10P

Solution Summary: The author explains that the position of protons bonded to the sp2 hybridized carbons is to be estimated.

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