The given reaction is N 2(g) + 3H 2(g) ⇌ 2NH 3(g) The partial pressures of each reactant and P total has to be calculated. Concept Introduction: Equilibrium constant using partial pressure: The equilibrium constant of partial pressure can be defined as the ratio of products and reactants concentration at equilibrium in terms of partial pressure. For a reaction, aA (g) + bB (g) ⇌ cC (g) + dD (g) The expression of K p can be given as K p = (P C ) c (P D ) d (P A ) a (P B ) b
The given reaction is N 2(g) + 3H 2(g) ⇌ 2NH 3(g) The partial pressures of each reactant and P total has to be calculated. Concept Introduction: Equilibrium constant using partial pressure: The equilibrium constant of partial pressure can be defined as the ratio of products and reactants concentration at equilibrium in terms of partial pressure. For a reaction, aA (g) + bB (g) ⇌ cC (g) + dD (g) The expression of K p can be given as K p = (P C ) c (P D ) d (P A ) a (P B ) b
The partial pressures of each reactant and Ptotal has to be calculated.
Concept Introduction:
Equilibrium constant using partial pressure:
The equilibrium constant of partial pressure can be defined as the ratio of products and reactants concentration at equilibrium in terms of partial pressure.
For a reaction,
aA(g)+ bB(g)⇌cC(g)+ dD(g)
The expression of Kp can be given as
Kp = (PC)c(PD)d(PA)a(PB)b
(b)
Interpretation Introduction
Interpretation:
The given reaction is
N2(g) + 3H2(g)⇌2NH3(g)
The partial pressure of each reactant and Ptotal under the given conditions assuming that partial pressure of NH3 is 50 atm has to be calculated. The suggestion is valid or not has to be given.
Concept Introduction:
Equilibrium constant using partial pressure:
The equilibrium constant of partial pressure can be defined as the ratio of products and reactants concentration at equilibrium in terms of partial pressure.
Draw the product of the reaction
shown below. Ignore inorganic
byproducts.
H
conc. HBr
Drawing
Q
Calculate the atomic packing factor of diamond knowing that the number of Si atoms per cm3 is 2.66·1022 and that the atomic radii of silicon and oxygen are, respectively, 0.038 and 0.117 nm.
Chapter 17 Solutions
Chemistry: The Molecular Nature of Matter and Change (Looseleaf)
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