Interpretation Highly toxic disulfur decafluoride decomposes by a free radical process: S 2 F 10 (g) ⇌ SF 4 (g) + SF 6 (g) . In a study of the decomposition, S 2 F 10 was placed in a 2.0 L flask and heated to 100 o C ; [S 2 F 10 ] was 0.50 M at equilibrium. More S 2 F 10 was added, and when equilibrium was retained, the concentration of S 2 F 10 was 2.5 M. How the concentrations change of [SF 4 ] and [SF 6 ] affects the equilibrium has to be determined. Concept Introduction Law of Chemical Equilibrium The equilibrium constant is the product of molar concentrations of the product which is raised to its stoichiometric coefficients divided by the product of molar concentrations of the reactant which is raised to its stoichiometric coefficients. Equilibrium Constant Consider a reaction, aA+bB ⇔ cC+dD Forward reaction rate K f = [A] a [B] B Backward reaction rate K b = [C] c [D] d At equilibrium, the rate of forward reaction = rate of backward reaction K eq = K f K b K f K b = [C] c [D] d [A] a [B] B K eq = K f K b = [C] c [D] d [A] a [B] B K eq is the equilibrium constant.
Interpretation Highly toxic disulfur decafluoride decomposes by a free radical process: S 2 F 10 (g) ⇌ SF 4 (g) + SF 6 (g) . In a study of the decomposition, S 2 F 10 was placed in a 2.0 L flask and heated to 100 o C ; [S 2 F 10 ] was 0.50 M at equilibrium. More S 2 F 10 was added, and when equilibrium was retained, the concentration of S 2 F 10 was 2.5 M. How the concentrations change of [SF 4 ] and [SF 6 ] affects the equilibrium has to be determined. Concept Introduction Law of Chemical Equilibrium The equilibrium constant is the product of molar concentrations of the product which is raised to its stoichiometric coefficients divided by the product of molar concentrations of the reactant which is raised to its stoichiometric coefficients. Equilibrium Constant Consider a reaction, aA+bB ⇔ cC+dD Forward reaction rate K f = [A] a [B] B Backward reaction rate K b = [C] c [D] d At equilibrium, the rate of forward reaction = rate of backward reaction K eq = K f K b K f K b = [C] c [D] d [A] a [B] B K eq = K f K b = [C] c [D] d [A] a [B] B K eq is the equilibrium constant.
Highly toxic disulfur decafluoride decomposes by a free radical process: S2F10(g) ⇌ SF4(g) + SF6(g). In a study of the decomposition, S2F10 was placed in a 2.0 L flask and heated to 100oC; [S2F10] was 0.50 M at equilibrium. More S2F10 was added, and when equilibrium was retained, the concentration of S2F10 was 2.5 M. How the concentrations change of [SF4] and [SF6] affects the equilibrium has to be determined.
Concept Introduction
Law of Chemical Equilibrium
The equilibrium constant is the product of molar concentrations of the product which is raised to its stoichiometric coefficients divided by the product of molar concentrations of the reactant which is raised to its stoichiometric coefficients.
Equilibrium Constant
Consider a reaction,
aA+bB⇔cC+dD
Forward reaction rate Kf= [A]a[B]B
Backward reaction rate Kb= [C]c[D]d
At equilibrium, the rate of forward reaction = rate of backward reaction
Indicate the type of bond that is considered to be a hydrogen bond.(A). Permanent dipole-dipole interaction between polar molecules.(B). Mixed ionic-covalent bond.(C). Principal interatomic bond(D). Van del Waals forces.
Retro aldol:
NaOH
H₂O
H
NaOH
& d
H₂O
H
Draw the product of the reaction
shown below. Ignore inorganic
byproducts.
H
conc. HBr
Drawing
Q
Chapter 17 Solutions
Chemistry: The Molecular Nature of Matter and Change (Looseleaf)
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