Organic Chemistry Study Guide and Solutions
6th Edition
ISBN: 9781936221868
Author: Marc Loudon, Jim Parise
Publisher: W. H. Freeman
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Chapter 17, Problem 17.5P
Interpretation Introduction
Interpretation:
The reason as to why trityl chloride is much more reactive than the other
Concept introduction:
The nucleophilic substitution reactions are the reactions in which one nucleophile is substituted by another nucleophile. These reactions depend upon the nucleophilicity and concentration of the incoming nucleophile. The
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Don't used hand raiting
The following 'H NMR spectrum was taken with a 750 MHz spectrometer:
1.0
0.5
0.0
10.0
9.0
8.0
7.0
6.0
5.0
4.0
3.0 ' 2.0
1.0
0.0
(ppm)
What is the difference Av
in the frequency of RF
ac
Δν
ac
radiation absorbed by the a and c protons? (Note:
it's not equal to the difference in chemical shifts.)
Round your answer to 2 significant digits, and be
sure it has an appropriate unit symbol.
=
O
O a will shift left, c will shift right.
O a will shift right, c will shift left.
a and c will both shift left, with more space
between them.
Suppose a new spectrum is taken with a 500 MHz
spectrometer. What will be true about this new
spectrum?
O
a and c will both shift left, with less space
between them.
O
a and c will both shift right, with more space
between them.
O
a and c will both shift right, with less space
between them.
Which protons have the largest energy gap
between spin up and spin down states?
O None of the above.
○ a
Ob
Explanation
Check
C
Ar
B
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What mass of Na2CO3 must you add to 125g of water to prepare 0.200 m Na2CO3? Calculate mole fraction of Na2CO3, mass percent, and molarity of the resulting solution. MM (g/mol): Na2CO3 105.99; water 18.02. Final solution density is 1.04 g/mL.
Chapter 17 Solutions
Organic Chemistry Study Guide and Solutions
Ch. 17 - Prob. 17.1PCh. 17 - Prob. 17.2PCh. 17 - Prob. 17.3PCh. 17 - Prob. 17.4PCh. 17 - Prob. 17.5PCh. 17 - Prob. 17.6PCh. 17 - Prob. 17.7PCh. 17 - Prob. 17.8PCh. 17 - Prob. 17.9PCh. 17 - Prob. 17.10P
Ch. 17 - Prob. 17.11PCh. 17 - Prob. 17.12PCh. 17 - Prob. 17.13PCh. 17 - Prob. 17.14PCh. 17 - Prob. 17.15PCh. 17 - Prob. 17.16PCh. 17 - Prob. 17.17PCh. 17 - Prob. 17.18PCh. 17 - Prob. 17.19PCh. 17 - Prob. 17.20PCh. 17 - Prob. 17.21PCh. 17 - Prob. 17.22APCh. 17 - Prob. 17.23APCh. 17 - Prob. 17.24APCh. 17 - Prob. 17.25APCh. 17 - Prob. 17.26APCh. 17 - Prob. 17.27APCh. 17 - Prob. 17.28APCh. 17 - Prob. 17.29APCh. 17 - Prob. 17.30APCh. 17 - Prob. 17.31APCh. 17 - Prob. 17.32APCh. 17 - Prob. 17.33APCh. 17 - Prob. 17.35APCh. 17 - Prob. 17.36APCh. 17 - Prob. 17.37APCh. 17 - Prob. 17.38APCh. 17 - Prob. 17.39APCh. 17 - Prob. 17.40APCh. 17 - Prob. 17.41APCh. 17 - Prob. 17.42APCh. 17 - Prob. 17.43APCh. 17 - Prob. 17.44APCh. 17 - Prob. 17.45APCh. 17 - Prob. 17.46APCh. 17 - Prob. 17.47APCh. 17 - Prob. 17.48APCh. 17 - Prob. 17.49APCh. 17 - Prob. 17.50APCh. 17 - Prob. 17.51APCh. 17 - Prob. 17.52APCh. 17 - Prob. 17.53APCh. 17 - Prob. 17.54APCh. 17 - Prob. 17.55APCh. 17 - Prob. 17.56APCh. 17 - Prob. 17.57APCh. 17 - Prob. 17.58APCh. 17 - Prob. 17.59AP
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