Student Solutions Manual for Bettelheim/Brown/Campbell/Farrell/Torres' Introduction to General, Organic and Biochemistry, 11th
Student Solutions Manual for Bettelheim/Brown/Campbell/Farrell/Torres' Introduction to General, Organic and Biochemistry, 11th
11th Edition
ISBN: 9781305081055
Author: Bettelheim, Frederick A.
Publisher: Cengage Learning
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Chapter 17, Problem 17.46P
Interpretation Introduction

Interpretation:

To identify the functional groups in Warfarin.

Concept Introduction:

A group of atoms which are responsible for the chemical reactions of a various compounds is known as functional groups.

A stereo centre is the centre where all the 4 groups attached to a carbon are different.

A keto group stays in the equilibrium with its enol (−OH) form by resonance.

NaBH4 is a reducing agent it reduces ketone or aldehyde to an alcohol.

Interpretation Introduction

Interpretation:

To draw the stereorepresentation of the r enantiomer as s enantiomer is more active than r enantiomer.

Concept Introduction:

A stereo centre is the centre where all the 4 groups attached to a carbon are different.

A keto group stays in the equilibrium with its enol (−OH) form by resonance.

NaBH4 is a reducing agent it reduces ketone or aldehyde to an alcohol.

Interpretation Introduction

Interpretation:

To draw the structural formula of keto form of Warfarin.

Concept Introduction:

A stereo centre is the centre where all the 4 groups attached to a carbon are different.

A keto group stays in the equilibrium with its enol (−OH) form by resonance.

NaBH4 is a reducing agent it reduces ketone or aldehyde to an alcohol.

Interpretation Introduction

Interpretation:

To draw the product formed by treating warfarin with NaBH4..

Concept Introduction:

A stereo centre is the centre where all the 4 groups attached to a carbon are different.

A keto group stays in the equilibrium with its enol (−OH) form by resonance.

NaBH4 is a reducing agent it reduces ketone or aldehyde to an alcohol.

Interpretation Introduction

Interpretation:

The number of molecules of warfarin present in 4 mg tablet should be determined.

Concept Introduction:

A stereo centre is the centre where all the 4 groups attached to a carbon are different.

A keto group stays in the equilibrium with its enol (−OH) form by resonance.

NaBH4 is a reducing agent it reduces ketone or aldehyde to an alcohol.

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Chapter 17 Solutions

Student Solutions Manual for Bettelheim/Brown/Campbell/Farrell/Torres' Introduction to General, Organic and Biochemistry, 11th

Ch. 17 - 17-11 What is the difference in structure between...Ch. 17 - 17-12 Is it possible for the carbon atom of a...Ch. 17 - 17-13 Which compounds contain carbonyl groups?Ch. 17 - 17-14 Following are structural formulas for two...Ch. 17 - 17-15 Draw structural formulas for the four...Ch. 17 - Prob. 17.16PCh. 17 - Prob. 17.17PCh. 17 - 17-18 Draw structural formulas for these ketones....Ch. 17 - 17-19 Write the JUPAC names for these compounds.Ch. 17 - Prob. 17.20PCh. 17 - 17-2 1 Explain why each name is incorrect. Write...Ch. 17 - Prob. 17.22PCh. 17 - Prob. 17.23PCh. 17 - 17-24 In each pair of compounds, select the one...Ch. 17 - Prob. 17.25PCh. 17 - 17-26 Account for the fact that acetone has a...Ch. 17 - 17-27 Pentane, 1-butanol, and butanal all have...Ch. 17 - 17-28 Show how acetaldehyde can form hydrogen...Ch. 17 - 17-29 Why can’t two molecules of acetone form a...Ch. 17 - 17-30 Answer true or false. (a) The reduction of...Ch. 17 - 17-3 1 Draw a structural formula for the principal...Ch. 17 - Prob. 17.32PCh. 17 - 17-33 What simple chemical test could you use to...Ch. 17 - 17-34 Explain why liquid aldehydes are often...Ch. 17 - 17-35 Suppose that you take a bottle of...Ch. 17 - 17-36 Explain why the reduction of an aldehyde...Ch. 17 - Prob. 17.37PCh. 17 - Prob. 17.38PCh. 17 - Prob. 17.39PCh. 17 - Prob. 17.40PCh. 17 - Prob. 17.41PCh. 17 - Prob. 17.42PCh. 17 - Prob. 17.43PCh. 17 - Prob. 17.44PCh. 17 - Prob. 17.45PCh. 17 - Prob. 17.46PCh. 17 - 17-47 What is the characteristic structural...Ch. 17 - Prob. 17.48PCh. 17 - Prob. 17.49PCh. 17 - Prob. 17.50PCh. 17 - Prob. 17.51PCh. 17 - Prob. 17.52PCh. 17 - Prob. 17.53PCh. 17 - 17-54 Following is the structure of...Ch. 17 - Prob. 17.55PCh. 17 - Prob. 17.56PCh. 17 - Prob. 17.57PCh. 17 - Prob. 17.58PCh. 17 - Prob. 17.59PCh. 17 - 17-60 1-Propanol can be prepared by the reduction...Ch. 17 - Prob. 17.61PCh. 17 - 17-62 Show how to bring about these conversions....Ch. 17 - Prob. 17.63PCh. 17 - Prob. 17.64PCh. 17 - Prob. 17.65PCh. 17 - Prob. 17.66PCh. 17 - 17-67 Draw structural formulas for these...Ch. 17 - Prob. 17.68PCh. 17 - 17-69 Propanal (bp 49°C) and 1-propanol (bp 97°C)...Ch. 17 - 17-70 What simple chemical test could you use to...Ch. 17 - Prob. 17.71PCh. 17 - 17-72 The following molecule is an enediol; each...Ch. 17 - 17-73 Alcohols can be prepared by the...Ch. 17 - 17-74 Glucose, C6H12O6, contains an aldehyde group...Ch. 17 - Prob. 17.75PCh. 17 - Prob. 17.76PCh. 17 - Prob. 17.77PCh. 17 - 17-78 Complete the following equation for these...Ch. 17 - 17-79 Write an equation for each conversion. (a)...
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